Problem 29
Question
Graph each piecewise-defined function. $$ f(x)=\left\\{\begin{array}{lll} 4 x+5 & \text { if } & x \leq 0 \\ \frac{1}{4} x+2 & \text { if } & x>0 \end{array}\right. $$
Step-by-Step Solution
Verified Answer
Graph consists of two lines that meet at \((0,5)\) for \(x\leq0\) and start from \((0,2)\) for \(x>0\).
1Step 1: Identify the function pieces
The given function is a piecewise function with two parts. For \( x \leq 0 \), the function is \( 4x + 5 \). For \( x > 0 \), the function is \( \frac{1}{4}x + 2 \). Each part covers a different domain of the input variable \( x \).
2Step 2: Graph the first piece \( 4x + 5 \) for \( x \leq 0 \)
Start by identifying a few key points for the line \( 4x + 5 \). At \( x = 0 \), \( f(x) = 5 \). At \( x = -1 \), \( f(-1) = 4(-1) + 5 = 1 \). Plot these points and draw a solid line for all \( x \leq 0 \). Use a solid dot at \( (0,5) \) since \( x = 0 \) is included.
3Step 3: Graph the second piece \( \frac{1}{4}x + 2 \) for \( x > 0 \)
Identify a few key points for the line \( \frac{1}{4}x + 2 \). At \( x = 1 \), \( f(1) = \frac{1}{4}(1) + 2 = 2.25 \). At \( x = 2 \), \( f(2) = \frac{1}{4}(2) + 2 = 2.5 \). Plot these points and draw a dashed line for all \( x > 0 \). Use an open circle at \( (0,2) \) because \( x = 0 \) is not included for this piece.
4Step 4: Combine the graphs
Overlay the two graphs onto the same coordinate plane. The first part of the function covers the left side (\( x \leq 0 \)), and the second part covers the right side (\( x > 0 \)). Ensure transitions at \( x = 0 \) are consistent with part-specific domain constraints (solid for first part, open for second).
Key Concepts
Graphing FunctionsFunction DomainsLinear Functions
Graphing Functions
Graphing functions is like drawing a picture of a function on a piece of graph paper. You plot points calculated from the function's formula and connect them to see the shape they make. In piecewise functions, like the one given in our exercise, you have different formulas for different parts of the domain. Each formula gives you a part of the complete graph.
When graphing piecewise functions, it is important to pay attention to the domains of each piece. For example, in the solution provided, the piece for \(4x + 5\) is graphed using a solid line for all \(x \leq 0\). The line continues indefinitely to the left. On the other hand, the second piece \(\frac{1}{4}x + 2\) is graphed as a dashed line starting right at \(x > 0\), because this part only applies to positive \(x\) values.
Always remember:
When graphing piecewise functions, it is important to pay attention to the domains of each piece. For example, in the solution provided, the piece for \(4x + 5\) is graphed using a solid line for all \(x \leq 0\). The line continues indefinitely to the left. On the other hand, the second piece \(\frac{1}{4}x + 2\) is graphed as a dashed line starting right at \(x > 0\), because this part only applies to positive \(x\) values.
Always remember:
- Plot points using your equations.
- Draw solid lines where the function is continuously defined.
- Use dashed lines or open circles where the function doesn't include boundary points.
Function Domains
In mathematics, a domain is the set of all possible input values (often \(x\)-values) for which a function is defined. Domains help dictate which parts of a graph you can draw using a particular function rule. When working with piecewise functions, each piece has its own distinct domain.
In our exercise, there are two pieces with different domains:
Understanding domains is crucial because it helps you know where to draw each portion of the graph and what kinds of dots or lines to use at domain boundaries (solid or open circles). This ensures you accurately portray the function's behavior within the specified intervals.
In our exercise, there are two pieces with different domains:
- The domain for \(4x + 5\) is \(x \leq 0\).
- The domain for \(\frac{1}{4}x + 2\) is \(x > 0\).
Understanding domains is crucial because it helps you know where to draw each portion of the graph and what kinds of dots or lines to use at domain boundaries (solid or open circles). This ensures you accurately portray the function's behavior within the specified intervals.
Linear Functions
Linear functions are functions that create a straight line on a graph. They are expressed in the general form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. The slope \(m\) tells you how steep the line is, and the y-intercept \(b\) tells you where the line crosses the y-axis.
Let's look at each piece of the piecewise function from our exercise:
Let's look at each piece of the piecewise function from our exercise:
- The first piece \(4x + 5\) has a slope of 4 and a y-intercept of 5. This tells you that for every step you move right on the \(x\)-axis, the function value increases by 4.
- The second piece \(\frac{1}{4}x + 2\) has a much smaller slope of \(\frac{1}{4}\). It increases much more slowly, and starts crossing the y-axis at 2.
Other exercises in this chapter
Problem 29
Sketch the graph of each function. $$ h(x)=-|x+2|+3 $$
View solution Problem 29
Write an equation of each line. Write the equation in the form \(x=a, y=b\), or \(y=m x+b\). See Examples 5 and \(6 .\) Through (1,4)\(;\) parallel to \(y=7\)
View solution Problem 30
If \(f(x)=\frac{x+8}{2 x-1}\) and \(g(x)=\frac{x-2}{x-5},\) find each function value. Find the domain of \(f(x)\).
View solution Problem 30
Sketch the graph of each function. $$ g(x)=-|x+1|+1 $$
View solution