Problem 29
Question
For each pair of bonds, predict which is the shorter. (a) \(\mathrm{B}-\mathrm{Cl}\) or \(\mathrm{Ga}-\mathrm{Cl}\) (b) \(\mathrm{C}-\mathrm{O}\) or \(\mathrm{Sn}-\mathrm{O}\) (c) \(\mathrm{P}-\mathrm{S}\) or \(\mathrm{P}-\mathrm{O}\) (d) The \(\mathrm{C}=\mathrm{C}\) or the \(\mathrm{C}=\mathrm{O}\) bond in acrolein
Step-by-Step Solution
Verified Answer
(a) B-Cl, (b) C-O, (c) P-O, (d) C=O are shorter bonds.
1Step 1: Understand Bond Length Basics
Bond length is the distance between the nuclei of two bonded atoms. Generally, bonds involving smaller atoms or multiple bonds (like double or triple bonds) are shorter. Elements that are higher up on the periodic table often have shorter bonds because their atomic radii are smaller.
2Step 2: Compare B-Cl and Ga-Cl Bond Lengths
Boron (B) is higher on the periodic table than Gallium (Ga), which implies that the B–Cl bond is typically shorter than the Ga–Cl bond because boron is smaller than gallium.
3Step 3: Compare C-O and Sn-O Bond Lengths
Carbon (C) is higher on the periodic table than Tin (Sn), indicating that the C–O bond is shorter than the Sn–O bond, as carbon is smaller and forms shorter bonds compared to tin.
4Step 4: Compare P-S and P-O Bond Lengths
Oxygen is more electronegative and smaller than sulfur, which means that a P–O bond is shorter than a P–S bond, as oxygen forms shorter bonds than sulfur.
5Step 5: Compare C=C and C=O Bond Lengths
Oxygen, being more electronegative and forming stronger bonds than carbon, typically results in a shorter C=O bond than a C=C bond, as observed in acrolein.
Key Concepts
Periodic Table TrendsAtomic RadiiElectronegativityMultiple Bonds
Periodic Table Trends
The periodic table is a fundamental tool in chemistry, organizing elements based on their atomic number and electron configurations. One key trend you notice is that atomic size changes across the table. Atomic size generally decreases from left to right across a period due to increasing nuclear charge pulling electrons closer to the nucleus. It increases from top to bottom down a group because additional electron shells are added.
Understanding these trends helps predict several properties, including bond length.
Understanding these trends helps predict several properties, including bond length.
- Smaller atoms, often seen higher on the periodic table, tend to form shorter bonds due to their reduced atomic radii.
- Greater electronegativities across periods result in varying bond strengths and lengths.
Atomic Radii
Atomic radii refer to the size of an atom, typically defined as half the distance between two nuclei of the same element bonded together. This concept is essential in determining bond lengths in molecular structures.
Smaller atomic radii usually lead to shorter bonds, as the nuclei are closer together.
Smaller atomic radii usually lead to shorter bonds, as the nuclei are closer together.
- The radii decrease across a period from left to right due to increasing positive charge, drawing electrons inward.
- Atomic radii increase down a group because of the addition of electron shells, which outweighs the increasing nuclear charge.
- Atoms higher up and to the right on the periodic table generally form shorter, tighter bonds.
Electronegativity
Electronegativity measures an atom's ability to attract and hold electrons in a bond. It is a crucial factor that affects bond length and bond strength.
Atoms with high electronegativity, like oxygen and fluorine, often form shorter and stronger covalent bonds because they attract bonding electrons more forcefully.
Atoms with high electronegativity, like oxygen and fluorine, often form shorter and stronger covalent bonds because they attract bonding electrons more forcefully.
- Generally, electronegativity increases across a period from left to right, as atoms become more eager to complete their electron shells.
- It decreases down a group as the increased distance from the nucleus lessens the attractive force on bonding electrons.
- This concept helps explain why the \( \mathrm{C} = \mathrm{O} \) bond is typically shorter than the \( \mathrm{C} = \mathrm{C} \) bond because oxygen is more electronegative than carbon.
Multiple Bonds
Multiple bonds, such as double and triple bonds, are stronger and shorter than single bonds. The presence of additional shared electrons in multiple bonds increases the attraction between the bonded atoms, drawing them closer together.
- For example, double bonds like \( \mathrm{C} = \mathrm{O} \) and \( \mathrm{C} = \mathrm{C} \) illustrate how multiple bonds are usually shorter and stronger due to more shared electrons.
- These bonds involve the overlapping of p-orbitals, resulting in increased electron density between the atoms.
- The bond order, or number of chemical bonds between a pair of atoms, is higher in multiple bonds, further contributing to the shortened bond length.
Other exercises in this chapter
Problem 27
In each case, tell whether cis and trans isomers exist. If they do, write structural formulas for the two isomers and label each cis or trans. For those that ca
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Which of these molecules can have cis and trans iso- mers? For those that do, write the structural formulas of the two isomers and label each cis or trans. For
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For each pair of bonds, predict which is the shorter. (a) \(\mathrm{Si}-\mathrm{N}\) or \(\mathrm{P}-\mathrm{O}\) (b) \(\mathrm{Si}-\mathrm{O}\) or \(\mathrm{C}
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Using only a periodic table (not a table of bond energies), predict which is the strongest bond. (a) \(\mathrm{Si}-\mathrm{F}\) (b) \(\mathrm{P}-\mathrm{S}\) (c
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