Problem 28
Question
Use the center and the radius to graph each circle. $$ (x+4)^{2}+(y-4)^{2}=4 $$
Step-by-Step Solution
Verified Answer
The center of the circle is at point (-4,4) and the radius is 2. Plot these on a graph to draw the circle.
1Step 1: Identify Center and Radius
The equation given is \((x+4)^{2} +(y-4)^{2}=4\). Comparing to the standard form, it can be seen that \( h = -4 \), \( k = 4 \), and \( r = \sqrt{4} = 2 \). So, the center of the circle is (-4, 4) and the radius is 2.
2Step 2: Sketch the Center
Draw a pair of perpendicular axes on a graph. Plot the center of circle, which is at point (-4, 4). The center of the circle will be the reference point for drawing the circle.
3Step 3: Plot the Radius
From the center of the circle, measure 2 units in all directions which is the radius of the circle. Plot these points. These points will help in drawing an accurate circle.
4Step 4: Draw the Circle
Join all the points plotted in the previous step in a round shape which forms the circle. The points should be an equal distance from the center and this distance is equivalent to the radius of the circle.
Key Concepts
Circle EquationCenter and RadiusStandard Form of Circle Equation
Circle Equation
Understanding circle equations is key to graphing and analyzing circles in mathematics. A circle equation expresses the relationship between the points on a circle in terms of their coordinates.
When you encounter a circle equation like \((x+4)^2 + (y-4)^2 = 4\), it tells you about all the points \((x, y)\) that lie on the circle with a specific center and radius.
When you encounter a circle equation like \((x+4)^2 + (y-4)^2 = 4\), it tells you about all the points \((x, y)\) that lie on the circle with a specific center and radius.
- The expression \((x+4)^2\) indicates a horizontal shift from the origin, while \((y-4)^2\) indicates a vertical shift.
- The right side of the equation, \(4\), represents the square of the radius of the circle.
Center and Radius
The center and radius are essential components in defining a circle's shape and size. To extract these from an equation, use the standard form of the circle equation.
Here, the equation \((x+4)^2 + (y-4)^2 = 4\) leads you to identify:
Here, the equation \((x+4)^2 + (y-4)^2 = 4\) leads you to identify:
- Center: Represented by the coordinates \((h, k)\), in this case (-4, 4). This means the circle is centered 4 units left and 4 units up from the origin.
- Radius: Found by taking the square root of the radius squared (\(r^2\)). With \(r^2 = 4\), the radius \(r = 2\).
Standard Form of Circle Equation
The standard form of a circle equation is fundamental to understanding and utilizing circle equations in graphing.
The general format is \((x-h)^2 + (y-k)^2 = r^2\), where:
By comparing a given equation to the standard form, such as \((x+4)^2 + (y-4)^2 = 4\):
The general format is \((x-h)^2 + (y-k)^2 = r^2\), where:
- \((h, k)\) is the center of a circle.
- \(r\) is the radius.
By comparing a given equation to the standard form, such as \((x+4)^2 + (y-4)^2 = 4\):
- Identify \(h = -4\) and \(k = 4\) for the circle's center.
- Calculate the radius \(r = \sqrt{4} = 2\).
Other exercises in this chapter
Problem 28
Campbell claims that \(\frac{x^{2}}{10}+\frac{y^{2}}{10}=1\) represents an ellipse. Monique disagrees. Whom do you support? Give a reasoned argument.
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Graph each equation. $$ 16 x^{2}-20 y^{2}=560 $$
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$$ x^{2}=4 y $$
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Write an equation of an ellipse for the given foci and co-vertices. foci \(( \pm 5,0),\) co-vertices \((0, \pm 8)\)
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