Problem 29
Question
Convert \(x+y=1\) into an \(r \theta\) equation and solve tor \(r .\) Then substitute this \(r\) into \(x=r \cos \theta\) and \(y=r \sin \theta\) to find parametric equations for the line.
Step-by-Step Solution
Verified Answer
Parametric equations are \( x = \frac{\cos\theta}{\cos\theta + \sin\theta} \) and \( y = \frac{\sin\theta}{\cos\theta + \sin\theta} \).
1Step 1: Set up Polar Coordinate Conversion
To start, we know that in polar coordinates, the relationships between the Cartesian coordinates and polar coordinates are given by:\[ x = r \cos(\theta) \] \[ y = r \sin(\theta) \]Substitute these into the given equation \(x+y=1\).
2Step 2: Substitute and Simplify
Substitute \(x = r \cos(\theta)\) and \(y = r \sin(\theta)\) into the equation:\[ r \cos(\theta) + r \sin(\theta) = 1 \]Factor out the common \(r\):\[ r(\cos(\theta) + \sin(\theta)) = 1 \]
3Step 3: Solve for r
To find \(r\), divide both sides of the equation by \((\cos(\theta) + \sin(\theta))\):\[ r = \frac{1}{\cos(\theta) + \sin(\theta)} \]
4Step 4: Substitute r into x and y Formulas
Now, use the expression for \(r\) to find the parametric equations. Substitute \(r = \frac{1}{\cos(\theta) + \sin(\theta)}\) into \(x = r \cos(\theta)\) and \(y = r \sin(\theta)\):\[ x = \left( \frac{1}{\cos(\theta) + \sin(\theta)} \right) \cos(\theta) \]\[ y = \left( \frac{1}{\cos(\theta) + \sin(\theta)} \right) \sin(\theta) \]
5Step 5: Simplify Parametric Equations
Simplify the expressions for \(x\) and \(y\):\[ x = \frac{\cos(\theta)}{\cos(\theta) + \sin(\theta)} \]\[ y = \frac{\sin(\theta)}{\cos(\theta) + \sin(\theta)} \]
Key Concepts
Parametric EquationsPolar Form ConversionCartesian CoordinatesTrigonometric Identities
Parametric Equations
In mathematics, when we talk about parametric equations, we refer to a way of expressing a set of related quantities as explicit functions of an independent variable. Instead of representing geometric figures (like lines or circles) with an equation involving only the standard coordinates (like x and y), a new variable known as a parameter is introduced.
For example, a line in the Cartesian plane can be expressed by using a single parameter \(t\) such as:
In the context of the exercise, after converting from polar to parametric form, the line \(x + y = 1\) was expressed using equations with parameter \(\theta\). These equations allow us to represent the line in a way that's independent of specific position coordinates, using polar components. This helps in areas like computer graphics, where parametrically driven animations are common.
For example, a line in the Cartesian plane can be expressed by using a single parameter \(t\) such as:
- \(x = x_0 + at\)
- \(y = y_0 + bt\)
In the context of the exercise, after converting from polar to parametric form, the line \(x + y = 1\) was expressed using equations with parameter \(\theta\). These equations allow us to represent the line in a way that's independent of specific position coordinates, using polar components. This helps in areas like computer graphics, where parametrically driven animations are common.
Polar Form Conversion
Converting between Cartesian and polar coordinates is an essential skill in mathematics, especially when dealing with circular shapes or radar plots. The process involves using the trigonometric relationships to represent a Cartesian point \((x,y)\) as a polar point \((r, \theta)\).
The fundamental formulae involved are:
Such conversions are useful in various applications, ranging from physics (waves and oscillations) to engineering (signal processing). They provide a different perspective that is more convenient in certain mathematical problems, especially when symmetry around the origin is involved.
The fundamental formulae involved are:
- \( x = r \cos(\theta) \)
- \( y = r \sin(\theta) \)
Such conversions are useful in various applications, ranging from physics (waves and oscillations) to engineering (signal processing). They provide a different perspective that is more convenient in certain mathematical problems, especially when symmetry around the origin is involved.
Cartesian Coordinates
Cartesian coordinates serve as the foundation for two-dimensional space representations. They use a pair of numerical coordinates, which can show spatial location in relation to two perpendicular lines, traditionally called the x-axis and the y-axis.
This system is named after René Descartes, who laid the groundwork for modern day analytic geometry. In basic terms, every point on the plane is defined by an x (horizontal) and y (vertical) value. Lines like \(x+y=1\) are expressed directly using such coordinates by assessing intersections and slopes.
The Cartesian coordinate system is integral to a variety of fields:
This system is named after René Descartes, who laid the groundwork for modern day analytic geometry. In basic terms, every point on the plane is defined by an x (horizontal) and y (vertical) value. Lines like \(x+y=1\) are expressed directly using such coordinates by assessing intersections and slopes.
The Cartesian coordinate system is integral to a variety of fields:
- Data visualization (graphs and charts)
- Engineering and architecture (blueprints)
- Physics (motion trajectories)
Trigonometric Identities
Trigonometric identities are equations that hold true for all values of the involved variables, thus forming a crucial part of trigonometry involving angles and side ratios in triangles. These identities help in simplifying complex expressions, solving equations, and converting between different forms of functions.
Key trigonometric identities include:
Being comfortable with these identities is essential for solving higher-level mathematics problems in calculus, physics, and engineering, where cyclical phenomena and wave functions are often modeled.
Key trigonometric identities include:
- Pythagorean identity: \( \sin^2(\theta) + \cos^2(\theta) = 1 \)
- Angle sum identity: \( \cos(a + b) = \cos(a)\cos(b) - \sin(a)\sin(b) \)
Being comfortable with these identities is essential for solving higher-level mathematics problems in calculus, physics, and engineering, where cyclical phenomena and wave functions are often modeled.
Other exercises in this chapter
Problem 28
(a) The flower \(r=\cos 2 \theta\) is symmetric across the \(x\) and \(y\) axes. Does that make it symmetric about the origin? (Do two symmetries imply the thir
View solution Problem 29
Find an \(x y\) equation for the flower \(r=\cos 2 \theta\).
View solution Problem 30
Find equations for curves with these properties: (a) Symmetric about the origin but not the \(x\) axis (b) Symmetric across the \(45^{\circ}\) line but not symm
View solution Problem 31
Compute the seashell area \(2 \pi \sqrt{2} \int_{0}^{\alpha} e^{-2 \theta} \cos \theta d \theta\) using two integrations by parts.
View solution