Problem 28
Question
The polynomial \(f(x)=x^{3}-i x^{2}+2 i x+2\) has the complex number \(i\) as a zero; however, the conjugate \(-i\) of \(i\) is not a zero. Why doesn't this result contradict the theorem on conjugate pair zeros of a polynomial?
Step-by-Step Solution
Verified Answer
The polynomial has imaginary coefficients, so the theorem doesn't apply.
1Step 1: Identify the Theorem
The theorem on conjugate pair zeros states that if a polynomial with real coefficients has a complex zero, then its complex conjugate must also be a zero.
2Step 2: Analyze Polynomial Coefficients
Examine the polynomial given: \(f(x) = x^{3} - i x^{2} + 2 i x + 2 \). Notice the coefficients are not all real; they include imaginary components, such as \(-i\) for \(x^{2}\) and \(2i\) for \(x\).
3Step 3: Check Validity of Theorem
As the coefficients are not entirely real, the theorem does not apply. This is because the theorem specifically applies only to polynomials with real coefficients.
Key Concepts
Complex NumbersPolynomials with Complex CoefficientsTheorem on Complex Conjugates
Complex Numbers
Complex numbers are numbers that include both a real and an imaginary part. The standard form of a complex number is written as \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part. The imaginary unit is denoted as \(i\), and it is defined by the property \(i^2 = -1\).
Complex numbers allow for the extension of real numbers, providing solutions to equations that have no solutions in the real number system. For example, the equation \(x^2 + 1 = 0\) has no real solution because no real number squared results in \(-1\). However, with complex numbers, the solution is \(x = i\) or \(x = -i\).
Understanding complex numbers is crucial since they enable a comprehensive approach to solving polynomial equations, which often arise in advanced mathematics and engineering fields. Complex numbers encompass both broadening our understanding of algebraic structures and enhancing our problem-solving toolkit.
Complex numbers allow for the extension of real numbers, providing solutions to equations that have no solutions in the real number system. For example, the equation \(x^2 + 1 = 0\) has no real solution because no real number squared results in \(-1\). However, with complex numbers, the solution is \(x = i\) or \(x = -i\).
Understanding complex numbers is crucial since they enable a comprehensive approach to solving polynomial equations, which often arise in advanced mathematics and engineering fields. Complex numbers encompass both broadening our understanding of algebraic structures and enhancing our problem-solving toolkit.
Polynomials with Complex Coefficients
Polynomials can have complex coefficients, meaning that their coefficients are complex numbers rather than strictly real numbers. For example, consider the polynomial \(f(x) = x^3 - ix^2 + 2ix + 2\). In this polynomial, the coefficients of \(x^2\) and \(x\) are complex, specifically \(-i\) and \(2i\) respectively.
When dealing with polynomials with complex coefficients, typical rules that apply to polynomials with real coefficients might not hold. One such rule is the Conjugate Pair Zeros Theorem, which has specific conditions. In this case, since the coefficients include imaginary parts, some of the constraints or theorems that typically apply to traditional polynomials need to be reconsidered.
When dealing with polynomials with complex coefficients, typical rules that apply to polynomials with real coefficients might not hold. One such rule is the Conjugate Pair Zeros Theorem, which has specific conditions. In this case, since the coefficients include imaginary parts, some of the constraints or theorems that typically apply to traditional polynomials need to be reconsidered.
- It's important to always examine the nature of polynomial coefficients before applying specific theorems.
- The presence of complex coefficients implies that different mathematical properties might be at play.
Theorem on Complex Conjugates
The theorem on complex conjugates, often referred to as the Conjugate Pair Zeros Theorem, is a fundamental concept in algebra. This theorem states that if a polynomial has real coefficients and one of its zeros is a complex number, then its conjugate must also be a zero. The complex conjugate of a complex number \(a + bi\) is \(a - bi\).
In the context of the given exercise, the polynomial \(f(x) = x^3 - ix^2 + 2ix + 2\) doesn't contradict this theorem because it does not meet the initial condition of having all real coefficients. Since the coefficients are complex, the theorem's requirement isn't satisfied, thereby ensuring there's no contradiction.
This theorem helps in understanding the symmetry that occurs in polynomials with real coefficients when complex numbers are involved. However, it clearly stipulates the need for real coefficients as an essential condition. This is why, in situations like the exercise, understanding the applicable conditions of a theorem is vital to correctly applying it and avoiding misinterpretations.
In the context of the given exercise, the polynomial \(f(x) = x^3 - ix^2 + 2ix + 2\) doesn't contradict this theorem because it does not meet the initial condition of having all real coefficients. Since the coefficients are complex, the theorem's requirement isn't satisfied, thereby ensuring there's no contradiction.
This theorem helps in understanding the symmetry that occurs in polynomials with real coefficients when complex numbers are involved. However, it clearly stipulates the need for real coefficients as an essential condition. This is why, in situations like the exercise, understanding the applicable conditions of a theorem is vital to correctly applying it and avoiding misinterpretations.
Other exercises in this chapter
Problem 27
Does there exist a polynomial of degree 3 with real coefficients that has zeros \(1,-1\), and \(i\) ? Justify your answer.
View solution Problem 28
Sketch the graph of \(f\). $$ f(x)=\frac{2 x^{2}+8 x+6}{x^{2}-2 x} $$
View solution Problem 29
A thin flat plate is situated in an \(x y\)-plane such that the density \(d\) (in \(\mathrm{lb} / \mathrm{ft}^{2}\) ) at the point \(P(x, y)\) is inversely prop
View solution Problem 29
If \(n\) is an odd positive integer, prove that a polynomial of degree \(n\) with real coefficients has at least one real zero.
View solution