Problem 29
Question
Indicate which molecule of each pair has the smaller bond angles. Explain your answer. (a) \(\mathrm{BCl}_{3}\) or \(\mathrm{NCl}_{3}\) (b) \(\mathrm{OF}_{2}\) or \(\mathrm{SF}_{6}\)
Step-by-Step Solution
Verified Answer
(a) \( \mathrm{NCl}_3 \); (b) \( \mathrm{OF}_2 \).
1Step 1: Analyze Molecular Geometry of BCl3
The molecule \( \mathrm{BCl}_3 \) is a trigonal planar molecule with a bond angle of 120 degrees because it has three bonding pairs of electrons and no lone pairs around the boron atom. This geometry allows for equal repulsion between all bond pairs, resulting in larger bond angles.
2Step 2: Analyze Molecular Geometry of NCl3
The molecule \( \mathrm{NCl}_3 \) has a trigonal pyramidal shape with bond angles less than 109.5 degrees. This is due to the presence of one lone pair and three bond pairs around the nitrogen atom, which causes greater repulsion and smaller bond angles compared to \( \mathrm{BCl}_3 \).
3Step 3: Compare BCl3 and NCl3
\( \mathrm{NCl}_3 \) has smaller bond angles than \( \mathrm{BCl}_3 \) due to the effect of the lone pair on nitrogen, which compresses the bond angles in \( \mathrm{NCl}_3 \) more than the all-bonded structure of \( \mathrm{BCl}_3 \).
4Step 4: Analyze Molecular Geometry of OF2
The molecule \( \mathrm{OF}_2 \) has a bent shape similar to \( \mathrm{H}_2\, \mathrm{O} \) due to two lone pairs and two bonding pairs, resulting in bond angles around 103 degrees. The presence of lone pairs compresses the bond angle significantly.
5Step 5: Analyze Molecular Geometry of SF6
The molecule \( \mathrm{SF}_6 \) is an octahedral molecule with bond angles of 90 degrees. It has no lone pairs but six bonding pairs around the sulfur atom, creating a regular geometric bond angle between all bonds.
6Step 6: Compare OF2 and SF6
For \( \mathrm{OF}_2 \) and \( \mathrm{SF}_6 \), \( \mathrm{OF}_2 \) has smaller bond angles (about 103 degrees) compared to the 90 degrees in \( \mathrm{SF}_6 \), because the lone pairs in \( \mathrm{OF}_2 \) contribute to decreasing the bond angles more significantly than the structure of \( \mathrm{SF}_6 \).
Key Concepts
Bond AnglesTrigonal Planar MoleculesLone PairsOctahedral Molecules
Bond Angles
In chemistry, bond angles refer to the angles formed between three atoms across at least two bonds. Understanding bond angles is crucial in predicting the shape and reactivity of molecules.
These angles depend on several factors:
- The type of atoms involved
- The number of bonds
- The presence of lone pairs, which influence the spatial arrangement of atoms
Trigonal Planar Molecules
Trigonal planar molecules are a specific type of molecular geometry where three atoms are bonded to a central atom. The central atom and its bonded partners form a flat, triangular shape. An example of this is seen in boron trichloride (BCl₃).
In the trigonal planar configuration, bond angles are typically around 120 degrees. This arrangement occurs when there are three regions of electron density and no lone pairs on the central atom.
- Example: Boron trichloride (BCl₃) is a trigonal planar molecule.
- Bond Angles: Typically 120 degrees.
- Key Feature: Equal repulsive forces between bonding pairs, making it symmetric and stable.
Lone Pairs
Lone pairs refer to valence electrons that are not involved in bonding. Instead, they reside on the central atom of a molecule and can significantly influence the molecular shape and bond angles.
Lone pairs are particularly potent because their electron clouds are closer to the central atom compared to shared pairs, leading to enhanced repulsion. This repulsion can:
- Distort bond angles, making them smaller than expected.
- Influence the overall shape of the molecule, as seen with the trigonal pyramidal shape.
- Alter physical and chemical properties by affecting molecule polarity.
Octahedral Molecules
Octahedral molecules have a distinctive geometric shape with a central atom surrounded by six other atoms. The geometric shape resembles two pyramids base to base, with bond angles strictly at 90 degrees.
This configuration leads to:
- Symmetry that often results in non-polar molecules if all surrounding atoms are the same.
- Equal repulsion forces, lending stability to the structure.
- A potential for high coordination, making them common in transition metal complexes.
Other exercises in this chapter
Problem 27
Give the bonded-atom lonè-pair arrangement and the molecular shape of the following species. (a) \(\mathrm{SeO}_{2}\) (b) \(\mathrm{N}_{2} \mathrm{O}(\mathrm{N}
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In Give the bonded-atom lone-pair arrangement and the shape of the following species. (a) \(\mathrm{XeO}_{2}\) (b) \(\mathrm{I}_{3}^{-}\) (c) \(\mathrm{NO}_{2}^
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Indicate which species of each pair has the smaller bond angles. Explain your answer. (a) \(\mathrm{SO}_{4}^{2-}\) or \(\mathrm{AlBr}_{3}\) (b) \(\mathrm{CCl}_{
View solution Problem 31
Indicate which species of each pair has the smaller bond angles. Explain your answer. (a) \(\mathrm{Cl}_{2} \mathrm{NH}\) or \(\mathrm{NH}_{4}^{+}\) (b) \(\math
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