Problem 29
Question
A 0.60\(\cdot \mathrm{kg}\) book slides on a horizontal table. The kinetic friction force on the book has magnitude 1.2 \(\mathrm{N}\) . (a) How much work is done on the book by friction during a displacement of 3.0 \(\mathrm{m}\) to the left? (b) The book now slides 3.0 \(\mathrm{m}\) to the right, returning to its starting point. During this second 3.0 \(\mathrm{m}\) displacement, how much work is done on the book by friction? (c) What is the total work done on the book by friction during the complete round trip? (d) On the basis of your answer to part (c), would you say that the friction force is conservative or nonconservative? Explain.
Step-by-Step Solution
Verified Answer
(a) -3.6 J; (b) -3.6 J; (c) -7.2 J; (d) Nonconservative force.
1Step 1: Calculate Work Done (Leftward)
The work done by friction when an object is moved is given by the formula \( W = F_d \cdot d \cdot \cos(\theta) \), where \( F_d \) is the force of friction, \( d \) is the displacement, and \( \theta \) is the angle between the force and displacement. In this scenario, friction acts opposite to the direction of displacement, so \( \theta = 180^\circ \), making \( \cos(\theta) = -1 \). Thus, the work done by friction is \( W = 1.2 \ \text{N} \times 3.0 \ \text{m} \times (-1) = -3.6 \ \text{J} \).
2Step 2: Calculate Work Done (Rightward)
The book now moves 3.0 m to the right, again in the opposite direction to friction. The conditions are the same as in the previous step, with the work done by friction being \( W = 1.2 \ \text{N} \times 3.0 \ \text{m} \times (-1) = -3.6 \ \text{J} \).
3Step 3: Calculate Total Work Done for Round Trip
For the complete round trip (3.0 m to the left and 3.0 m to the right), add the work done during both displacements: \( W_{\text{total}} = -3.6 \ \text{J} + (-3.6 \ \text{J}) = -7.2 \ \text{J} \).
4Step 4: Determine Nature of Friction Force
Friction is nonconservative. A conservative force does zero total work on a closed path; however, friction has done \(-7.2 \ \text{J}\) of work during the round trip, showing it is nonconservative.
Key Concepts
Kinetic FrictionNonconservative ForcesWork-Energy Principle
Kinetic Friction
Kinetic friction is a type of friction that occurs between moving surfaces. When you slide an object over a surface, kinetic friction is the force that resists the motion. This force acts in the opposite direction to the movement. It is proportional to the normal force, the force perpendicular to the contact surface, experienced by the object.
For our book sliding across the table, the force of kinetic friction is given as 1.2 N. This value does not change with the speed of the book and remains constant as long as the surfaces and conditions remain unchanged.
For our book sliding across the table, the force of kinetic friction is given as 1.2 N. This value does not change with the speed of the book and remains constant as long as the surfaces and conditions remain unchanged.
- Kinetic friction depends on both the surfaces in contact and the normal force.
- It causes mechanical energy to convert into thermal energy, thus opposing the sliding motion.
Nonconservative Forces
Nonconservative forces, like friction, are forces where the work they do on a moving object cannot be recovered fully upon the return to an original position. In essence, the energy is lost from the system, often as heat or sound, in a manner that is not reversible.
- Unlike conservative forces, nonconservative forces depend on the path taken, not just start and end positions.
- They continuously extract energy from moving bodies, reducing mechanical energy overall.
Work-Energy Principle
The work-energy principle is fundamental in physics and relates the work done on an object to its change in kinetic energy. According to this principle, if a force does work on an object, it changes the object's kinetic energy by the same amount.
- Work done by nonconservative forces leads to changes in both kinetic energy and thermal energy.
- In our scenario, all the work done by the frictional force converts mechanical energy into thermal energy, so the book's kinetic energy reduces.
Other exercises in this chapter
Problem 27
A \(10.0-\mathrm{kg}\) box is pulled by a horizontal wire in a circle on a rough horizontal surface for which the coefficient of kinetic friction is 0.250 . Cal
View solution Problem 28
In an experiment, one of the forces exerted on a proton is \(\overrightarrow{\boldsymbol{F}}=-\alpha x^{2} \hat{i},\) where \(\alpha=12 \mathrm{N} / \mathrm{m}^
View solution Problem 30
You and three friends stand at the corners of a square whose sides are 8.0 \(\mathrm{m}\) long in the middle of the gym floor, as shown in Fig. \(7.26 .\) You t
View solution Problem 31
A block with mass \(m\) is attached to an ideal spring that has force constant \(k .\) (a) The block moves from \(x_{1}\) to \(x_{2},\) where \(x_{2}>x_{1} .\)
View solution