Problem 29
Question
For the following exercises, use the given information to find the unknown value. \(y\) varies inversely with \(x\). When \(x=3\), then \(y=2\). Find \(y\) when \(x=1\).
Step-by-Step Solution
Verified Answer
When \( x = 1 \), \( y = 6 \).
1Step 1: Understand Inverse Variation
When a variable "varies inversely" with another variable, it means that their product remains constant. Therefore, if \( y \) varies inversely with \( x \), then they can be expressed as \( y \times x = k \), where \( k \) is a constant.
2Step 2: Determine the Constant
Use the given values \( x = 3 \) and \( y = 2 \) to find the constant \( k \). Substitute these values into the equation \( y \times x = k \). This gives us \( 2 \times 3 = k \), so \( k = 6 \).
3Step 3: Solve for the Unknown Value
Now that we know \( k = 6 \), use it to find \( y \) when \( x = 1 \). Using the equation \( y \times x = k \), substitute \( x = 1 \) and \( k = 6 \). This gives us \( y \times 1 = 6 \), therefore \( y = 6 \).
Key Concepts
Constant of VariationSolving EquationsDirect and Inverse Relationships
Constant of Variation
In inverse variation, the constant of variation plays a crucial role. This constant is commonly denoted as \( k \). When a problem states that one variable varies inversely with another, it means the product of those variables equals a constant.
In mathematical terms, if \( y \) varies inversely with \( x \), the equation \( y \times x = k \) comes into play. Here, \( k \) is a constant number that doesn't change even if \( x \) and \( y \) do.
In mathematical terms, if \( y \) varies inversely with \( x \), the equation \( y \times x = k \) comes into play. Here, \( k \) is a constant number that doesn't change even if \( x \) and \( y \) do.
- Think of \( k \) as the glue holding \( x \) and \( y \) together in a fixed relationship.
- The constant of variation helps us adjust one variable when the other changes.
Solving Equations
Solving equations, especially in inverse variation, involves understanding the relationship between the variables. Once we know our equation (\( y \times x = k \)), tracing the unknown value becomes straightforward.
When given initial values of \( x \) and \( y \), you can find \( k \) by substituting these values into the equation. This makes finding \( k \) an essential step:
When given initial values of \( x \) and \( y \), you can find \( k \) by substituting these values into the equation. This makes finding \( k \) an essential step:
- Substitute the known values into the equation to calculate \( k \).
- Reverse engineer the problem: now that \( k \) is known, you can solve for the unknown variable using the same base equation.
- This process is consistent regardless of which variable is unknown.
Direct and Inverse Relationships
Understanding the difference between direct and inverse relationships is key in many mathematical problems. In a direct variation, two variables change in the same direction. If one increases, so does the other. Alternatively, inverse variation implies an opposite change:
- In direct variation: \( y = kx \), the variables increase or decrease together.
- In inverse variation: \( y \times x = k \), as one variable increases, the other decreases.
Other exercises in this chapter
Problem 28
Find the intercepts of the functions. $$f(x)=x^{3}+27$$
View solution Problem 28
For the following exercises, use the vertex \((h, k)\) and a point on the graph \((x, y)\) to find the general form of the equation of the quadratic function. $
View solution Problem 29
For the following exercises, describe the local and end behavior of the functions. $$ f(x)=\frac{2 x^{2}-32}{6 x^{2}+13 x-5} $$
View solution Problem 29
For the following exercises, find the inverse of the functions. $$ f(x)=x^{2}+4 x+1,[-2, \infty) $$
View solution