Problem 29
Question
Find the domain of the function. $$ g(w)=\frac{2 w-8}{w^{2}-16} $$
Step-by-Step Solution
Verified Answer
The domain of \( g(w) \) is \((-\infty, -4) \cup (-4, 4) \cup (4, \infty)\).
1Step 1: Identify the Function's Denominator
The first step in finding the domain of the function is to identify the values of the variable that would make the denominator equal to zero. For the function \( g(w) = \frac{2w - 8}{w^2 - 16} \), the denominator is \( w^2 - 16 \).
2Step 2: Set the Denominator to Zero
Set the denominator equal to zero and solve for \( w \):\[w^2 - 16 = 0\]This equation reveals the critical values where the function is undefined.
3Step 3: Solve the Equation
Solve the equation \( w^2 - 16 = 0 \). By factoring the equation, we have: \[(w - 4)(w + 4) = 0\]This gives \( w = 4 \) and \( w = -4 \).
4Step 4: Determine the Domain
The domain of \( g(w) \) is all real numbers except for those values that make the denominator zero. Thus, the domain of \( g(w) \) is \[w \in \mathbb{R} \setminus \{-4, 4\}\].
5Step 5: Express the Domain In Interval Notation
The domain in interval notation excludes the points where the function is undefined: \[(-\infty, -4) \cup (-4, 4) \cup (4, \infty)\].
Key Concepts
Denominator in FunctionsFactoring EquationsUsing Interval NotationUnderstanding Real Numbers
Denominator in Functions
In mathematics, the denominator of a fraction represents the bottom part of the fraction. It tells you into how many equal parts the whole is divided. For functions that are rational, like the one in our problem, the denominator is particularly important.
For the function \( g(w) = \frac{2w - 8}{w^2 - 16} \), the denominator is \( w^2 - 16 \). The domain of a function is the set of all possible input values (or \( w \) values here) that keep the function defined. Since dividing by zero is undefined, we seek to find when the denominator becomes zero and exclude such values.
For the function \( g(w) = \frac{2w - 8}{w^2 - 16} \), the denominator is \( w^2 - 16 \). The domain of a function is the set of all possible input values (or \( w \) values here) that keep the function defined. Since dividing by zero is undefined, we seek to find when the denominator becomes zero and exclude such values.
- Identify the denominator: \( w^2 - 16 \)
- Set it equal to zero to find problematic points
Factoring Equations
Factoring is a method used to simplify equations and find solutions. It involves breaking down a complex expression into more manageable components.
In the equation \( w^2 - 16 = 0 \), we can recognize this as a difference of squares. A difference of squares follows the pattern \( a^2 - b^2 = (a - b)(a + b) \).
Here, \( w^2 - 4^2 \) can be factored as:
In the equation \( w^2 - 16 = 0 \), we can recognize this as a difference of squares. A difference of squares follows the pattern \( a^2 - b^2 = (a - b)(a + b) \).
Here, \( w^2 - 4^2 \) can be factored as:
- \((w - 4)(w + 4) = 0\)
Using Interval Notation
Interval notation is a mathematical method used to describe a set of numbers along the number line. It is especially useful for conveying the domain of a function.
When determining the domain, we avoid values that make the denominator zero. Since \( w = 4 \) and \( w = -4 \) are these problematic values, we must exclude them. In interval notation, this exclusion can be elegantly expressed as:
When determining the domain, we avoid values that make the denominator zero. Since \( w = 4 \) and \( w = -4 \) are these problematic values, we must exclude them. In interval notation, this exclusion can be elegantly expressed as:
- \((-fty, -4) \cup (-4, 4) \cup (4, fty)\)
Understanding Real Numbers
Real numbers encompass a vast set of numbers that include both rational and irrational numbers. They are essentially all numbers that can be found on the number line.
This category includes:
Real numbers thus provide a comprehensive framework for solving, graphing, and understanding functions across different mathematical contexts.
This category includes:
- Integers, like -1, 0, and 1
- Fractions, such as \( \frac{1}{2} \) and 0.75
- Irrational numbers, like \( \sqrt{2} \) and \( \pi \)
Real numbers thus provide a comprehensive framework for solving, graphing, and understanding functions across different mathematical contexts.
Other exercises in this chapter
Problem 29
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Determine at which points the graphs of the given pair of functions intersect. $$ f(x)=e^{x} \text { and } g(x)=e^{-x^{2}} $$
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