Problem 28
Question
The frustum of a regular pyramid has square bases, one \(4.83 \mathrm{mm}\) on a side and the other \(2.84 \mathrm{mm}\) on a side. Its altitude is \(3.88 \mathrm{mm} .\) Find its volume and lateral area.
Step-by-Step Solution
Verified Answer
The volume of the frustum is approximately 58.00 mm^3 and the lateral area is approximately 61.21 mm^2.
1Step 1: Calculating the Volume of the Frustum
To find the volume of the frustum, use the formula: \[V = \frac{1}{3}h(a^2 + ab + b^2)\] where \(h\) is the altitude, \(a\) is the side of the larger base, and \(b\) is the side of the smaller base. Plug in the given values: \(h = 3.88\) mm, \(a = 4.83\) mm, \(b = 2.84\) mm, then calculate the volume.
2Step 2: Calculating the Volume
Volume calculation: \[V = \frac{1}{3} \times 3.88 \times (4.83^2 + 4.83 \times 2.84 + 2.84^2)\] \[V = \frac{1}{3} \times 3.88 \times (23.3089 + 13.7142 + 8.0656)\] \[V = \frac{1}{3} \times 3.88 \times 45.0887\] \[V ≈ 58.00 \, \text{mm}^3\] (rounded to two decimal places)
3Step 3: Calculating the Lateral Area of the Frustum
To calculate the lateral area, first find the slant height \(l\) using the Pythagorean theorem on the triangle formed by half the difference of the squares' sides, \((a-b)/2\), and the altitude \(h\). Slant height \(l = \sqrt{h^2 + \left(\frac{a - b}{2}\right)^2}\). Use this \(l\) and the perimeters of the bases to find the lateral area: \[A_L = \frac{P_a + P_b}{2} \times l\] where \(P_a\) and \(P_b\) are the perimeters of the larger and smaller bases respectively.
4Step 4: Calculating the Slant Height
Calculate the slant height: \[l = \sqrt{3.88^2 + \left(\frac{4.83 - 2.84}{2}\right)^2}\] \[l = \sqrt{15.0544 + \left(0.995\right)^2}\] \[l = \sqrt{15.0544 + 0.990025}\] \[l ≈ 3.99 \, \text{mm}\] (rounded to two decimal places)
5Step 5: Calculating the Lateral Area
Perimeters are \(P_a = 4 \times a\) and \(P_b = 4 \times b\). Using the slant height, calculate lateral area: \[A_L = \frac{4 \times 4.83 + 4 \times 2.84}{2} \times 3.99\] \[A_L = \frac{19.32 + 11.36}{2} \times 3.99\] \[A_L = 15.34 \times 3.99\] \[A_L ≈ 61.21 \, \text{mm}^2\] (rounded to two decimal places)
Key Concepts
Volume of a Frustum FormulaCalculating Lateral AreaPythagorean TheoremSlant Height of a Frustum
Volume of a Frustum Formula
Understanding the volume of a frustum is a fundamental concept in geometry. A frustum is a portion of a solid—typically a cone or pyramid—that remains after cutting the top off with a plane parallel to the base.
For the volume of a frustum derived from a pyramid with a square base, the formula is: \[\begin{equation}V = \frac{1}{3} h (a^2 + ab + b^2)\end{equation}\]where:
For the volume of a frustum derived from a pyramid with a square base, the formula is: \[\begin{equation}V = \frac{1}{3} h (a^2 + ab + b^2)\end{equation}\]where:
- \(V\) is the volume of the frustum,
- \(h\) is the altitude or height of the frustum,
- \(a\) and \(b\) are the lengths of the sides of the larger and smaller square bases, respectively.
Calculating Lateral Area
The lateral area of a frustum is another intriguing concept to explore. It refers to the total area of the sides of the frustum, excluding its top and bottom bases. Calculating the lateral area can be approached by finding the slant height and using the perimeters of both bases.
To compute the lateral area (\(A_L\)) of a frustum with square bases, the formula used is:\[\begin{equation}A_L = \frac{P_a + P_b}{2} \times l\end{equation}\]where:
To compute the lateral area (\(A_L\)) of a frustum with square bases, the formula used is:\[\begin{equation}A_L = \frac{P_a + P_b}{2} \times l\end{equation}\]where:
- \(P_a\) and \(P_b\) are the perimeters of the larger and smaller bases, and
- \(l\) is the slant height of the frustum.
Pythagorean Theorem
The Pythagorean Theorem is a timeless principle in geometry, vital for solving problems involving right triangles. This theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In the mathematical form, the theorem is:\[\begin{equation}c^2 = a^2 + b^2\end{equation}\]where:
In the mathematical form, the theorem is:\[\begin{equation}c^2 = a^2 + b^2\end{equation}\]where:
- \(c\) is the hypotenuse,
- \(a\) and \(b\) are the other two sides of the triangle.
Slant Height of a Frustum
Slant height is a necessary measurement when working with frustums as it's instrumental in calculating the lateral area. The slant height (\(l\)) of a frustum is the shortest distance from any point on the edge of one base to the edge of the other base, measured along the surface of the frustum.
Using the Pythagorean Theorem, the slant height can be found with the formula:\[\begin{equation}l = \sqrt{h^2 + \left(\frac{a - b}{2}\right)^2}\end{equation}\]where:
Using the Pythagorean Theorem, the slant height can be found with the formula:\[\begin{equation}l = \sqrt{h^2 + \left(\frac{a - b}{2}\right)^2}\end{equation}\]where:
- \(h\) is the altitude and
- \(a\) and \(b\) are the sides of the larger and smaller bases, respectively.
Other exercises in this chapter
Problem 26
Find the surface area and radius of a sphere that has a volume of \(462 \mathrm{ft}^{3}\).
View solution Problem 27
Find the volume and lateral area of a regular pyramid having a square base 6.83 in. on a side and an altitude of 7.93 in.
View solution Problem 29
A spherical radome encloses a volume of \(9000 \mathrm{m}^{3} .\) Assume that the sphere is complete, (a) Find the radome radius, \(r\). (b) If the radome is co
View solution Problem 29
The slant height of a right pyramid is 11.0 in., and the base is a 4.00 -in. square. Find the area of the entire surface.
View solution