Problem 28
Question
Write each complex number in rectangular form. $$ 2 e^{i \frac{5 \pi}{6}} $$
Step-by-Step Solution
Verified Answer
-\sqrt{3} + i
1Step 1: Identify the polar form components
The complex number is given in the polar form as \(2 e^{i \frac{5 \pi}{6}} \). Here, the magnitude (or modulus) is \(r = 2\) and the argument (or angle) is \(\theta = \frac{5 \pi}{6}\).
2Step 2: Use Euler's formula
According to Euler's formula, \( e^{i \theta} = \cos \theta + i \sin \theta\). Substitute \(\theta = \frac{5 \pi}{6}\) into Euler's formula so that \( e^{i \frac{5 \pi}{6}} = \cos \left(\frac{5 \pi}{6}\right) + i \sin \left(\frac{5 \pi}{6}\right) \).
3Step 3: Calculate the cosine component
Find \( \cos \left( \frac{5 \pi}{6} \right) \). Using the unit circle, \( \cos \left( \frac{5 \pi}{6} \right) = -\frac{\sqrt{3}}{2} \).
4Step 4: Calculate the sine component
Find \( \sin \left( \frac{5 \pi}{6} \right) \). Using the unit circle, \( \sin \left( \frac{5 \pi}{6} \right) = \frac{1}{2} \).
5Step 5: Combine magnitudes and components
Multiply the magnitude \(r = 2\) by the rectangular components \( 2 \left( -\frac{\sqrt{3}}{2} + i \frac{1}{2} \right) \).
6Step 6: Simplify to rectangular form
Distribute the 2 to get: \( 2 \left( -\frac{\sqrt{3}}{2} \right) + 2i \left( \frac{1}{2} \right) = -\sqrt{3} + i \). Thus, the rectangular form is \( -\sqrt{3} + i \).
Key Concepts
Polar formEuler's formulaUnit circle
Polar form
When dealing with complex numbers, you will often see them in two main forms. One of these is the polar form. The polar form expresses a complex number as \( r e^{i \theta} \), where \( r \) is the magnitude (or modulus) and \( \theta \) is the argument (or angle). Here is the step-by-step to understand and utilize it:
- The magnitude \( r \) represents the distance from the origin to the point in the complex plane.
- The angle \( \theta \) represents the direction of the line connecting the origin to the point.
In the exercise, the complex number is given as \( 2 e^{i \frac{5 \pi}{6}} \). This means the magnitude is 2 and the angle is \( \frac{5 \pi}{6} \).
The polar form allows for easy multiplication and division of complex numbers. However, to perform addition or subtraction, you will often need to convert the polar form into the rectangular form.
- The magnitude \( r \) represents the distance from the origin to the point in the complex plane.
- The angle \( \theta \) represents the direction of the line connecting the origin to the point.
In the exercise, the complex number is given as \( 2 e^{i \frac{5 \pi}{6}} \). This means the magnitude is 2 and the angle is \( \frac{5 \pi}{6} \).
The polar form allows for easy multiplication and division of complex numbers. However, to perform addition or subtraction, you will often need to convert the polar form into the rectangular form.
Euler's formula
Euler's formula is integral when working with complex numbers in polar form. The formula states: \( e^{i \theta} = \cos \theta + i \sin \theta \). This formula links exponential functions to trigonometric functions. For example, in our exercise, to convert the polar form \( 2 e^{i \frac{5 \pi}{6}} \) into rectangular form, we leverage Euler's formula:
- Substitute \( \theta = \frac{5 \pi}{6} \) so we have \( e^{i \frac{5 \pi}{6}} = \cos \left(\frac{5 \pi}{6}\right) + i \sin \left(\frac{5 \pi}{6}\right) \). This converts the exponential to trigonometric form, making it easier to work with.
- Substitute \( \theta = \frac{5 \pi}{6} \) so we have \( e^{i \frac{5 \pi}{6}} = \cos \left(\frac{5 \pi}{6}\right) + i \sin \left(\frac{5 \pi}{6}\right) \). This converts the exponential to trigonometric form, making it easier to work with.
Unit circle
The unit circle is a crucial concept in trigonometry and complex numbers. It's a circle with a radius of 1 centered at the origin of the coordinate plane. The unit circle allows us to find the sine and cosine of any angle. For the exercise:
- To find \( \cos \left( \frac{5 \pi}{6} \right) \), we refer to the unit circle and see that \( \cos \left( \frac{5 \pi}{6} \right) = -\frac{\sqrt{3}}{2} \).
- Similarly, for \( \sin \left( \frac{5 \pi}{6} \right) \), we find \( \sin \left( \frac{5 \pi}{6} \right) = \frac{1}{2} \).
Using these values, we substitute back into Euler's formula and then multiply by the magnitude 2 to find our rectangular components. This crucial step simplifies the process of converting from polar to rectangular form.
- To find \( \cos \left( \frac{5 \pi}{6} \right) \), we refer to the unit circle and see that \( \cos \left( \frac{5 \pi}{6} \right) = -\frac{\sqrt{3}}{2} \).
- Similarly, for \( \sin \left( \frac{5 \pi}{6} \right) \), we find \( \sin \left( \frac{5 \pi}{6} \right) = \frac{1}{2} \).
Using these values, we substitute back into Euler's formula and then multiply by the magnitude 2 to find our rectangular components. This crucial step simplifies the process of converting from polar to rectangular form.
Other exercises in this chapter
Problem 28
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The vector \(\mathbf{v}\) has initial point \(P\) and terminal point \(Q .\) Find its position vector. That is, express \(\mathbf{v}\) in the form \(a \mathbf{i
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Plot each point given in polar coordinates. $$ \left(-3, \frac{2 \pi}{3}\right) $$
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Transform each polar equation to an equation in rectangular coordinates. Then identify and graph the equation. $$ r \csc \theta=8 $$
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