Problem 29
Question
In a theater, there are 20 seats in the first row. Each row has 3 more seats than the row ahead of it. There are 35 rows in the theater. a. Express the number of seats in the \(n\) th row of the theater in terms of \(n .\) b. Use sigma notation to represent the number of seats in the theater.
Step-by-Step Solution
Verified Answer
a. The nth row has \(3n + 17\) seats. b. Total seats: \(\sum_{n=1}^{35} (3n + 17) = 2485\).
1Step 1: Understanding the Pattern
The first row has 20 seats. Each subsequent row has 3 more seats than the previous row. If the first row has 20 seats, the second row has 23, the third row has 26, and so on, we observe an arithmetic sequence with the first term 20 and a common difference of 3.
2Step 2: Finding the nth Term of the Sequence
The nth term of an arithmetic sequence can be found using the formula for the nth term, which is given by \( a_n = a_1 + (n-1) \cdot d \). Here, \( a_1 = 20 \) and \( d = 3 \). Therefore, \( a_n = 20 + (n-1) \cdot 3 \). Simplify to get \( a_n = 3n + 17 \).
3Step 3: Expressing Seats in nth Row
From the formula \( a_n = 3n + 17 \), we express the number of seats in the nth row as \( 3n + 17 \). This is the expression for part (a).
4Step 4: Using Sigma Notation
To find the total number of seats in the theater, we need to sum the number of seats from row 1 to row 35. We use Sigma notation to represent this sum: \( \sum_{n=1}^{35} (3n + 17) \).
5Step 5: Calculating the Total Number of Seats
The sum \( \sum_{n=1}^{35} (3n + 17) \) can be expanded as \( \sum_{n=1}^{35} 3n + \sum_{n=1}^{35} 17 \). Calculate the first part as \( 3 \sum_{n=1}^{35} n \), where \( \sum_{n=1}^{35} n = \frac{35 \times 36}{2} = 630 \), so the first sum is \( 3 \times 630 = 1890 \). The second sum is \( 17 \times 35 = 595 \). The total number of seats is \( 1890 + 595 = 2485 \).
Key Concepts
Sigma NotationSum of Arithmetic SeriesFinding nth Term
Sigma Notation
Sigma notation is a concise way to represent the sum of a sequence of numbers, and it's particularly useful in arithmetic sequences. In the context of our theater seating problem, we're interested in summing up the number of seats from row 1 to row 35.
The sigma notation is expressed as \( \sum \), followed by the expression to sum and the index of summation (often denoted by \( n \)). For example, if you wanted to sum the expression \( 3n + 17 \) from \( n = 1 \) to \( n = 35 \), you'd write it as \( \sum_{n=1}^{35} (3n + 17) \). This reads as "the sum of \( 3n + 17 \) as \( n \) goes from 1 to 35."
Sigma notation can be broken down further:
The sigma notation is expressed as \( \sum \), followed by the expression to sum and the index of summation (often denoted by \( n \)). For example, if you wanted to sum the expression \( 3n + 17 \) from \( n = 1 \) to \( n = 35 \), you'd write it as \( \sum_{n=1}^{35} (3n + 17) \). This reads as "the sum of \( 3n + 17 \) as \( n \) goes from 1 to 35."
Sigma notation can be broken down further:
- \( n = 1 \) is the starting value of the index \( n \).
- \( 35 \) is the ending value.
- The expression \( 3n + 17 \) describes the pattern of seats in each row.
Sum of Arithmetic Series
The sum of arithmetic series involves adding up all the terms in an arithmetic sequence. In our problem, the sequence of seats follows an arithmetic pattern starting at 20 seats and increasing by 3 seats per row.
To find the sum: first, recognize the series starts at 20 seats and is defined by the formula for the nth term, \( a_n = 3n + 17 \), which means every term increases by 3. The formula for the sum \( S_n \) of an arithmetic series where the first term is \( a_1 \) and the last term is \( a_n \) is given by:
To find the sum: first, recognize the series starts at 20 seats and is defined by the formula for the nth term, \( a_n = 3n + 17 \), which means every term increases by 3. The formula for the sum \( S_n \) of an arithmetic series where the first term is \( a_1 \) and the last term is \( a_n \) is given by:
- \( S_n = \frac{n}{2} (a_1 + a_n) \)
- \( n \) is the number of terms.
- \( a_1 = 20 \) is the first term.
- The 35th term \( a_{35} = 3 \times 35 + 17 = 122 \).
- \( S_{35} = \frac{35}{2} (20 + 122) = \frac{35}{2} \times 142 = 2485 \).
Finding nth Term
Finding the nth term of an arithmetic sequence is crucial for understanding patterns of increase or decrease in a sequence. In our example, each row in the theater seats more people than the row in front by a constant amount of 3 seats.
The general formula for the nth term of an arithmetic sequence is \( a_n = a_1 + (n-1) \cdot d \). Here's how it applies:
So by understanding this formula, you can determine the seating for any row in this arithmetic sequence.
The general formula for the nth term of an arithmetic sequence is \( a_n = a_1 + (n-1) \cdot d \). Here's how it applies:
- \( a_1 = 20 \), representing the seats in the first row.
- \( d = 3 \), the common difference indicating how much more each row has compared to the previous one.
- \( a_n = 20 + (n-1) \cdot 3 \)
- Simplify to get \( a_n = 3n + 17 \).
So by understanding this formula, you can determine the seating for any row in this arithmetic sequence.
Other exercises in this chapter
Problem 28
What is the 9 th term of the geometric sequence \(125,25,5, \ldots ?\)
View solution Problem 28
In a theater, there are 20 seats in the first row. Each row has 3 more seats than the row ahead of it. There are 35 rows in the theater. Find the total number o
View solution Problem 29
In a geometric sequence, \(a_{1}=1\) and \(a_{5}=16 .\) Find \(a_{9}\)
View solution Problem 29
On Monday, Enid spent 45 minutes doing homework. On the remaining four days of the school week spent 15 minutes longer doing homework than she had the day befor
View solution