Problem 28
Question
Use the function to evaluate the indicated expressions and simplify. $$ f(x)=6 x-18 ; \quad f\left(\frac{x}{3}\right), \frac{f(x)}{3} $$
Step-by-Step Solution
Verified Answer
\( f\left(\frac{x}{3}\right) = 2x - 18 \); \( \frac{f(x)}{3} = 2x - 6 \).
1Step 1: Understanding the Function
The given function is \( f(x) = 6x - 18 \). This function is linear, with a slope of 6 and a y-intercept of -18.
2Step 2: Evaluate \( f\left(\frac{x}{3}\right) \)
To evaluate \( f\left(\frac{x}{3}\right) \), substitute \( \frac{x}{3} \) into the function. We start by replacing every \( x \) in \( f(x) \) with \( \frac{x}{3} \): \[ f\left(\frac{x}{3}\right) = 6\left(\frac{x}{3}\right) - 18 \] Simplify: \[ f\left(\frac{x}{3}\right) = 2x - 18 \]
3Step 3: Evaluate \( \frac{f(x)}{3} \)
Now, evaluate \( \frac{f(x)}{3} \) by dividing the entire function \( f(x) \) by 3: \[ \frac{f(x)}{3} = \frac{6x - 18}{3} \] Simplify each term: \[ \frac{6x}{3} - \frac{18}{3} = 2x - 6 \]
4Step 4: Simplified Expressions
The simplified expressions are: \( f\left(\frac{x}{3}\right) = 2x - 18 \) \( \frac{f(x)}{3} = 2x - 6 \) Both expressions have been computed correctly. The first expression shows how \( f \) changes when its argument is scaled, while the second shows the function when divided entirely by 3.
Key Concepts
Linear FunctionSubstitution in FunctionsSimplifying Expressions
Linear Function
A linear function is a type of function that creates a straight line when graphed on a coordinate plane. Linear functions have the general form \( f(x) = mx + b \).
Understanding these components will help us grasp how changing elements of the function affects its graph.
- \( m \) is the slope: It indicates how steep the line is and the direction it goes (up or down).
- \( b \) is the y-intercept: It is the point where the line crosses the y-axis.
Understanding these components will help us grasp how changing elements of the function affects its graph.
Substitution in Functions
Substitution in functions involves replacing the input variable \( x \) with another expression or value to determine the output. This process can help us observe how a function behaves under different conditions.
In our example, we are asked to find \( f\left(\frac{x}{3}\right) \) by substituting \( x \) with \( \frac{x}{3} \) into the original function \( f(x) = 6x - 18 \).
In our example, we are asked to find \( f\left(\frac{x}{3}\right) \) by substituting \( x \) with \( \frac{x}{3} \) into the original function \( f(x) = 6x - 18 \).
- Substitute: Replace \( x \) in the function with \( \frac{x}{3} \).
- Evaluate: The expression then becomes \( f\left(\frac{x}{3}\right) = 6\left(\frac{x}{3}\right) - 18 \).
- Simplify: Using arithmetic operations, simplify the expression to \( 2x - 18 \).
Simplifying Expressions
Simplifying expressions involves making them more concise while retaining their value. It often includes combining like terms or reducing fractions.
In our exercise, we first evaluate the expression \( f\left(\frac{x}{3}\right) \) which simplifies to \( 2x - 18 \). Then, we simplify \( \frac{f(x)}{3} \).
In our exercise, we first evaluate the expression \( f\left(\frac{x}{3}\right) \) which simplifies to \( 2x - 18 \). Then, we simplify \( \frac{f(x)}{3} \).
- Start with \( \frac{f(x)}{3} = \frac{6x - 18}{3} \): Dividing each term by 3.
- \( \frac{6x}{3} - \frac{18}{3} = 2x - 6 \): Simplify each term separately.
Other exercises in this chapter
Problem 28
Use the Inverse Function Property to show that \(f\) and \(g\) are inverses of each other. \(f(x)=x^{3}+1 ; \quad g(x)=(x-1)^{1 / 3}\)
View solution Problem 28
\(17-28\) A function is given. Determine the average rate of change of the function between the given values of the variable. $$ f(t)=\sqrt{t} ; \quad t=a, t=a+
View solution Problem 29
\(29-40\) Find the functions \(f \circ g, g \circ f, f \circ f,\) and \(g \circ g\) and their domains. $$ f(x)=2 x+3, \quad g(x)=4 x-1 $$
View solution Problem 29
\(29-38=\) Find the maximum or minimum value of the function. $$ f(x)=x^{2}+x+1 $$
View solution