Problem 29
Question
Is \(\mathbb{R}^{3}\) a complex vector space? Explain.
Step-by-Step Solution
Verified Answer
No, \(\mathbb{R}^3\) is not a complex vector space. It fails to satisfy the closure property under complex scalar multiplication, as the result of complex scalar multiplication creates a vector in \(\mathbb{C}^3\) instead of \(\mathbb{R}^3\).
1Step 1: Define complex scalar multiplication
Let's define complex scalar multiplication for a complex vector space. Given a scalar \(c \in \mathbb{C}\) and a vector \(v \in V\), where \(V\) is a complex vector space, the product \(cv\) must also be in \(V\).
2Step 2: Apply complex scalar multiplication to \(\mathbb{R}^3\)
Let \(c = a+bi \in \mathbb{C}\) be any complex scalar, and let \(v = \begin{pmatrix} x \\ y \\ z \end{pmatrix} \in \mathbb{R}^3\) be any real-valued 3-dimensional vector. Apply the complex scalar multiplication to \(v\):
\(c \cdot v = (a + bi) \begin{pmatrix} x \\ y \\ z \end{pmatrix} = \begin{pmatrix} ax - by \\ ay + bx \\ az + bz \end{pmatrix} + \begin{pmatrix} bx \\ by \\ bz \end{pmatrix} i\)
3Step 3: Determine if the result is in \(\mathbb{R}^3\)
Now, we need to determine if the result of the complex scalar multiplication is in \(\mathbb{R}^3\). In this case, the result is:
\(\begin{pmatrix} ax - by \\ ay + bx \\ az + bz \end{pmatrix} + \begin{pmatrix} bx \\ by \\ bz \end{pmatrix} i\)
The first part is real-valued, but the second part has imaginary components. Therefore, the result is not in \(\mathbb{R}^3\), since the imaginary components create a vector in \(\mathbb{C}^3\).
4Step 4: Conclusion
As the result of complex scalar multiplication is not in \(\mathbb{R}^3\), we conclude that \(\mathbb{R}^3\) is not a complex vector space.
Key Concepts
Scalar MultiplicationReal Vector SpacesComplex Numbers
Scalar Multiplication
Scalar multiplication in the context of vector spaces involves multiplying a vector by a scalar, which is a single number, modifying the vector's magnitude and direction. In real vector spaces, this scalar is usually a real number. However, in complex vector spaces, the scalar could be a complex number, represented as \(a + bi\), where \(a\) and \(b\) are real numbers and \(i\) is the imaginary unit.
When we apply scalar multiplication to vectors, particularly in complex vector spaces, we must ensure that the operation results in a vector that still belongs to the original space. If we take an array \(v = \begin{pmatrix} x \ y \ z \end{pmatrix}\) from \(\mathbb{R}^3\), and multiply it by a complex scalar \(c = a + bi\), the resulting vector is \((a+bi) \cdot v\). This operation introduces imaginary components, which means the new vector exists in \(\mathbb{C}^3\) and not in \(\mathbb{R}^3\).
This illustrates a key difference between real and complex vector spaces when performing scalar multiplication.
When we apply scalar multiplication to vectors, particularly in complex vector spaces, we must ensure that the operation results in a vector that still belongs to the original space. If we take an array \(v = \begin{pmatrix} x \ y \ z \end{pmatrix}\) from \(\mathbb{R}^3\), and multiply it by a complex scalar \(c = a + bi\), the resulting vector is \((a+bi) \cdot v\). This operation introduces imaginary components, which means the new vector exists in \(\mathbb{C}^3\) and not in \(\mathbb{R}^3\).
This illustrates a key difference between real and complex vector spaces when performing scalar multiplication.
Real Vector Spaces
Real vector spaces, like \(\mathbb{R}^3\), consist of all possible vectors formed by real numbers. A vector space must satisfy certain properties, such as closure under addition and scalar multiplication, existence of a zero vector, and more.
For \(\mathbb{R}^3\), the space is three-dimensional, where each vector can be described by three real numbers \(x, y,\) and \(z\). When we multiply a vector in a real vector space by a real scalar, the resulting vector remains within that space — \(\mathbb{R}^3\). Such operations don't involve complex components; hence, the space only consists of real-valued vectors.
The introduction of complex numbers in scalar multiplication disrupts this premise. Since complex numbers can have imaginary components, the scalar multiplication with complex numbers moves vectors out of the real space into the complex space, which is why \(\mathbb{R}^3\) isn't a complex vector space.
For \(\mathbb{R}^3\), the space is three-dimensional, where each vector can be described by three real numbers \(x, y,\) and \(z\). When we multiply a vector in a real vector space by a real scalar, the resulting vector remains within that space — \(\mathbb{R}^3\). Such operations don't involve complex components; hence, the space only consists of real-valued vectors.
The introduction of complex numbers in scalar multiplication disrupts this premise. Since complex numbers can have imaginary components, the scalar multiplication with complex numbers moves vectors out of the real space into the complex space, which is why \(\mathbb{R}^3\) isn't a complex vector space.
Complex Numbers
Complex numbers extend the real number system by introducing an imaginary component. A complex number is formulated as \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part multiplied by the imaginary unit \(i\), which satisfies \(i^2 = -1\).
The arithmetic operations on complex numbers, like addition, subtraction, multiplication, and division, alter both the real and imaginary parts. For vector spaces, using complex numbers means that scalar multiplication involves altering the vector with both real and imaginary parts, potentially moving it into a more extensive space like \(\mathbb{C}^3\).
Understanding complex numbers is crucial in distinguishing real from complex vector spaces. In real vector spaces, vectors and operations are strictly related to real numbers. Introducing complex numbers changes the dimensionality and properties of the vector space, as observed with the result of complex scalar multiplication on real vectors.
The arithmetic operations on complex numbers, like addition, subtraction, multiplication, and division, alter both the real and imaginary parts. For vector spaces, using complex numbers means that scalar multiplication involves altering the vector with both real and imaginary parts, potentially moving it into a more extensive space like \(\mathbb{C}^3\).
Understanding complex numbers is crucial in distinguishing real from complex vector spaces. In real vector spaces, vectors and operations are strictly related to real numbers. Introducing complex numbers changes the dimensionality and properties of the vector space, as observed with the result of complex scalar multiplication on real vectors.
Other exercises in this chapter
Problem 28
Determine the null space of the given matrix \(A\). $$A=\left[\begin{array}{rrrr} 1 & 3 & -2 & 1 \\ 3 & 10 & -4 & 6 \\ 2 & 5 & -6 & -1 \end{array}\right]$$
View solution Problem 29
determine a linearly independent set of vectors that spans the same subspace of \(V\) as that spanned by the original set of vectors. $$\begin{aligned} V=M_{2}(
View solution Problem 29
Determine the null space of the given matrix \(A\). $$A=\left[\begin{array}{rrr} 1 & i & -2 \\ 3 & 4 i & -5 \\ -1 & -3 i & i \end{array}\right]$$
View solution Problem 30
Decide (with justification) whether or not the given set \(S\) of vectors (a) spans \(V,\) and (b) is linearly independent. $$\begin{aligned} V=& M_{2 \times 3}
View solution