Problem 28
Question
Which is the stronger of the following two acids? (a) acetic acid, \(\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}, K_{\mathrm{a}}=1.8 \times 10^{-5}\) (b) chloroacetic acid, \(\mathrm{ClCH}_{2} \mathrm{CO}_{2} \mathrm{H}, \mathrm{p} K_{\mathrm{a}}=2.87\)
Step-by-Step Solution
Verified Answer
Chloroacetic acid is the stronger acid.
1Step 1: Understand Acid Strength
The strength of an acid is determined by its dissociation constant, \( K_a \). A larger \( K_a \) value means a stronger acid, as it dissociates more in solution.
2Step 2: Convert pKa to Ka for Chloroacetic Acid
Given \( \mathrm{p}K_a = 2.87 \) for chloroacetic acid, convert it to \( K_a \) using the formula: \( K_a = 10^{-\mathrm{p}K_a} \).\[ K_a = 10^{-2.87} \approx 1.35 \times 10^{-3} \]
3Step 3: Compare Ka Values
Compare the \( K_a \) values of both acids. - Acetic acid: \( K_a = 1.8 \times 10^{-5} \)- Chloroacetic acid: \( K_a = 1.35 \times 10^{-3} \)
4Step 4: Determine the Stronger Acid
Since \( 1.35 \times 10^{-3} \) (chloroacetic acid's \( K_a \)) is greater than \( 1.8 \times 10^{-5} \) (acetic acid's \( K_a \)), chloroacetic acid is the stronger acid.
Key Concepts
Dissociation ConstantpKa to Ka ConversionComparison of Ka Values
Dissociation Constant
The dissociation constant, often represented as \( K_a \), plays a crucial role when discussing acid strength. It helps us understand how well an acid dissociates in water. Essentially, \( K_a \) is a measure of the ionization of the acid in solution. The higher the \( K_a \) value, the more the acid ionizes, and consequently, the stronger the acid.
- Acids with higher \( K_a \) values dissociate more completely in water.
- This leads to a greater production of hydronium ions \( (H_3O^+) \), indicating stronger acidity.
pKa to Ka Conversion
The dissociation constant \( K_a \) can also be expressed in a logarithmic form known as \( \text{p}K_a \). This form is often more manageable because it deals with smaller numbers. However, when comparing acid strength, we need the \( K_a \) values. That's where conversion comes into play.The relationship between \( \text{p}K_a \) and \( K_a \) is given by the formula: \[ K_a = 10^{-\text{p}K_a} \]This transformation is vital for accurately assessing and comparing the strengths of different acids. For example, if chloroacetic acid has a \( \text{p}K_a \) of 2.87, we calculate \( K_a \) as follows:
- First, apply the formula: \( K_a = 10^{-2.87} \)
- Adjusting the numbers gives us \( K_a \approx 1.35 \times 10^{-3} \)
Comparison of Ka Values
Once we've determined the \( K_a \) values of different acids, the next step is to compare these values to identify the stronger acid. This process is straightforward but crucial to understanding acid strength.Here’s how it works:
- Acetic acid has a \( K_a \) of \( 1.8 \times 10^{-5} \).
- Chloroacetic acid, after conversion, has a \( K_a \) of \( 1.35 \times 10^{-3} \).
- The larger the \( K_a \), the stronger the acid.
- Here, \( 1.35 \times 10^{-3} \) is significantly larger than \( 1.8 \times 10^{-5} \).
- Thus, chloroacetic acid is the stronger acid between the two.
Other exercises in this chapter
Problem 24
If \(K_{\mathrm{a}}\) for a weak acid is \(2.4 \times 10^{-11},\) what is the value of \(\mathrm{p} K_{\mathrm{a}} ?\)
View solution Problem 27
Which is the stronger of the following two acids? (a) benzoic acid, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2} \mathrm{H}, \mathrm{p} K_{\mathrm{a}}=4.20\)
View solution Problem 29
Chloroacetic acid \(\left(\mathrm{ClCH}_{2} \mathrm{CO}_{2} \mathrm{H}\right)\) has \(K_{\mathrm{a}}=1.36 \times 10^{-3}\).What is the value of \(K_{b}\) for th
View solution Problem 30
A weak base has \(K_{b}=1.5 \times 10^{-9} .\) What is the value of \(K_{a}\) for the conjugate acid?
View solution