Problem 29
Question
In Exercises \(21-30,\) write each logarithm as a sum and\or difference of logarithmic expressions. Eliminate exponents and radicals and evaluate logarithms wherever possible. Assume that \(a, x, y\) \(z>0\) and \(a \neq 1\). $$\log \sqrt[3]{\frac{x y^{3}}{z^{5}}}$$
Step-by-Step Solution
Verified Answer
\(\frac{1}{3} (\log x + 3 \log y - 5 \log z)\)
1Step 1: Recognize the Form of the Logarithmic Expression
The logarithmic expression is in the form \(\log \sqrt[3]{\frac{x y^{3}}{z^{5}}}\). This represents a third root of a fraction, which is equivalent to the fraction raised to the power of \(1/3\). Therefore, the logarithmic expression can be rewritten as \(\log \left(\frac{x y^{3}}{z^{5}}\right)^{1/3}\).
2Step 2: Apply the Power Property of Logarithms
Using the power property of logarithms, which states that \(\log b^p = p \log b\), the logarithmic expression can be simplified further to \(\frac{1}{3} \log \left(\frac{x y^{3}}{z^{5}}\right)\).
3Step 3: Apply the Quotient Property of Logarithms
Now apply the quotient property of logarithms, which states that \(\log \left( \frac{a}{b} \right) = \log a - \log b\). This simplifies the expression to \(\frac{1}{3} \left( \log xy^{3} - \log z^{5} \right)\).
4Step 4: Apply the Product Property of Logarithms
Next, use the product property of logarithms, which states that \(\log ab = \log a + \log b\). This gives \(\frac{1}{3} (\log x + \log y^{3} - \log z^{5})\).
5Step 5: Apply the Power Property of Logarithms Again
Finally, you apply the power property of logarithms again to simplify \(\log y^{3}\) to \(3 \log y\) and \(\log z^{5}\) to \(5 \log z\), resulting in the simplified expression \(\frac{1}{3} (\log x + 3 \log y - 5 \log z)\).
Key Concepts
Power Property of LogarithmsQuotient Property of LogarithmsProduct Property of Logarithms
Power Property of Logarithms
The power property of logarithms is instrumental in simplifying logarithmic expressions involving powers. In essence, this property states that if you have a logarithm of a number raised to a power, you can bring the exponent in front of the logarithm for simplification. Mathematically, it is written as:
\[\log_b (a^p) = p \log_b (a)\]Here are some key points to remember:
This step reduces complexity and makes calculations easier, especially when further simplifications or evaluations are necessary.
\[\log_b (a^p) = p \log_b (a)\]Here are some key points to remember:
- The base of the logarithm remains unchanged.
- The exponent becomes a coefficient in front of the logarithm.
This step reduces complexity and makes calculations easier, especially when further simplifications or evaluations are necessary.
Quotient Property of Logarithms
The quotient property of logarithms is a super helpful tool when dealing with division inside a logarithm. It states that:
\[\log_b \left( \frac{a}{c} \right) = \log_b a - \log_b c\]This rule splits the logarithm of a quotient into the difference of two logarithms. Let's look at how it can be applied:
Imagine the expression \( \log \left( \frac{x y^3}{z^5} \right) \). By using the quotient property, this can be written as \( \log (x y^3) - \log (z^5) \).
\[\log_b \left( \frac{a}{c} \right) = \log_b a - \log_b c\]This rule splits the logarithm of a quotient into the difference of two logarithms. Let's look at how it can be applied:
Imagine the expression \( \log \left( \frac{x y^3}{z^5} \right) \). By using the quotient property, this can be written as \( \log (x y^3) - \log (z^5) \).
- The numerator becomes one logarithmic term.
- The denominator becomes another, subtracted term.
Product Property of Logarithms
The product property comes into play when you have a logarithm of a product of terms. The product property of logarithms can be articulated as follows:
\[\log_b (ab) = \log_b a + \log_b b\]This property allows the separation of multiplicative components inside the logarithm into individual sums. Applying this to our example, \( \log (x y^3) \) can be expanded to \( \log x + \log y^3 \).
\[\log_b (ab) = \log_b a + \log_b b\]This property allows the separation of multiplicative components inside the logarithm into individual sums. Applying this to our example, \( \log (x y^3) \) can be expanded to \( \log x + \log y^3 \).
- Each factor in the product has its own individual logarithm.
- These individual logarithms are then summed together.
Other exercises in this chapter
Problem 29
Solve the exponential equation. Round to three decimal places, when needed. $$9-e^{x^{2}-1}=2$$
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State cohether each function is one-to-one. $$f(x)=-3 x+2$$
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Evaluate each expression without using a calculator. $$\log _{3} \frac{1}{81}$$
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Sketch the graph of each function. $$f(x)=-2\left(\frac{1}{3}\right)^{x}$$
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