Problem 29
Question
For the following exercises, expand the binomial. $$(3 y-6)^{2}$$
Step-by-Step Solution
Verified Answer
(3y-6)^2 = 9y^2 - 36y + 36
1Step 1: Understand the Binomial Theorem
The binomial theorem states that \((a + b)^n\) can be expanded into a series of terms based on the powers of \(a\) and \(b\). For this exercise, we will expand using \((a - b)^2\) where \(a = 3y\) and \(b = 6\).
2Step 2: Apply the Formula for Squaring a Binomial
The formula for squaring a binomial \((a - b)^2\) is \(a^2 - 2ab + b^2\). We'll use this formula to expand \((3y - 6)^2\) by substituting \(a = 3y\) and \(b = 6\).
3Step 3: Calculate Each Term in the Expansion
First, calculate \(a^2 = (3y)^2 = 9y^2\). Next, calculate \(-2ab = -2(3y)(6) = -36y\). Finally, calculate \(b^2 = 6^2 = 36\).
4Step 4: Combine the Terms
Combine the calculated terms into the expanded form: \(9y^2 - 36y + 36\).
5Step 5: Verify the Calculation
Review each calculation to ensure accuracy. Confirm that \(9y^2\), \(-36y\), and \(+36\) are correctly derived from the original expression \((3y - 6)^2\).
Key Concepts
Binomial TheoremSquaring a BinomialAlgebraic Expressions
Binomial Theorem
The binomial theorem provides us with a powerful way to expand expressions of the form \((a + b)^n\). The theorem uses a formula that simplifies the process of expanding binomials by dealing with the powers of both terms in the binomial. When approached step-by-step, this allows us to find the expanded form of any binomial raised to a power without directly multiplying out large expressions.
For example, in the exercise \((3y - 6)^2\), we're using a special case of the binomial theorem tailored for squaring a binomial term. It's a great introduction to working with binomials because it focuses specifically on the pattern that emerges when \(n = 2\).
For example, in the exercise \((3y - 6)^2\), we're using a special case of the binomial theorem tailored for squaring a binomial term. It's a great introduction to working with binomials because it focuses specifically on the pattern that emerges when \(n = 2\).
- The core idea is to leverage the predictable pattern in the expansion to simplify our calculations.
- Understanding this theorem better equips us to approach more complex polynomial expressions.
Squaring a Binomial
Squaring a binomial involves expanding an expression of the form \((a - b)^2\), which is a foundational skill in algebra. Doing this allows us to convert the squared binomial into a sum of terms, utilizing the formula \(a^2 - 2ab + b^2\).
This formula results from multiplying the binomial by itself, thus allowing us to break it down into smaller, more manageable pieces. In the given exercise \((3y - 6)^2\), you're essentially applying this blueprint to find out what it expands to.
This formula results from multiplying the binomial by itself, thus allowing us to break it down into smaller, more manageable pieces. In the given exercise \((3y - 6)^2\), you're essentially applying this blueprint to find out what it expands to.
- Each part of the formula has a specific purpose:
- \(a^2\): multiplies the first term by itself.
- -2ab: represents twice the product of both terms.
- \(b^2\): squares the second term.
- By splitting the binomial, you gain insight into how each part contributes to the expansion.
Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and operations. They form the building blocks of algebra, making it possible to describe general patterns and solve equations.
Working with algebraic expressions involves manipulating these elements to simplify or transform them into a desired format, like expanding binomials or factoring polynomials.
Working with algebraic expressions involves manipulating these elements to simplify or transform them into a desired format, like expanding binomials or factoring polynomials.
- Understanding the way these expressions are constructed is crucial to grasp many algebraic concepts.
- Expressions like \((3y - 6)^2\) introduce a structured method to approach more complex algebraic problems.
Other exercises in this chapter
Problem 29
For the following exercises, divide the rational expressions. $$ \frac{144 b^{2}-25}{72 b^{2}-6 b-10} \div \frac{18 b^{2}-21 b+5}{36 b^{2}-18 b-10} $$
View solution Problem 29
For the following exercises, simplify each expression. $$ \frac{8}{1-\sqrt{17}} $$
View solution Problem 29
Divide the rational expressions. $$ \frac{144 b^{2}-25}{72 b^{2}-6 b-10} \div \frac{18 b^{2}-21 b+5}{36 b^{2}-18 b-10} $$
View solution Problem 29
Simplify each expression. $$\frac{8}{1-\sqrt{17}}$$
View solution