Problem 28
Question
The distance from \(\pi i\) to 0 is \(|\pi i|=\pi\)
Step-by-Step Solution
Verified Answer
The distance from \( \pi i \) to 0 is \( \pi \).
1Step 1: Understanding the Problem
The problem requires us to find the distance from the point represented by the complex number \( \pi i \) to the origin, which is the point 0, in the complex plane.
2Step 2: Identify the Formula
To find the distance of a complex number \( a + bi \) from the origin, we use the modulus, calculated as \( \sqrt{a^2 + b^2} \). In this case, the complex number is \( 0 + \pi i \).
3Step 3: Apply the Formula
For \( \pi i \), the real part \( a = 0 \) and the imaginary part \( b = \pi \). The modulus is \( \sqrt{0^2 + \pi^2} = \sqrt{\pi^2} \).
4Step 4: Simplify the Expression
We simplify \( \sqrt{\pi^2} \) to get \( \pi \). Therefore, the distance from \( \pi i \) to 0 is \( \pi \).
Key Concepts
Modulus of a Complex NumberComplex PlaneImaginary Numbers
Modulus of a Complex Number
In mathematics, the modulus of a complex number is a fundamental concept used to measure the distance from the complex number to the origin on the complex plane. When dealing with a complex number represented as \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part, the modulus is calculated using the formula:\[|a + bi| = \sqrt{a^2 + b^2}\]For example, in our original problem with the complex number \(\pi i\), we see it as \(0 + \pi i\). Here, \(a = 0\) and \(b = \pi\). Thus, the modulus becomes \(\sqrt{0^2 + \pi^2} = \pi\).
The modulus provides us with a way to grasp the 'size' or 'magnitude' of a complex number, similar to how we perceive the length of a real number on the number line.
The modulus provides us with a way to grasp the 'size' or 'magnitude' of a complex number, similar to how we perceive the length of a real number on the number line.
Complex Plane
The complex plane, sometimes known as the Argand plane, is a graphical representation of complex numbers. This plane consists of two perpendicular axes: the horizontal real axis and the vertical imaginary axis. Each complex number \(a + bi\) corresponds to a unique point in this plane.
For instance, the complex number \(\pi i\) is not just represented by a coordinate -- it's a point directly above the origin (0, 0) on the imaginary axis, at a distance \(\pi\) units upwards.
For instance, the complex number \(\pi i\) is not just represented by a coordinate -- it's a point directly above the origin (0, 0) on the imaginary axis, at a distance \(\pi\) units upwards.
- The real part (\(a\)) of a number indicates how far the point is from the origin along the horizontal axis.
- The imaginary part (\(b\)) specifies the vertical distance from the origin.
Imaginary Numbers
Imaginary numbers are numbers that can be written as a real number multiplied by the imaginary unit \(i\), where \(i\) is defined by the property \(i^2 = -1\). This concept might initially seem abstract, but it's incredibly useful in mathematics and engineering.
Consider the original problem featuring the number \(\pi i\). Here, \(\pi\) is the real number coefficient of the imaginary unit \(i\). Imaginary numbers extend the number line concept from one dimension into two, forming a plane.
Consider the original problem featuring the number \(\pi i\). Here, \(\pi\) is the real number coefficient of the imaginary unit \(i\). Imaginary numbers extend the number line concept from one dimension into two, forming a plane.
- These numbers allow for meaningful solutions to equations that don't have real roots such as \(x^2 + 1 = 0\).
- They facilitate complex analysis and are crucial in signal processing and control theory.
Other exercises in this chapter
Problem 27
The distance from \(2+5 i\) to \(i\) is \(|2+5 i-i|=|2+4 i|=2 \sqrt{5}\)
View solution Problem 28
$$\oint_{C} \frac{\cot \pi z}{z^{2}} d z=2 \pi i \operatorname{Res}(f(z), 0)=2 \pi i\left(-\frac{\pi}{3}\right)=-\frac{2 \pi^{2}}{3} i$$ Note: \(z=0\) is a pole
View solution Problem 28
From \(\lim _{n \rightarrow \infty} \sqrt[n]{\left|(-1)^{n}\left(\frac{1+2 i}{2}\right)^{n}\right|}=\lim _{n \rightarrow \infty}\left|\frac{1+2 i}{2}\right|=\fr
View solution Problem 30
$$\begin{aligned} &\int_{-\infty}^{\infty} \frac{x e^{i x}}{\left(x^{2}+1\right)\left(x^{2}+4\right)} d x=2 \pi i[\operatorname{Res}(f(z), i)+\operatorname{Res}
View solution