Problem 29
Question
Find \(x\) if the line through \((-2,4)\) and \((x, 6)\) has a slope of \(\frac{2}{9}\).
Step-by-Step Solution
Verified Answer
The value of \(x\) is 7.
1Step 1: Understand the Slope Formula
The slope of a line passing through two points \(x_1, y_1\) and \(x_2, y_2\) is given by the formula \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]. In this problem, you are given a slope, m = \(\frac{2}{9}\), and the points (-2, 4) and (x, 6), where x is unknown.
2Step 2: Apply Given Values to the Slope Formula
Using the slope formula with the given points (-2, 4) and (x, 6), substitute the values: \[ \frac{6 - 4}{x - (-2)} = \frac{2}{9} \]. Simplify to get: \[ \frac{2}{x + 2} = \frac{2}{9} \].
3Step 3: Solve for x
Since the fractions are equal, set the denominators equal: \(x + 2 = 9\). Solve for x by subtracting 2 from both sides: \[ x = 9 - 2 \]. Thus, \[ x = 7 \].
Key Concepts
Slope FormulaLinear EquationsSolving for Variables
Slope Formula
The slope formula is essential for understanding linear relationships in algebra. It helps us determine how steep or flat a line is between two specific points. When we talk about slope in algebra, we're referring to the change in the vertical direction (up-down) compared to the change in the horizontal direction (left-right). This is often represented as the ratio \( m = \frac{y_2 - y_1}{x_2 - x_1} \), where \( (x_1, y_1) \) and \( (x_2, y_2) \) are two points on a line.
- Numerator: The "rise" or vertical change between the two points.
- Denominator: The "run" or horizontal change between the two points.
Linear Equations
Linear equations form the basis of algebra and involve expressions of the first degree, meaning the variable is not raised to any power other than one. These equations typically have the form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept, the place where the line crosses the y-axis. However, linear equations can also be represented in a point-slope form or standard form.
- Point-Slope Form: Utilizes a given point and slope to model the line, expressed as \( y - y_1 = m(x - x_1) \).
- Standard Form: Typically written as \( Ax + By = C \), focusing more on the coefficients and constant terms.
Solving for Variables
Solving for variables is a crucial skill in algebra. It involves figuring out the value of unknowns that make an equation true. In this context, the variable \( x \) needs to be isolated to find its value. Let's break this down using our example:
- When given the slope \( \frac{2}{9} \) and points \((-2, 4)\) and \((x, 6)\), we formulated the equation \( \frac{2}{x+2} = \frac{2}{9} \).
- Since the numerators are the same, we focus on equaling the denominators so \( x + 2 = 9 \).
- Then, simply subtract \( 2 \) from both sides to solve for \( x \), resulting in \( x = 7 \).
Other exercises in this chapter
Problem 28
\(\operatorname{Graph}|y|>1\).
View solution Problem 29
\(x\) intercept of \(-3\) and slope of \(-\frac{5}{8}\)
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Graph \(|x+y|
View solution Problem 30
Find \(y\) if the line through \((1, y)\) and \((4,2)\) has a slope of \(\frac{5}{3}\).
View solution