Problem 28
Question
Write an equation of an ellipse for the given foci and co-vertices. foci \((0, \pm 8),\) co-vertices \(( \pm 8,0)\)
Step-by-Step Solution
Verified Answer
The equation of the ellipse given the foci at (0,±8) and co-vertices at (±8,0) is \(\frac{x^2}{128} + \frac{y^2}{64} = 1\).
1Step 1: Identify the coordinates of foci and co-vertices
The foci are at coordinates (0,±8) and the co-vertices are at (±8,0). This suggests that the center of the ellipse is at the origin (0,0).
2Step 2: Calculate the distances 'b' and 'c'
The distance 'c' from the center to each focus is 8 (the y-coordinate of the foci) and the distance 'b' to each co-vertex is also 8 (the x-coordinate of the co-vertices).
3Step 3: Compute for 'a'
By definition, in an ellipse, \(a^2 = b^2 + c^2\). Substituting the values of 'b' and 'c' into the equation: \(a^2 = 8^2 + 8^2 = 128\). So, 'a' is \( \sqrt{128} = 8\sqrt{2}\).
4Step 4: Write the equation of the ellipse
The standard equation of an ellipse with center at the origin in the coordinate plane is \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\). Substituting our values for 'a' and 'b', the equation of the ellipse is \(\frac{x^2}{128} + \frac{y^2}{64} = 1\).
Key Concepts
Foci of EllipseCo-Vertices of EllipseStandard Form of Ellipse Equation
Foci of Ellipse
The foci of an ellipse are two points located inside the ellipse. They play a crucial role in its geometric definition. Let's explore what makes them special. The foci are a fundamental aspect because the sum of the distances from any point on the ellipse to each focus is constant. This is the key defining property of an ellipse. In our given example, the foci are at
- (0, 8)
- (0, -8)
Co-Vertices of Ellipse
Co-vertices are another important aspect when discussing ellipses. These are the points where the ellipse intersects its minor axis. The ellipse is symmetrical about both the x-axis and y-axis, as illustrated by its co-vertices
- (8, 0)
- (-8, 0)
Standard Form of Ellipse Equation
The equation of an ellipse in its standard form helps us represent the curve algebraically. The standard form of an ellipse centered at the origin \[ (0, 0) \] is \[ \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \] Here, 'a' represents the semi-major axis' length whereas 'b' is the length of the semi-minor axis. These axes are the longest and shortest diameters respectively. Calculating 'a' and 'b' is essential for setting up this equation. Given 'b'=8 and 'c'=8, we calculated 'a' using \[ a^2 = b^2 + c^2 \] resulting in \[ a^2 = 128 \] and thus \[ a = 8\sqrt{2} \]. Thus, the equation \[ \frac{x^2}{128} + \frac{y^2}{64} = 1 \] describes our ellipse. Understanding this formula allows us to graph and analyze ellipses in various contexts more effectively.
Other exercises in this chapter
Problem 27
Use the center and the radius to graph each circle. $$ (x+9)^{2}+(y+2)^{2}=100 $$
View solution Problem 27
Identify the vertex, the focus, and the directrix of each graph. Then sketch the graph. $$ y^{2}-25 x=0 $$
View solution Problem 28
Campbell claims that \(\frac{x^{2}}{10}+\frac{y^{2}}{10}=1\) represents an ellipse. Monique disagrees. Whom do you support? Give a reasoned argument.
View solution Problem 28
Graph each equation. $$ 16 x^{2}-20 y^{2}=560 $$
View solution