Problem 29
Question
Exer. 23-34: Sketch the graph of the circle or semicircle. $$ 4 x^{2}+4 y^{2}=25 $$
Step-by-Step Solution
Verified Answer
The graph of \(4x^{2} + 4y^{2} = 25\) is a circle with center (0,0) and radius \(\frac{5}{2}\).
1Step 1: Identify Circle Equation
The given equation of the geometrical shape is \(4x^{2} + 4y^{2} = 25\). This equation represents a circle, but it is not in the standard form of a circle, which is \((x-h)^2 + (y-k)^2 = r^2\). To rewrite it, observe that both \(x^2\) and \(y^2\) are multiplied by 4.
2Step 2: Simplify to Standard Form
Divide every term in the equation by 4 to simplify it: \(x^{2} + y^{2} = \frac{25}{4}\). This is now in the standard form of a circle \((x-h)^2 + (y-k)^2 = r^2\), where \(h = 0\), \(k = 0\), and \(r^2 = \frac{25}{4}\). Thus, the center of the circle is at the origin (0,0) and the radius \(r = \sqrt{\frac{25}{4}} = \frac{5}{2}\).
3Step 3: Plot the Circle
On a coordinate plane, place a point at the origin to represent the center of the circle. Using the radius \(\frac{5}{2}\), measure out from the origin in all directions to the points (\(\frac{5}{2},0\)), (-\(\frac{5}{2},0\)), (0,\(\frac{5}{2}\)), and (0,-\(\frac{5}{2}\)). These are the endpoints of the circle's diameter lines on the x and y axes.
4Step 4: Sketch the Circle
Draw a smooth round curve connecting these four points, making sure the curve is equidistant from the center at all points. This completes the sketch of the circle defined by the simplified equation.
Key Concepts
Standard Form of a CircleCenter and Radius of a CircleGraphing Circles
Standard Form of a Circle
The standard form of a circle's equation is expressed as \((x-h)^2 + (y-k)^2 = r^2\). This format is particularly useful because it provides immediate information about the circle's position and size:
- \((h, k)\) represents the center of the circle.
- \(r^2\) is the radius squared.
Center and Radius of a Circle
Once we have a circle's equation in the standard form \((x-h)^2 + (y-k)^2 = r^2\), identifying the center and radius is a straightforward task. The
The process of obtaining the radius involves solving \(r = \sqrt{r^2}\). With the solution's equation, this means calculating \(r = \sqrt{\frac{25}{4}}\), resulting in a radius \(r = \frac{5}{2}\). Knowing the center and radius, we have all we need to graph the circle.
- center is the point \((h, k)\), where \(h\) and \(k\) are constants from the equation.
- radius is \(r\), which is the square root of \(r^2\).
The process of obtaining the radius involves solving \(r = \sqrt{r^2}\). With the solution's equation, this means calculating \(r = \sqrt{\frac{25}{4}}\), resulting in a radius \(r = \frac{5}{2}\). Knowing the center and radius, we have all we need to graph the circle.
Graphing Circles
When it comes to graphing circles, positioning the center and using the radius efficiently are vital steps. With the exercise's equation reformed to \(x^2 + y^2 = \frac{25}{4}\), the center of the circle is already identified at the origin (0,0) on the coordinate plane.
To graph:
To graph:
- Start at the center point and mark it clearly on your plane.
- Using the radius \(\frac{5}{2}\), measure this distance outwards from the origin in four cardinal directions: right and left along the x-axis and up and down along the y-axis.
- This will create four key points at \((\frac{5}{2}, 0), (-\frac{5}{2}, 0), (0, \frac{5}{2}), (0, -\frac{5}{2})\).
- Finally, draw a smooth, round curve connecting these points, ensuring it's equidistant from the center to maintain the circle's shape.
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