Problem 29
Question
A bottle of ammonia and a bottle of dry hydrogen chloride connected through a long tube are opened simultaneously at both ends, the white ammonium chloride ring first formed will be (a) at the center of the tube (b) near the hydrogen chloride bottle (c) near the ammonia bottle (d) throughout the length of the tube
Step-by-Step Solution
Verified Answer
The ring forms near the hydrogen chloride bottle.
1Step 1: Understand the Problem
We need to determine where the ammonium chloride ring will form when ammonia diffuses from one end of a tube and hydrogen chloride from the other.
2Step 2: Consider Diffusion Speeds
The speed of gas diffusion is inversely proportional to the square root of its molar mass according to Graham's law. Ammonia (NH₃) is lighter with a molar mass of approximately 17 g/mol, while hydrogen chloride (HCl) is heavier with a molar mass of about 36.5 g/mol.
3Step 3: Apply Graham's Law
According to Graham's law, the rate of effusion ( ext{r}) of a gas is inversely proportional to the square root of its molar mass ( ext{M}): \[ \frac{r_{\text{NH}_3}}{r_{\text{HCl}}} = \sqrt{\frac{M_{\text{HCl}}}{M_{\text{NH}_3}}} \]Plugging in the values:\[ \frac{r_{\text{NH}_3}}{r_{\text{HCl}}} = \sqrt{\frac{36.5}{17}} \approx 1.46 \]This means ammonia diffuses faster than hydrogen chloride.
4Step 4: Identify Ring Location
Since ammonia diffuses more rapidly, it travels further down the tube from its source compared to the hydrogen chloride gas. This causes the ammonium chloride ring to form closer to the side where hydrogen chloride is introduced.
Key Concepts
Graham's LawAmmoniaHydrogen ChlorideMolar MassEffusion Rate
Graham's Law
Graham's Law is a fundamental principle in chemistry that explains how gases diffuse and effuse. This law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.
- This means lighter gases will effuse more quickly compared to heavier gases.
- The mathematical formula for this law is: \( \frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}} \), where \( r \) is the effusion rate and \( M \) is the molar mass of the gases.
Ammonia
Ammonia is a colorless gas with a distinct pungent smell. Its chemical formula is \( NH_3 \). Ammonia plays a vital role in numerous industrial processes and is widely used as a fertilizer.
- It has a lower molar mass of approximately 17 g/mol, making it lighter than many other gases.
- This lower molar mass contributes to its faster diffusion rate, as demonstrated with Graham’s Law.
Hydrogen Chloride
Hydrogen chloride, represented by the chemical formula \( HCl \), is a colorless gas known for its strong, acrid smell.
- In its gaseous form, it is more dense and has a molar mass of about 36.5 g/mol, making it heavier than ammonia.
- This heavier molar mass results in a slower diffusion rate under Graham’s Law.
Molar Mass
Understanding molar mass is essential for determining how gases diffuse and react. Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol).
- Lighter gases like ammonia (17 g/mol) diffuse faster due to their smaller mass.
- Heavier gases such as hydrogen chloride (36.5 g/mol) diffuse more slowly.
Effusion Rate
The effusion rate of a gas refers to the speed at which gas molecules escape through a small hole into a vacuum. Factors affecting effusion include the molar mass of the gas and the conditions under which effusion occurs.
- Graham's Law dictates that gas effusion rate is inversely proportional to the square root of the gas's molar mass.
- Thus, lighter gases like ammonia, with a lower molar mass, will effuse more rapidly than heavier gases like hydrogen chloride.
Other exercises in this chapter
Problem 28
The density of neon will be maximum at (a) NTP (b) \(0^{\circ} \mathrm{C}, 2 \mathrm{~atm}\) (c) \(273^{\circ} \mathrm{C}, 1 \mathrm{~atm}\) (d) \(273^{\circ} \
View solution Problem 29
Total volume of atoms present in a face-centerd cubic unit cell of a metal is ( \(r\) is atomic radius) (a) \((20 / 3) \pi \mathrm{r}^{3}\) (b) \((24 / 3) \pi r
View solution Problem 30
The surface tension of which of the following liquids is maximum ? (a) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) (b) \(\mathrm{CH}_{3} \mathrm{OH}\) (c) \(\
View solution Problem 30
According to the kinetic theory of gases, in an ideal gas, between two successive collisions a gas molecule travels (a) in a circular path (b) in a wavy path (c
View solution