Problem 29
Question
A man of mass \(m_{1}=70.0 \mathrm{~kg}\) is skating at \(v_{1}=\) \(8.00 \mathrm{~m} / \mathrm{s}\) behind his wife of mass \(\mathrm{m}_{2}=50.0 \mathrm{~kg}\), who is skating at \(\tau_{2}=4.00 \mathrm{~m} / \mathrm{s}\). Instead of passing her, he inadvertently collides with her. He grabs her around the waist, and they maintain their balance. (a) Sketch the problem with before-and-after diagrams, representing the skaters as blocks. (b) Is the collision best described as elastic, inelastic, or perfectly inelastic? Why? (c) Write the general equation for conservation of momentum in terms of \(m_{1}, v_{1}, w_{2}, v_{2}\), and final velocity \(v\) - (d) Solve the momentum equation for \(v_{\gamma}\). (e) Substitute values, obtaining the numerical value for \(v_{f}\), their speed after the collision.
Step-by-Step Solution
VerifiedKey Concepts
Perfectly Inelastic Collision
Physics Problem Solving
Next, look for conservation laws applicable to the situation, such as conservation of momentum in collision problems. Simplify complex scenarios by breaking them into stepwise processes:
- Recognize the collision type.
- Apply the proper equations.
- Solve the equations meticulously.
- Substitute the known values to find the unknowns.
Momentum Equation
To find the final velocity \(v_f\), rearrange the equation:\[v_f = \frac{m_{1}v_{1} + m_{2}v_{2}}{m_{1}+m_{2}}\] Here, each object's contribution to the total momentum is summed up to determine the shared speed after impact. It’s crucial to remember, this principle applies broadly across various collision types in an isolated system.
Collision Types
- Elastic Collisions: Both momentum and kinetic energy are conserved. Objects rebound without deformation.
- Inelastic Collisions: Momentum is conserved but kinetic energy is not. The objects might touch but not stick together.
- Perfectly Inelastic Collisions: A subset of inelastic collisions where the objects stick together post-collision, thus moving with the same velocity.