Problem 29
Question
Determine whether the sequence converges or diverges. If it converges, find the limit. \( a_n = e^{-1/ \sqrt n} \)
Step-by-Step Solution
Verified Answer
The sequence converges, and the limit is 1.
1Step 1: Identify the Type of Sequence
The sequence given is \( a_n = e^{-1/ \sqrt{n}} \). It is an exponential sequence where the exponent is \(-1/ \sqrt{n}\). As \(n\) approaches infinity, the term \(\sqrt{n}\) also increases.
2Step 2: Consider the Limit of the Exponent
Let's focus on the exponent \(-1/ \sqrt{n}\). As \(n \to \infty\), \(\sqrt{n}\) also approaches infinity, which means \(1/ \sqrt{n}\) approaches 0. Consequently, the whole exponent \(-1/ \sqrt{n}\) approaches 0.
3Step 3: Determine the Limit of the Sequence
Since \(-1/ \sqrt{n} \to 0\) as \(n \to \infty\), we look at the limit of the exponential function. For \(a_n = e^{x}\) where \(x \to 0\), \(e^x \to e^0 = 1\). Thus, the sequence \(a_n = e^{-1/ \sqrt{n}}\) converges to 1 as \(n\) goes to infinity.
4Step 4: Conclusion on Convergence
Therefore, the sequence \( a_n = e^{-1/ \sqrt{n}} \) converges, and its limit is 1.
Key Concepts
Exponential SequenceLimit of a SequenceConvergent SequenceExponential Function Behavior
Exponential Sequence
An exponential sequence is a sequence where the terms involve an exponent that is a function of the index, like in the given example, \( a_n = e^{-1/\sqrt{n}} \). Here, the base is the mathematical constant \( e \), commonly known as Euler's number, which is approximately equal to 2.718. In an exponential sequence, the changes in the index \( n \) result in a significant change in the values of the terms due to the exponentiation.
- The base \( e \) is a constant known to be important in many areas of mathematics such as calculus and complex numbers.
- The behavior of the sequence is greatly impacted by the exponent, which can cause rapid growth or decay depending on its value.
Limit of a Sequence
The limit of a sequence refers to the value that the terms of a sequence approach as the sequence progresses toward infinity. For the sequence \( a_n = e^{-1/\sqrt{n}} \), recognizing the behavior of the expression \(-1/\sqrt{n}\) is key in finding its limit.
- As \( n \) becomes very large, \( \sqrt{n} \) also grows larger, causing \( 1/\sqrt{n} \) to shrink towards zero.
- Thus, the exponent \(-1/\sqrt{n}\) approaches zero, leading to a crucial evaluation point of the sequence.
Convergent Sequence
A convergent sequence is defined as a sequence where the terms approach a single finite value as \( n \) approaches infinity. This value is known as the sequence's limit. In our example of the sequence \( a_n = e^{-1/\sqrt{n}} \), we can see that it is convergent.
- This conclusion stems from analyzing the behavior of the sequence's exponent: \(-1/\sqrt{n} \) tends towards zero as \( n \to \infty \).
- Subsequently, \( e^{-1/\sqrt{n}} \) approaches \( e^0 = 1 \).
Exponential Function Behavior
The behavior of exponential functions like \( e^x \) is characterized by their exponential growth or decay based on the value of the exponent \( x \). This is a crucial observation when examining sequences such as \( a_n = e^{-1/\sqrt{n}} \).
- Exponential growth occurs when the exponent is positive, resulting in rapidly increasing values.
- Conversely, an exponential function decays when the exponent is negative, leading to values that decrease towards zero.
- In our case, as \( -1/\sqrt{n} \) approaches zero, \( e^{-1/\sqrt{n}} \) approaches \( e^0 = 1 \), illustrating a stabilizing behavior because the exponent itself is approaching zero.
Other exercises in this chapter
Problem 29
Find the values of \( p \) for which the series is convergent. \( \displaystyle \sum_{n = 2}^{\infty} \frac {{1}}{{n(\ln n)^P}} \)
View solution Problem 29
Determine whether the series is convergent or divergent. If it is convergent, find its sum. \( \displaystyle \sum_{n = 1}^{\infty} \frac {2 + n}{1 - 2n} \)
View solution Problem 30
Suppose you know that \( f^{(n)}(4) = \frac {( - 1)^n n!}{3^n(n + 1)} \) and the Taylor series of \( f \) centered at 4 converges to \( f(x) \) for all \( x \)
View solution Problem 30
Use a power series to approximate the definite integral to six decimal places. \( \int^{1/2}_0 \arctan (x/2) dx \)
View solution