Problem 29
Question
Find an antiderivative \(F(x)\) with \(F^{\prime}(x)=\) \(f(x)\) and \(F(0)=0\). Is there only one possible solution? $$ f(x)=2+4 x+5 x^{2} $$
Step-by-Step Solution
Verified Answer
The antiderivative is \( F(x) = 2x + 2x^2 + \frac{5}{3}x^3 \), and it is unique.
1Step 1: Identify the Given Function
The given function is \( f(x) = 2 + 4x + 5x^2 \). We need to find an antiderivative \( F(x) \) of this function.
2Step 2: Apply the Power Rule of Integration
Integrate each term of \( f(x) \) separately. According to the power rule of integration, \( \int x^n \cdot dx = \frac{x^{n+1}}{n+1} + C \), where \( C \) is the integration constant.
3Step 3: Integrate Each Term
1. For the constant \( 2 \), the integral is \( 2x.\) 2. For \( 4x \), the integral is \( 4 \cdot \frac{x^2}{2} = 2x^2.\) 3. For \( 5x^2 \), the integral is \( 5 \cdot \frac{x^3}{3} = \frac{5}{3}x^3. \)
4Step 4: Combine the Integrated Terms
Combine the integrations: \[ F(x) = 2x + 2x^2 + \frac{5}{3}x^3 + C \] Here, \( C \) is an arbitrary constant.
5Step 5: Apply the Initial Condition
Use the initial condition \( F(0) = 0 \) to solve for \( C \). Substitute \( x = 0 \) into the antiderivative:\[ F(0) = 2(0) + 2(0)^2 + \frac{5}{3}(0)^3 + C = 0 \] This simplifies to \( C = 0 \).
6Step 6: Write the Final Antiderivative
Substituting \( C = 0 \) into the antiderivative, we have: \[ F(x) = 2x + 2x^2 + \frac{5}{3}x^3 \]
7Step 7: Evaluate Uniqueness
Since \( F(x) = 2x + 2x^2 + \frac{5}{3}x^3 \) satisfies the initial condition \( F(0) = 0 \) and there are no additional constants possible to satisfy this condition, this antiderivative is unique.
Key Concepts
Power Rule of IntegrationInitial ConditionsUniqueness of Solutions
Power Rule of Integration
Antiderivatives are functions that reverse the process of differentiation. To find the antiderivative of a function, we often rely on a powerful technique known as the Power Rule of Integration. This rule simplifies the process of integration by providing a straightforward formula: - If you have a term in the form of \(x^n\), you can find its integral by using \(\int x^n \, dx = \frac{x^{n+1}}{n+1} + C\), where \(C\) is the constant of integration. - Apply this rule to each term separately.
In our example, the function \(f(x) = 2 + 4x + 5x^2\) contains three terms. We integrate each one: - For the constant \(2\), it becomes a linear term \(2x\). - For \(4x\), use the power rule to get \(2x^2\). - For \(5x^2\), applying the rule results in \(\frac{5}{3}x^3\).
Combining these results gives us the antiderivative \(F(x) = 2x + 2x^2 + \frac{5}{3}x^3 + C\), demonstrating the ease and consistency of the Power Rule.
In our example, the function \(f(x) = 2 + 4x + 5x^2\) contains three terms. We integrate each one: - For the constant \(2\), it becomes a linear term \(2x\). - For \(4x\), use the power rule to get \(2x^2\). - For \(5x^2\), applying the rule results in \(\frac{5}{3}x^3\).
Combining these results gives us the antiderivative \(F(x) = 2x + 2x^2 + \frac{5}{3}x^3 + C\), demonstrating the ease and consistency of the Power Rule.
Initial Conditions
Initial conditions give specific values that an antiderivative must satisfy. In many cases, they allow us to determine the constant of integration \(C\) and, therefore, identify a particular solution. Consider the antiderivative \(F(x) = 2x + 2x^2 + \frac{5}{3}x^3 + C\), derived for the function \(f(x) = 2 + 4x + 5x^2\).
Given the initial condition \(F(0) = 0\), we substitute \(x = 0\) into the antiderivative: - \(0 = 2(0) + 2(0)^2 + \frac{5}{3}(0)^3 + C\) simplifies to \(C = 0\). This step is crucial; it transforms the general antiderivative into a unique solution: \(F(x) = 2x + 2x^2 + \frac{5}{3}x^3\).
Initial conditions ensure that the antiderivative aligns precisely with certain values, providing specificity and accuracy in solutions.
Given the initial condition \(F(0) = 0\), we substitute \(x = 0\) into the antiderivative: - \(0 = 2(0) + 2(0)^2 + \frac{5}{3}(0)^3 + C\) simplifies to \(C = 0\). This step is crucial; it transforms the general antiderivative into a unique solution: \(F(x) = 2x + 2x^2 + \frac{5}{3}x^3\).
Initial conditions ensure that the antiderivative aligns precisely with certain values, providing specificity and accuracy in solutions.
Uniqueness of Solutions
The uniqueness of a solution for an antiderivative derived from an initial condition is an important concept. When an initial condition is applied to solve for the constant \(C\), any further variation leading to a different antiderivative is prevented. With \(F(x) = 2x + 2x^2 + \frac{5}{3}x^3\) obtained earlier, the condition \(F(0) = 0\) was satisfied with \(C = 0\) through a straightforward substitution.
Because this value of \(C\) was calculated to fulfill the initial condition, the solution becomes distinct. No other constant can make \(F(x)\) meet the requirement \(F(0) = 0\).
Because this value of \(C\) was calculated to fulfill the initial condition, the solution becomes distinct. No other constant can make \(F(x)\) meet the requirement \(F(0) = 0\).
- The established antiderivative fits the initial condition perfectly.
- There is no room for alteration in \(F(x)\).
Other exercises in this chapter
Problem 29
Derive the formula (called a reduction formula): $$ \int x^{n} e^{x} d x=x^{n} e^{x}-n \int x^{n-1} e^{x} d x $$
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Use the Fundamental Theorem of Calculus to find the average value of \(f(x)=e^{0.5 x}\) between \(x=0\) and \(x=3\). Show the average value on a graph of \(f(x)
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Find the integrals in problems. Check your answers by differentiation. $$ \int x e^{3 x^{2}} d x $$
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Find the exact area of the region bounded by the \(x\) -axis and the graph of \(y=x^{3}-x\).
View solution