Problem 29
Question
If \( \sum_{n = 0}^{\infty} c_n4^n \) is convergent, can we conclude that each of the following series is convergent? (a) \( \sum_{n = 0}^{\infty} c_n ( - 2)^n \) (b) \( \sum_{n = 0}^{\infty} c_n ( - 4)^n \)
Step-by-Step Solution
Verified Answer
(a) Yes, it converges. (b) Convergence cannot be assured.
1Step 1: Understand convergence of the original series
The given series is \( \sum_{n = 0}^{\infty} c_n 4^n \). Since it's convergent, by the root test or ratio test for absolute convergence, it converges absolutely because any series of the form \( \sum_{n = 0}^{\infty} c_n x^n \) with \(|x| < R\) converges absolutely.
2Step 2: Examining Series (a)
For \( \sum_{n=0}^{\infty} c_n (-2)^n \), the common ratio relative to the original series is \( \frac{-2}{4} = -\frac{1}{2} \). Since this series does not involve terms that include \( 4^n \) directly, we cannot automatically apply the same conclusion. However, by the comparison test, if \( |c_n(-2)^n| = |c_n|2^n \) converges since \( c_n 4^n \) converges, \( (-2)^n \) has a smaller base than \( 4^n \). Hence, this series converges.
3Step 3: Examining Series (b)
For \( \sum_{n=0}^{\infty} c_n (-4)^n \), the common ratio relative to the original series is \( \frac{-4}{4} = -1 \). Notice that \((-4)^n = (-1)^n 4^n\), which means the terms are similar in magnitude to the original series but alternate in sign and are not assured to be absolutely convergent. By the alternating series test, we cannot directly conclude convergence unless \( c_n \) goes to zero suitably. Therefore, without more information about \( c_n \), the convergence of this series cannot be assured.
Key Concepts
Root TestRatio TestComparison TestAlternating Series Test
Root Test
The root test is a helpful tool in determining the convergence of infinite series. It is especially useful when looking at series with terms raised to powers involving their indices. Suppose you have a series denoted as \( \sum_{n=0}^{\infty} a_n \). To apply the root test, you calculate the n-th root of the absolute value of the n-th term: \( \lim_{n \to \infty} \sqrt[n]{|a_n|} = L \).
- If \( L < 1 \), the series converges absolutely.
- If \( L > 1 \), or if the limit is infinite, the series diverges.
- If \( L = 1 \), the test is inconclusive.
Ratio Test
The ratio test is another technique for analyzing series convergence and is very similar to the root test. It uses the ratio of successive terms to deduce behavior. Consider a series \( \sum_{n=0}^{\infty} a_n \). You calculate: \( L = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \).
- If \( L < 1 \), the series converges absolutely.
- If \( L > 1 \), the series diverges.
- If \( L = 1 \), the test is inconclusive.
Comparison Test
The comparison test is a simple but powerful method for determining the convergence of series, particularly when direct tests like the root test or ratio test fall short. The idea is to compare your series with another series that has known convergence properties.If you have series \( \sum_{n=0}^{\infty} a_n \) and \( \sum_{n=0}^{\infty} b_n \), for all \( n \):
- If \( 0 \leq a_n \leq b_n \) and \( \sum b_n \) converges, then \( \sum a_n \) converges.
- If \( 0 \leq b_n \leq a_n \) and \( \sum b_n \) diverges, then \( \sum a_n \) diverges.
Alternating Series Test
The alternating series test is pivotal when dealing with series that have terms alternating in sign, typically of the form \( (-1)^n a_n \). For the series \( \sum_{n=0}^{\infty} (-1)^n a_n \), the criteria for convergence are:
- The absolute value of the sequential term, \( a_n \), must be positive.
- \( a_n \) is a decreasing sequence, i.e., \( a_{n+1} \leq a_n \) for all \( n \) sufficiently large.
- \( a_n \) approaches zero as \( n \to \infty \).
Other exercises in this chapter
Problem 29
Use the Alternating Series Estimation Theorem or Taylor's Inequality to estimate the range of values of \( x \) for which the given approximation is accurate to
View solution Problem 29
Use a power series to approximate the definite integral to six decimal places. \( \int^{0.3}_0 \frac {x}{1 + x^3} dx \)
View solution Problem 29
Test the series for convergence or divergence. \( \displaystyle \sum_{n = 1}^{\infty} \frac {( - 1)^n }{\cosh n} \)
View solution Problem 29
Use the Root Test to determine whether the series is convergent or divergent. \( \displaystyle \sum_{n = 1}^{\infty} \left ( 1 + \frac {1}{n} \right)^{n2} \)
View solution