Problem 29
Question
\(9-32\) n Determine whether the sequence converges or diverges. If it converges, find the limit. $$\\{0,1,0,0,1,0,0,0,1, \ldots\\}$$
Step-by-Step Solution
Verified Answer
The sequence diverges.
1Step 1: Identify the Pattern
Observe the given sequence: \(\{0,1,0,0,1,0,0,0,1, \ldots\}\). Notice that there is a repeating pattern in the sequence: every fourth term is '1', while all other terms are '0'. Thus, the pattern in the sequence is 0, 1, 0, 0, repeating indefinitely.
2Step 2: Determine the Sequence Limit
In a convergent sequence, the terms approach a specific value as the sequence progresses. For the given sequence, as \(n\) becomes very large, the terms will not approach any single number because every fourth term deviates to '1' and the others are '0'. Thus, the sequence does not stabilize at any particular value.
3Step 3: Conclude on Convergence or Divergence
Since the sequence does not settle to any one particular value, and it continues to oscillate between '0' and '1', the sequence neither converges nor approaches a limit. Therefore, the sequence diverges.
Key Concepts
Divergence of SequencesSequence PatternsLimit of a Sequence
Divergence of Sequences
When we talk about whether a sequence converges or diverges, we're basically asking if the sequence settles towards a particular value or not. A diverging sequence, on the other hand, never reaches or approaches a specific number and often fluctuates or grows without bound. In the sequence \[\{0, 1, 0, 0, 1, 0, 0, 0, 1, \ldots\} \]we observe that it does not get closer to any particular number as it progresses. This is because the sequence repeatedly returns to '1' after a few '0’s, leading to no permanent stabilization.
- Non-convergence: Even as we extend the length of the sequence, we cannot zero in on a single value that it tries to reach or settle towards.
- Fluctuation: The mix of '0's and '1's exemplifies divergence through oscillation, as it never sticks to one value.
Sequence Patterns
Understanding the pattern of a sequence is crucial for analyzing its behavior over time. Patterns give us hints about how the sequence can be categorized and studied further.
The given sequence \[\{0, 1, 0, 0, 1, 0, 0, 0, 1, \ldots\} \]clearly shows a repeating pattern.
The given sequence \[\{0, 1, 0, 0, 1, 0, 0, 0, 1, \ldots\} \]clearly shows a repeating pattern.
- Repetitive Nature: There’s a clear pattern where every fourth term is '1', with the rest being '0'.
- Predictability: This periodic repetition makes it predictable but does not lead to convergence.
Limit of a Sequence
The limit of a sequence is a concept used to describe what value the terms of a sequence get closer to as the sequence progresses without end.
A convergent sequence has a distinct number, known as the limit, that it approaches. However, our sequence: \[\{0, 1, 0, 0, 1, 0, 0, 0, 1, \ldots\} \]never stabilizes at any single value as we make the sequence longer.
A convergent sequence has a distinct number, known as the limit, that it approaches. However, our sequence: \[\{0, 1, 0, 0, 1, 0, 0, 0, 1, \ldots\} \]never stabilizes at any single value as we make the sequence longer.
- Absence of Convergence: The terms fluctuate between '0' and '1' repeatedly, illustrating no consistent progression towards a fixed number.
- Irregular Stabilization: If a sequence does not stabilize, a limit does not exist. Therefore, this sequence has no limit.
Other exercises in this chapter
Problem 29
\(19-40=\) Determine whether the series is absolutely convergent, conditionally convergent, or divergent. $$ \sum_{n=1}^{\infty} \frac{\cos (n \pi / 3)}{n !} $$
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Use a Maclaurin series in Table 1 to obtain the Maclaurin series for the given function. $$f(x)=e^{x}+e^{2 x}$$
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Use a power series to approximate the definite integral to six decimal places. $$ \int_{0}^{0.4} \ln \left(1+x^{4}\right) d x $$
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