Problem 29
Question
Evaluate the expression without using a calculator. $$ (\sqrt[3]{64})^{4} $$
Step-by-Step Solution
Verified Answer
The result of \( (\sqrt[3]{64})^{4} \) is 256.
1Step 1: Simplify the Cube Root
Begin by simplifying the cube root of 64. A cube root asks the question 'what number times itself twice gives me this?' In the case of 64, the cube root is 4, because \(4 * 4 * 4 = 64\). So, \( \sqrt[3]{64} = 4 \).
2Step 2: Apply the Exponent
Now that we have simplified \( \sqrt[3]{64} \) to 4, we need to apply the exponent. The exercise asks us to raise this result to the 4th power, meaning we multiply it by itself four times. So, \(4^4 = 4 * 4 * 4 * 4 = 256\).
Key Concepts
Cube RootSimplifying RadicalsExponent Rules
Cube Root
A cube root helps us identify a number which, when multiplied by itself three times, gives us the original value. In simple terms, the cube root of a number like 64 asks, "What number times itself twice equals 64?" Here is how you can think about it:
- Imagine you have a number, say \( n \).
- When \( n \times n \times n = 64 \), \( n \) is the cube root of 64.
- For 64, the answer is 4 because \( 4 \times 4 \times 4 = 64 \).
Simplifying Radicals
Simplifying radicals is about making expressions like roots easier to work with. When we encounter a radical expression, our goal is to express it in the simplest form possible. Take the cube root of 64, for example. The sequence goes:
- Find the number which when cubed gives 64, which we found is 4.
- Hence, \( \sqrt[3]{64} = 4 \).
Exponent Rules
Exponent rules are foundational for solving problems involving powers. These rules dictate how we handle expressions that involve numbers raised to any power. Here's how it works in our context:
- After simplifying \( \sqrt[3]{64} \) to 4, you're asked to use an exponent.
- The expression \( 4^4 \) means multiplying 4 by itself four times: \( 4 \times 4 \times 4 \times 4 = 256 \).
- Exponents essentially provide a shorthand for repeated multiplication.
Other exercises in this chapter
Problem 29
Graph the points. Determine whether they are vertices of a right triangle. $$ (-3,2),(-3,5),(0,2) $$
View solution Problem 29
Solve by completing the square. $$ x^{2}-8 x+12=0 $$
View solution Problem 29
Simplify the expression. $$ \sqrt{6}(\sqrt{6}-1) $$
View solution Problem 29
Find the domain of the function. Then use several values in the domain to make a table of values for the function. $$y=6 \sqrt{x}$$
View solution