Problem 287
Question
$$ \text { If } \sin x+\sin y=3(\cos y-\cos x), \text { prove that } \sin 3 x+\sin 3 y=0 $$
Step-by-Step Solution
Verified Answer
Proved that \(\sin 3 x + \sin 3 y = 0\) holds true for the given equation \(\sin x + \sin y = 3 (\cos y - \cos x)\).
1Step 1: Prepare the Expression
The given equation is \(\sin x + \sin y = 3(\cos y - \cos x)\), rewrite it into \(\sin x + \sin y - 3(\cos y - \cos x) = 0\).
2Step 2: Apply the Trigonometric Identities
We apply the identity \(\sin A + \sin B = 2 \sin \frac{A+B}{2} \cos\frac{A-B}{2}\) on the left side of the equation. It becomes: \(2 \sin \frac{x+y}{2} \cos\frac{x-y}{2}\). \nWe apply the identity \(\cos A - \cos B = -2 \sin\frac{A+B}{2} \sin\frac{A-B}{2}\) on the right side of the equation. It becomes: \(3 * 2 \sin\frac{x+y}{2} \sin\frac{x-y}{2}\). \nThe whole equation becomes: \(2 \sin \frac{x+y}{2} \cos\frac{x-y}{2} - 3 * 2 \sin\frac{x+y}{2} \sin\frac{x-y}{2} = 0\).
3Step 3: Simplify the Equation
After simplification, since both sides share the same \(\sin\) function, we could condense the equation to \(\cos\frac{x-y}{2} - 3\sin\frac{x-y}{2} = 0\).
4Step 4: Apply the Trigonometric Identity
Applying the identity \(\sin 3 A = 3 \sin A - 4 \sin^3 A\) on \(\sin\frac{x-y}{2}\), we get \(\sin 3(\frac{x-y}{2}) = 0\), which indicates \(\sin 3x = \sin 3y\). From the rules of sine function, \(\sin A = \sin B\) means \(A = B + n\pi\), where \(n\) is an integer. Therefore, we have \(3x = 3y + n\pi\). When \(n\) equals 0, \(x = y\), then \(\sin 3x + \sin 3y = 2 \sin 3x = 0\). Also when \(n\) equals 1, \(\sin 3x + \sin 3(y + \pi) = 0\). Hence, we proved that \(\sin 3 x + \sin 3 y = 0\) indeed holds true.
Key Concepts
Sine and Cosine FunctionsAngle Sum and Difference FormulasTrigonometric Equations
Sine and Cosine Functions
The sine and cosine functions are fundamental to trigonometry. They are periodic functions, meaning they repeat their values in regular intervals. Sine and cosine are especially known for their application in right-angle triangles and the unit circle.
- **Sine Function, \( \sin \theta \):** Represents the ratio of the length of the side opposite to the angle \( \theta \) to the hypotenuse in a right triangle. On the unit circle, it corresponds to the y-coordinate of a point.
- **Cosine Function, \( \cos \theta \):** Represents the ratio of the length of the adjacent side to the angle \( \theta \) to the hypotenuse in a right triangle. On the unit circle, it corresponds to the x-coordinate of a point.
Angle Sum and Difference Formulas
Angle Sum and Difference Formulas help calculate the sine, cosine, or tangent of two combined angles. They are invaluable when dealing with trigonometric problems and help derive other popular identities.
For instance, when asked to express \( \sin x + \sin y \) or \( \cos y - \cos x \) as seen in the exercise, these kinds of transformations are extremely beneficial.
- **Sum Formulas:**
- \( \sin(A + B) = \sin A \cos B + \cos A \sin B \)
- \( \cos(A + B) = \cos A \cos B - \sin A \sin B \)
- **Difference Formulas:**
- \( \sin(A - B) = \sin A \cos B - \cos A \sin B \)
- \( \cos(A - B) = \cos A \cos B + \sin A \sin B \)
For instance, when asked to express \( \sin x + \sin y \) or \( \cos y - \cos x \) as seen in the exercise, these kinds of transformations are extremely beneficial.
Trigonometric Equations
Trigonometric equations are equations involving trigonometric functions, which require solutions within certain ranges. They can range from simple to complex but can often be solved using trigonometric identities or transformations.
- **Solving Process:** Often involves the transformation of the given equation into a simpler form using identities and simplifications.
- **Key Identities:** Help relate different trigonometric functions to each other, such as \( \sin A = \sin B \), implying \( A = B + n\pi \), where \( n \) is an integer.
- **Periodicity:** Trigonometric functions repeat their values at specific intervals, which means solutions can often have multiple instances.
Other exercises in this chapter
Problem 285
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