Problem 29
Question
Determine whether the integral is convergent or divergent. Evaluate all convergent integrals. Be efficient. If \(\lim _{x \rightarrow \infty} \neq 0\), then \(\int_{a}^{\infty} f(x) d x\) is divergent. \(\int_{1}^{\infty} \frac{x}{\sqrt{3+x^{2}}} d x\)
Step-by-Step Solution
Verified Answer
By carrying out the above steps, we find that \( \lim _{u \rightarrow \infty} 2*\sqrt{u} = \infty \), which is not finite. Therefore, given integral is divergent.
1Step 1: Apply integration by substitution
Let \( u = 3 + x^2 \), then the differential du = 2x dx. The integral changes from \( \int_{1}^{\infty} \frac{x}{\sqrt{3+x^{2}}} dx \) to \( 0.5 * \int_{4}^{\infty} \frac{1}{\sqrt{u}} du \)
2Step 2: Evaluate the resulting integral
The integral is of standard form and simplifies to \( 0.5 * \int_{a}^{\infty} u^{-1/2} du \), which evaluates to \(0.5 * [2*\sqrt{u}]_{4}^{\infty}\)
3Step 3: Substitute the limits of the integral
To determine whether the integral converges or diverges, substitute the limits of the integral into the evaluated integral function: \(f(\infty) - f(4)\)
4Step 4: Test for divergence
Calculate the value of \( \lim _{u \rightarrow \infty} \), if the result isn’t finite, then the given integral is Divergent.
Key Concepts
Convergence and DivergenceIntegration by SubstitutionLimits at Infinity
Convergence and Divergence
Understanding whether an integral is convergent or divergent is essential when dealing with improper integrals. To determine this, we evaluate the behavior of the integral as the variable approaches a point, often infinity. In this context:
- Convergence: When the integral approaches a finite value, meaning it sums up to a finite amount.
- Divergence: When the integral either increases without bound or cannot be summed up to a finite amount.
Integration by Substitution
Integration by substitution is a technique that helps simplify complex integrals by making a clever change of variables. This is especially useful for handling improper integrals that might initially seem too complicated to solve.In our problem, we set \( u = 3 + x^2 \). This substitution transforms the integral from a function of \( x \) to a function of \( u \). The main steps involve:
- Finding the derivative: \( du = 2x \, dx \).
- Rewriting the integral: \( \int_{1}^{\infty} \frac{x}{\sqrt{3+x^{2}}} dx \) becomes \( 0.5 * \int_{4}^{\infty} \frac{1}{\sqrt{u}} du \).
Limits at Infinity
To determine the convergence of an improper integral, evaluating the limit of the function as it approaches infinity is crucial.For the component \( 0.5 * [2*\sqrt{u}]_{4}^{\infty} \), we explore its behavior as \( u \to \infty \). If the resultant value is finite, the integral converges; otherwise, it diverges.In our specific case, as \( u \) increases, \( \sqrt{u} \) grows, leading to the conclusion that \( \lim_{u \to \infty} \sqrt{u} \) is infinite. Hence:
- The integral diverges because the evaluated limit at infinity is infinite.
- The overall value increases without bound, confirming the divergence.
Other exercises in this chapter
Problem 28
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