Problem 29
Question
Factor each trinomial, or state that the trinomial is prime. $$4 x^{2}+16 x+15$$
Step-by-Step Solution
Verified Answer
The factored form of the trinomial \(4x^2 + 16x + 15\) is \((2x + 3)(2x + 5)\).
1Step 1: Identify the coefficients
Identify the coefficients and the constant in the trinomial. In the given trinomial \(4x^2 + 16x + 15\), \(a = 4\), \(b = 16\), and \(c = 15\).
2Step 2: Find product of \(a\) and \(c\)
Calculate the product of \(a\) and \(c\), which gives \(4 \cdot 15 = 60\). Now, look for two numbers that multiply to 60 and add up to 16.
3Step 3: Identify the factors
The two numbers that fulfill these requirements are 6 and 10 because \(6 \cdot 10 = 60\) and \(6 + 10 = 16\). These two numbers will be used to split the middle term.
4Step 4: Rewrite the middle term and factor by grouping
Rewrite the trinomial \(4x^2 + 16x + 15\) as \(4x^2 + 6x + 10x + 15\). Now, group the terms to factor by grouping, so we have \(2x(2x + 3) + 5(2x + 3)\).
5Step 5: Final factorization
Since both terms have a common factor of \(2x + 3\), factor it out, leaving the factored form of the trinomial as \((2x + 3)(2x + 5)\).
Other exercises in this chapter
Problem 29
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Multiply or divide as indicated. $$\frac{x^{2}-25}{2 x-2} \div \frac{x^{2}+10 x+25}{x^{2}+4 x-5}$$
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Find each product. $$\left(8 x^{3}+3\right)\left(x^{2}-5\right)$$
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