Problem 28
Question
Use the Intermediate Value Theorem to approximate the zero of \(f\) in the interval \([a, b]\). Give your approximation to the nearest tenth. (If you have a graphing utility, use it to help you approximate the zero.) $$f(x)=x^{5}+x+1, \quad[-1,0]$$
Step-by-Step Solution
Verified Answer
The approximate zero of the function is ~-0.8.
1Step 1: Evaluate the function at the endpoints
First calculate the value of the function at the endpoints of the interval, -1 and 0. So you find \(f(-1)\) and \(f(0)\). If \(f(-1) = (-1)^{5}+(-1)+1 = -1\) and \(f(0) = (0)^{5}+(0)+1 = 1\).
2Step 2: Determine if 0 falls between the function's values
In step 1, it was found that the function takes the values -1 and 1 at the endpoints of the interval. Zero does indeed fall between these two values, therefore, according to the Intermediate Value Theorem, the function must take a value of 0 at some point within the interval [-1,0].
3Step 3: Approximate the zero of the function
The zero of the function lies somewhere between -1 and 0. Given this is a fifth degree polynomial, the exact root might be complex to find algebraically. Therefore, the exercise suggests using a graphing utility or a method of approximation such as bisection to find the root to the nearest tenth, which is approximately -0.8.
Key Concepts
Function EvaluationPolynomialsRoot Approximation
Function Evaluation
Grasping the idea of function evaluation is like learning to peek into a function's behavior at specific points. Imagine a function as a magical box that does mathematical operations on any number you put in. Every function consists of an equation with variables, like our given function, which is a polynomial:
- The function is defined as \( f(x) = x^5 + x + 1 \).
- The remarkable part of evaluating is simply replacing the \( x \) with chosen values to calculate what comes out.
- At \( x = -1 \), the function gives \( -1 \).
- At \( x = 0 \), the output is \( 1 \).
Polynomials
Polynomials are a special type of mathematical expression consisting of variables and coefficients, and they exhibit fascinating behavior. When examining polynomials, especially those of a higher degree like fifth-degree ones, you're often delving into some intriguing patterns and results.
- The function we are discussing, \( f(x) = x^5 + x + 1 \), is a polynomial.
- It combines terms of varying powers of \( x \), which is typical of polynomial functions.
- A degree, which is the highest power of \( x \). Here, it is 5.
- Various roots, which are values where the polynomial equals zero.
Root Approximation
Finding the root of a polynomial symbolizes finding an \( x \)-value where the function touches or crosses the x-axis, and this problem can sometimes be complex. The Intermediate Value Theorem assists in figuring out where this happens, suggesting that if a function thermometer changes signs across an interval, a "zero" lies somewhere in between.
- According to the theorem, there is a change between negative \( f(-1) \) to positive \( f(0) \).
- Therefore, there must be a root in between these values.
- The problem recommends graphing or using numerical means like bisection to close in on this zero.
- Through such techniques, it's been approximated to be around \( -0.8 \), lending an insightful estimation without needing precise algebraic methods.
Other exercises in this chapter
Problem 28
Find all the zeros of the function and write the polynomial as a product of linear factors. $$g(x)=3 x^{3}-4 x^{2}+8 x+8$$
View solution Problem 28
Perform the indicated operation and write the result in standard form. $$(2-5 i)^{2}-(2+5 i)^{2}$$
View solution Problem 29
Use synthetic division to divide. Divisor \(x-4\) Dividend $$2 x^{5}-30 x^{3}-37 x+13$$
View solution Problem 29
Determine (a) the maximum number of turning points of the graph of the function and (b) the maximum number of real zeros of the function. $$f(x)=-x^{5}+x^{4}-x$
View solution