Problem 286
Question
For the following exercises, use a calculator to draw the region enclosed by the curve. Find the area \(M\) and the centroid \((\overline{x}, \overline{y})\) for the given shapes. Use symmetry to help locate the center of mass whenever possible. Triangle: \(y=x, \quad y=2-x,\) and \(y=0\)
Step-by-Step Solution
Verified Answer
Area \(M = 1\), Centroid \((\overline{x}, \overline{y}) = (1, \frac{1}{3})\).
1Step 1: Identify the region
The given lines are \(y = x\), \(y = 2-x\), and \(y = 0\). These lines form a triangle in the xy-plane. The points of intersection can be found as \((0,0)\), \((1,1)\), and \((2,0)\). Thus, the triangle is bounded by these vertices.
2Step 2: Draw the region
Using a graphing calculator or plotting software, graph the lines \(y = x\), \(y = 2-x\), and \(y = 0\). Shade the triangular region bounded by these lines. This region is a right triangle with vertices at \((0,0)\), \((1,1)\), and \((2,0)\).
3Step 3: Calculate the area of the triangle
The area \(M\) of a triangle with vertices \((x_1, y_1)\), \((x_2, y_2)\), and \((x_3, y_3)\) can be calculated using the formula:\[ M = \frac{1}{2} |x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2)| \]Substituting the vertices \((0,0)\), \((1,1)\), and \((2,0)\), we get:\[ M = \frac{1}{2} |0(1-0) + 1(0-0) + 2(0-1)| = \frac{1}{2} |0 + 0 - 2| = \frac{1}{2} \times 2 = 1 \]
4Step 4: Find the centroid \(\overline{x}\)
The centroid \((\overline{x}, \overline{y})\) of a triangle with vertices \((x_1, y_1)\), \((x_2, y_2)\), and \((x_3, y_3)\) is given by:\[ \overline{x} = \frac{x_1 + x_2 + x_3}{3}, \overline{y} = \frac{y_1 + y_2 + y_3}{3} \]Substituting the vertices \((0,0)\), \((1,1)\), and \((2,0)\), we get:\[ \overline{x} = \frac{0 + 1 + 2}{3} = \frac{3}{3} = 1 \]
5Step 5: Find the centroid \(\overline{y}\)
Using the same formula for the y-coordinate:\[ \overline{y} = \frac{0 + 1 + 0}{3} = \frac{1}{3} \]
6Step 6: Use symmetry to verify centroid
The triangle is symmetric about the line \(x=1\). The calculated centroid \((1, \frac{1}{3})\) lies on this line, confirming that the calculations were done correctly, and the center of mass is at the centroid due to symmetry.
Key Concepts
Area of a TriangleCoordinate GeometrySymmetry in Geometry
Area of a Triangle
The area of a triangle can be easily found if you know its vertices. This is particularly handy in coordinate geometry. To find the area from the coordinates, there's a straightforward formula. It's:\[ M = \frac{1}{2} |x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2)| \]Here, \(x_1, y_1\), \(x_2, y_2\), and \(x_3, y_3\) are the coordinates of the vertices.
- First, plug in your known vertex values.
- Perform the calculations inside the absolute value function first.
- Then divide the result by 2.
- This gives you the area, and remember: areas are always positive!
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, allows the representation of geometric figures in a numerical context. This approach is powerful for solving problems involving shapes on a coordinate plane. You can analyze various properties using coordinate geometry:
- Find intersections of lines by solving equations.
- Calculate distances between points using the distance formula.
- Determine slopes of lines for parallelism or perpendicularity.
- Utilize formulas to find midpoints or centroids, like with triangles.
Symmetry in Geometry
Symmetry in geometry means a shape looks the same even after certain transformations like reflection or rotation. Symmetry can offer shortcuts in solving geometry problems by reducing complex situations into simpler ones. Consider the triangle in the example:
- This triangle is symmetrical about the line \(x=1\), meaning it's mirrored across this line.
- The symmetry helps ensure that the centroid appears correctly balanced around the midpoint of this line.
- Due to symmetry, you can often use the geometrical balance to guess or verify results like centroids before computation.
Other exercises in this chapter
Problem 284
A sphere created by rotating a semicircle with radius \(a\) around the \(y\) -axis. Does your answer agree with the volume of a sphere?
View solution Problem 285
For the following exercises, use a calculator to draw the region enclosed by the curve. Find the area \(M\) and the centroid \((\overline{x}, \overline{y})\) fo
View solution Problem 287
For the following exercises, use a calculator to draw the region enclosed by the curve. Find the area \(M\) and the centroid \((\overline{x}, \overline{y})\) fo
View solution Problem 288
For the following exercises, use a calculator to draw the region enclosed by the curve. Find the area \(M\) and the centroid \((\overline{x}, \overline{y})\) fo
View solution