Problem 29
Question
\(25-30\) Find \(f^{\prime}(a)\) $$f(x)=\frac{1}{\sqrt{x+2}}$$
Step-by-Step Solution
Verified Answer
\(f^{\prime}(a) = -\frac{1}{2(a+2)^{3/2}}\)
1Step 1: Identify the function and the derivative rule needed
We are given the function \(f(x) = \frac{1}{\sqrt{x+2}}\). This function can be rewritten as \(f(x) = (x+2)^{-1/2}\). We need to find the derivative \(f^{\prime}(x)\). To do this, we will use the power rule for differentiation, which is \(\frac{d}{dx}[x^n] = n \cdot x^{n-1}\).
2Step 2: Apply the power rule to differentiate
Using the power rule for derivatives on \(f(x) = (x+2)^{-1/2}\), we find:\[ f^{\prime}(x) = -\frac{1}{2} (x+2)^{-1/2-1} \cdot (1) \]The \(\cdot (1)\) is from the chain rule, as the derivative of \((x+2)\) with respect to \(x\) is 1.
3Step 3: Simplify the derivative
Simplify \(f^{\prime}(x) = -\frac{1}{2} (x+2)^{-3/2}\). The negative exponent \(-3/2\) indicates the expression should be in the denominator in root form:\[ f^{\prime}(x) = -\frac{1}{2} \cdot \frac{1}{(x+2)^{3/2}} = -\frac{1}{2(x+2)^{3/2}} \]
4Step 4: Evaluate the derivative at \(x=a\)
To find \(f^{\prime}(a)\), substitute \(x = a\) into the derivative:\[ f^{\prime}(a) = -\frac{1}{2(a+2)^{3/2}} \]This gives us the rate of change of the function \(f(x)\) at \(x = a\).
Key Concepts
Understanding the Power RuleIntroducing the Chain RuleExploring DifferentiationEssence of Function Simplification
Understanding the Power Rule
The power rule is a fundamental concept in calculus and a go-to tool for differentiating functions with exponents. It states that if you have a function of the form \(x^n\), then its derivative is \(n \cdot x^{n-1}\). This rule simplifies the process of taking derivatives by providing a straightforward formula. Instead of recalculating for each function, you apply this rule directly to find the rate of change. For example, if \(f(x) = x^3\), then the derivative, \(f^{\prime}(x)\), is \(3x^2\). This simple transformation is powerful because it works consistently across polynomial expressions, saving time and effort. When dealing with more complex functions that fit this form, the power rule becomes a trusty companion. Always remember to reduce the power by 1 and multiply by the original power—it's that easy!
Introducing the Chain Rule
The chain rule is essential for differentiating compositions of functions. It helps when you have a function within another function, such as \(f(g(x))\). Imagine you have an outer function and an inner function, both interacting to form a composite. The rule states: \( (f(g(x)))^{\prime} = f^{\prime}(g(x)) \cdot g^{\prime}(x) \). First, differentiate the outer function while keeping the inner function intact, and then multiply by the derivative of the inner function.
- Step 1: Differentiate the outer function \(f\).
- Step 2: Multiply by the derivative of the inner function \(g\).
- Step 3: Combine these elements for the full derivative.
Exploring Differentiation
Differentiation is a core concept in calculus that involves finding the derivative of a function. This process determines how a function changes over time, helping to understand the function's behavior. A derivative gives you the slope of the tangent line to the function's curve at any point, illustrating how the value of the function increases or decreases.
The steps of differentiation require selecting the appropriate rules based on the function's form:
- Use the power rule for polynomial terms.
- Employ the chain rule for composite functions.
- Consider other rules for trigonometric, exponential, or logarithm functions.
Essence of Function Simplification
Function simplification is key to making derivatives easier to handle. Before differentiating, simplify your function whenever possible. This step can reduce complexity and prevent errors, especially when dealing with fractions, roots, or negative exponents. In the given task, rewriting \(\frac{1}{\sqrt{x+2}}\) as \((x+2)^{-1/2}\) made it easier to apply the power rule directly. Simplification can involve:
- Converting roots to exponents.
- Reducing fractions to a simpler form.
- Expanding and rearranging terms.
Other exercises in this chapter
Problem 28
\(21-28\) Explain, using Theorems \(4,5,7,\) and \(9,\) why the function is continuous at every number in its domain. State the domain. \(H(x)=\cos \left(e^{\sq
View solution Problem 29
Find the derivative of the function using the definition of derivative. State the domain of the function and the domain of its derivative. \(f(x)=x^{4}\)
View solution Problem 29
Prove the statement using the \(\varepsilon, \delta\) definition of limit. \(\lim _{x \rightarrow 2}\left(x^{2}-4 x+5\right)=1\)
View solution Problem 29
15-36 Find the limit. $$ \lim _{x \rightarrow \infty} \frac{x+x^{3}+x^{5}}{1-x^{2}+x^{4}} $$
View solution