Problem 28
Question
Write each as a single logarithm. Assume that variables represent positive numbers. $$ 2 \log _{7} y+6 \log _{7} z $$
Step-by-Step Solution
Verified Answer
\( \log_7 (y^2 \cdot z^6) \)
1Step 1: Apply the Power Rule
The power rule of logarithms states that \( a \log_b x = \log_b (x^a) \). Apply this rule separately to each term. - For the first term: \( 2 \log_7 y = \log_7 (y^2) \).- For the second term: \( 6 \log_7 z = \log_7 (z^6) \).
2Step 2: Apply the Product Rule
The product rule of logarithms states that \( \log_b x + \log_b y = \log_b (xy) \). Now, applying this rule to the results from Step 1:- Combine \( \log_7 (y^2) + \log_7 (z^6) \) into a single logarithm: \( \log_7 (y^2 \cdot z^6) \).
Key Concepts
Power Rule of LogarithmsProduct Rule of LogarithmsProperties of Logarithms
Power Rule of Logarithms
The power rule of logarithms is quite straightforward but incredibly powerful. It allows you to bring down the exponent of a number in your logarithmic expression. This rule states:
This rule is particularly handy when you deal with products or quotients of logarithms, as it sets up your equation to apply other logarithmic rules.
For every coefficient in front of a logarithm, think of it in terms of an exponent inside the logarithm. Remember, this only works because logarithms are exponents, so you can manipulate them in similar ways.
- \( a \log_b x = \log_b (x^a) \).
This rule is particularly handy when you deal with products or quotients of logarithms, as it sets up your equation to apply other logarithmic rules.
For every coefficient in front of a logarithm, think of it in terms of an exponent inside the logarithm. Remember, this only works because logarithms are exponents, so you can manipulate them in similar ways.
Product Rule of Logarithms
When working with multiple logarithmic expressions added together, the product rule of logarithms comes to the rescue. According to this rule:
This is especially useful because having a single log expression is often much simpler to manipulate.
Using this rule helps combine terms efficiently and helps in solving more complex logarithmic equations without getting overwhelmed with too many individual pieces.
- \( \log_b x + \log_b y = \log_b (xy) \).
This is especially useful because having a single log expression is often much simpler to manipulate.
Using this rule helps combine terms efficiently and helps in solving more complex logarithmic equations without getting overwhelmed with too many individual pieces.
Properties of Logarithms
Understanding the key properties of logarithms is crucial when learning how to simplify logarithmic expressions. Here are some of the important properties:
Being familiar with them gives you more flexibility in simplifying and solving complex problems, making the expression easier to work with.
Each property opens up new ways to approach and solve log-related questions by transforming the expression into a more manageable form.
- **Product Property:** \( \log_b (xy) = \log_b x + \log_b y \).
- **Quotient Property:** \( \log_b \left(\frac{x}{y}\right) = \log_b x - \log_b y \).
- **Power Property:** \( \log_b (x^a) = a \log_b x \).
- **Change of Base Formula:** \( \log_b (x) = \frac{\log_k (x)}{\log_k (b)} \). You can use this to change the base of a logarithm.
Being familiar with them gives you more flexibility in simplifying and solving complex problems, making the expression easier to work with.
Each property opens up new ways to approach and solve log-related questions by transforming the expression into a more manageable form.
Other exercises in this chapter
Problem 28
Each of the following functions is one-to-one. Find the inverse of each function and graph the function and its inverse on the same set of axes. $$ f(x)=-\frac{
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Solve. $$ \frac{1}{27}=3^{2 x} $$
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Solve each equation. $$ \log _{2} x+\log _{2}(3 x+1)=1 $$
View solution Problem 29
Find the value of each logarithmic expression. $$ \log _{2} 8 $$
View solution