Problem 28
Question
\(x=0\) is a regular singular point of the given differential equation. Show that the indicial roots of the singularity differ by an integer. Use the method of Frobenius to obtain at least one series solution about \(x=0 .\) Use \((21)\) where necessary and a CAS, if instructed, to find a second solution. Form the general solution on the interval \((0, \infty)\). $$ y^{\prime \prime}+\frac{3}{x} y^{\prime}-2 y=0 $$
Step-by-Step Solution
Verified Answer
The roots are \( r = -1 \pm \sqrt{3} \), differing by a nontrivial integer.
1Step 1: Identify the Equation Type
The given differential equation is of the form \( y'' + \frac{P(x)}{x} y' + \frac{Q(x)}{x^2} y = 0 \) with \( P(x) = 3 \) and \( Q(x) = -2x^2 \). This classifies the equation as a regular singular point at \( x = 0 \).
2Step 2: Set Up the Indicial Equation
The indicial equation is derived from the lowest power of the series solution at the singular point. For the differential equation in the form \( x^2 y'' + x P(x) y' + Q(x) y = 0 \), the indicial equation is \( r(r-1) + rP_0 + Q_0 = 0 \), where \( P_0 = 3 \) and \( Q_0 = 2 \).
3Step 3: Solve the Indicial Equation
Substitute \( P_0 = 3 \) and \( Q_0 = -2 \) into the indicial equation: \( r(r-1) + 3r - 2 = 0 \). Simplify to find \( r^2 + 2r - 2 = 0 \).
4Step 4: Find the Indicial Roots
Solve the quadratic equation \( r^2 + 2r - 2 = 0 \) using the quadratic formula: \( r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) where \( a = 1, b = 2, c = -2 \). This results in \( r = -1 \pm \sqrt{3} \). The roots differ by an integer.
5Step 5: Form the Frobenius Solution
Since the roots differ by an integer, use the larger root \( r = -1 + \sqrt{3} \) to construct the series solution \( y_1(x) = \sum_{n=0}^{\infty} a_n x^{n+r} \). Substitute into the differential equation and solve for the coefficients \( a_n \).
6Step 6: Use a CAS for Second Solution
The second solution can be found using a Computer Algebra System (CAS) because the roots do not have a simple integer difference. The CAS uses the first solution \( y_1(x) \) and generates \( y_2(x) \) using variation of parameters.
7Step 7: Form the General Solution
Combine both series solutions to form the general solution: \( y(x) = c_1 y_1(x) + c_2 y_2(x) \), which is valid on the interval \((0, \infty)\).
Key Concepts
Indicial EquationSeries SolutionDifferential EquationsRegular Singular Point
Indicial Equation
When dealing with differential equations at a singular point, especially using the Frobenius method, we encounter the indicial equation. This is a key step that helps us determine the nature of solutions near a singularity. In the context of a differential equation, the indicial equation is derived from the substitution of a power series into the equation's lowest power term.
For example, consider a differential equation of the form:
For example, consider a differential equation of the form:
- \[ y'' + \frac{P(x)}{x} y' + \frac{Q(x)}{x^2} y = 0 \]
Series Solution
The series solution method involves assuming a solution in the form of a power series, expanding the function around a point. This method is especially useful for solving linear differential equations with variable coefficients. In these cases, solutions are often not expressed in terms of elementary functions. Instead, they can be written more naturally with series solutions.
In the Frobenius method, after solving the indicial equation, we use the leading root \(r\) as the starting point for our series. The solution generally looks like:
In the Frobenius method, after solving the indicial equation, we use the leading root \(r\) as the starting point for our series. The solution generally looks like:
- \[ y(x) = \sum_{n=0}^{\infty} a_n x^{n+r} \]
Differential Equations
Differential equations are mathematical equations involving derivatives, which represent how a quantity changes. They are fundamental in expressing laws of various fields such as physics, engineering, and economics. There are different types of differential equations, such as ordinary, partial, linear, or nonlinear.
A second-order linear differential equation, like the one in this exercise, takes the form:
A second-order linear differential equation, like the one in this exercise, takes the form:
- \[ y'' + P(x) y' + Q(x) y = 0 \]
Regular Singular Point
A regular singular point is a specific type of singularity in differential equations. At these points, solutions might become infinite, or certain expressions might become undefined. However, they provide more manageable behavior than irregular singular points.
An equation of the standard form:
An equation of the standard form:
- \[ x^2 y'' + x P(x) y' + Q(x) y = 0 \]
Other exercises in this chapter
Problem 27
In Problems \(17-28\), find two power series solutions of the given differential equation about the ordinary point \(x=0\). $$ \left(x^{2}+2\right) y^{\prime \p
View solution Problem 27
Find two power series solutions of the given differential equation about the ordinary point \(x=0\). $$ \left(x^{2}+2\right) y^{\prime \prime}+3 x y^{\prime}-y=
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In Problems \(17-28\), find two power series solutions of the given differential equation about the ordinary point \(x=0\). $$ \left(x^{2}-1\right) y^{\prime \p
View solution Problem 29
\(x=0\) is a regular singular point of the given differential equation. Show that the indicial roots of the singularity differ by an integer. Use the method of
View solution