Problem 29
Question
In Exercises \(23-30,\) show that the given sequence is geometric and find the common ratio. $$\left\\{10 e^{4 n}\right\\}$$
Step-by-Step Solution
Verified Answer
Question: Determine if the given sequence \(\{10 e^{4n}\}\) is geometric, and if so, find the common ratio.
Answer: The sequence \(\{10 e^{4n}\}\) is geometric with a common ratio of \(e^4\).
1Step 1: Identify the sequence and the general term
The given sequence is \(\{10 e^{4n}\}\). The general term in the sequence is of the form \(a_n = 10 e^{4n}\) where \(n = 0, 1, 2, \dots\).
Step 2: Calculate the ratio between consecutive terms
2Step 2: Calculate the ratio between consecutive terms
To find the ratio between consecutive terms, divide a term by the previous term. We can find the ratio:
\(r = \dfrac{a_{n + 1}}{a_n} = \dfrac{10e^{4(n + 1)}}{10e^{4n}}\)
Step 3: Simplify the ratio
3Step 3: Simplify the ratio
To simplify the ratio, we can apply exponent rules:
\(r = \dfrac{10e^{4(n + 1)}}{10e^{4n}} = \dfrac{10e^{4n+4}}{10e^{4n}} = \dfrac{e^{4n}e^{4}}{e^{4n}} = e^4\)
Step 4: Conclusion
4Step 4: Conclusion
The ratio \(r\) is a constant, which means the given sequence \(\{10 e^{4n}\}\) is a geometric sequence. The common ratio for this sequence is \(r = e^4\).
Key Concepts
Common RatioExponent RulesSequence Identification
Common Ratio
In a geometric sequence, the common ratio is very important. It's the constant factor by which we multiply one term to get to the next term in the sequence.
To determine the common ratio, we divide any term by the previous term. This is precisely what was performed in the solution provided: the ratio
To determine the common ratio, we divide any term by the previous term. This is precisely what was performed in the solution provided: the ratio
- Given the sequence \[\{10 e^{4n}\}\], the terms can be written as \[10 e^{4 \cdot 0}, 10 e^{4 \cdot 1}, 10 e^{4 \cdot 2}, \dots\]
- Calculating the ratio between the terms \[\dfrac{10 e^{4(n+1)}}{10 e^{4n}}\] results in \[e^4\].
Exponent Rules
Understanding exponent rules will make simplifying expressions in a geometric sequence much easier. Here we deal with powers and how to handle them properly.
Exponent rules provide a systematic approach to manage complex expressions:
Exponent rules provide a systematic approach to manage complex expressions:
- Product Rule: When multiplying powers with the same base, add the exponents. \[a^m \cdot a^n = a^{m+n}\]
- Quotient Rule: When dividing powers with the same base, subtract the exponents. \[\dfrac{a^m}{a^n} = a^{m-n}\]
- Power of Power Rule: When raising a power to another power, multiply the exponents. \[(a^m)^n = a^{mn}\]
- Being savvy with these rules helps in reducing complex expressions quickly and correctly.
Sequence Identification
Identifying what kind of sequence you’re looking at is vital before solving any problems associated with it. Distinguishing between an arithmetic and a geometric sequence can guide your approach.
To identify a sequence neatly as geometric, ask if a constant multiplier exists between consecutive terms:
To identify a sequence neatly as geometric, ask if a constant multiplier exists between consecutive terms:
- Geometric Sequence: Multiplier remains constant. For instance: In the sequence \[\{10 e^{4n}\}\]
- The multiplier between consecutive terms is confirmed to be the common ratio \[e^4\].
- This constant multiplier is the exact identifier that tells you it is a geometric sequence.
- Look for an exponential pattern. Here, the sequence’s terms are clearly exponential expressions, fitting the geometric profile.
Other exercises in this chapter
Problem 28
The first term \(a_{1}\) and the common difference d of an arithmetic sequence are given. Find the fifth term and the formula for the nth term. $$a_{1}=-6, d=\f
View solution Problem 28
Find the first five terms of the recursively defined sequence. $$a_{1}=3 \text { and } a_{n}=n+2 a_{n-1} \text { for } n \geq 2$$
View solution Problem 29
Use the Extended Principle of Mathematical Induction (Exercise 28 ) to prove the given statement. \(2 n-4>n\) for every \(n \geq 5 .\) (Use 5 for \(q\) here.)
View solution Problem 29
Expand and (where possible) simplify the expression. $$(\sqrt{x}+1)^{6}$$
View solution