Problem 28
Question
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Passing through \((-2,0)\) and \((0,2)\)
Step-by-Step Solution
Verified Answer
The point-slope form is \(y - 0 = 1(x - (-2))\), which simplifies to \(y = x + 2\). The slope-intercept form is also \(y = x + 2\). Hence the line that passes through the points \((-2,0)\) and \((0,2)\) is described by the equation \(y = x + 2\).
1Step 1: Calculation of Slope
Use the given points and the slope formula to find the slope, \(m\). Here, let's use the points, \((-2,0)\) and \((0,2)\). Then \(m = (2 - 0) / (0 - (-2)) = 2/2 = 1\)
2Step 2: Write the Point-Slope Form
Substitute the slope value and the coordinates of one of the points into the point slope form of the equation, which is \(y - y1 = m(x - x1)\) to obtain \(y - 0 =1(x - (-2))\), which simplifies to \(y = x + 2\)
3Step 3: Write the Slope-Intercept Form
The slope-intercept form of the equation can be obtained from the point-slope form by simplifying the equation. In this case, the slope-intercept form is already obtained \(y = x + 2\)
4Step 4: Check the Answer
Ensure that the equation is correct by testing if the second point \((0,2)\) satisfies the equation. Substituting \(x = 0\), the equation turns to \(y = 0 + 2\), which gives \(y = 2\). Since this matches the \(y\) coordinate of the second point, the equation is correct.
Other exercises in this chapter
Problem 28
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Find the domain of each function. $$g(x)=\frac{\sqrt{x-3}}{x-6}$$
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Determine whether each function is even, odd, or neither. $$f(x)=x \sqrt{1-x^{2}}$$
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find the midpoint of each line segment with the given endpoints. $$ (\sqrt{18},-4) \text { and }(\sqrt{2}, 4) $$
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