Problem 28
Question
Suppose that the concentration (measured in \(\mathrm{gm}^{-3}\) ) of nitrogen in the soil along a transect in moist tundra yields data points that follow a straight line with equation $$ y=673.8-34.7 x $$ for \(0 \leq x \leq 10\), where \(x\) is the distance to the beginning of the transect. What is the average concentration of nitrogen in the soil along this transect?
Step-by-Step Solution
Verified Answer
The average concentration is \(500.3 \, \mathrm{gm}^{-3}\).
1Step 1: Identify the Function
We start with the linear equation given for nitrogen concentration: \(y = 673.8 - 34.7x\). This describes how the concentration \(y\) changes with distance \(x\).
2Step 2: Define the Integral for Average Value
To find the average concentration, we need to integrate the concentration function over the interval \([0, 10]\) and then divide by the length of the interval. The average value \(\bar{y}\) is given by \[\bar{y} = \frac{1}{b-a} \int_{a}^{b} y \, dx\], where \(a = 0\) and \(b = 10\).
3Step 3: Set Up the Integral
Substitute the given function into the integral: \[\int_{0}^{10} (673.8 - 34.7x) \, dx\].
4Step 4: Solve the Integral
Calculate the integral: \[\int 673.8 \, dx = 673.8x\] and \[\int -34.7x \, dx = -\frac{34.7}{2}x^2 = -17.35x^2\]. Combine these results to get \[673.8x - 17.35x^2 \bigg|_{0}^{10}\].
5Step 5: Evaluate the Integral from 0 to 10
Plug in the limits into the integrated function: \[\left(673.8(10) - 17.35(10)^2\right) - (673.8(0) - 17.35(0)^2) = (6738 - 1735) - 0\].
6Step 6: Compute the Result
Calculate the result from the subtraction to find the definite integral: \[6738 - 1735 = 5003\].
7Step 7: Calculate the Average Concentration
Divide the integral result by the interval length: \[\bar{y} = \frac{5003}{10 - 0} = \frac{5003}{10} = 500.3\].
Key Concepts
IntegrationLinear EquationDefinite IntegralTransect Analysis
Integration
Integration is a powerful mathematical tool used to find areas under curves, among other applications. It is particularly useful in this exercise to determine the area under the nitrogen concentration function, which helps us find the average concentration. Integration can be thought of as the process of summing an infinite number of infinitesimally small quantities, thus enabling us to calculate things like total distance, area, or in this case, the total nitrogen concentration along a transect.
Here's a quick introduction to integration:
Here's a quick introduction to integration:
- When you integrate a function, you are essentially finding its antiderivative.
- In practical terms, this means calculating the accumulated value or area under the curve represented by the function.
- In our exercise, this area corresponds to the total concentration of nitrogen along the transect from 0 to 10.
Linear Equation
A linear equation is a mathematical expression that represents a straight line when plotted on a graph. In this exercise, the nitrogen concentration along the transect is described by the linear equation \(y = 673.8 - 34.7x\).
Some key points to remember about linear equations include:
Some key points to remember about linear equations include:
- They are of the form \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.
- The slope \(m\) indicates how steep the line is and the direction of the line.
- In our equation, the slope \(-34.7\) suggests that nitrogen concentration decreases as you move further along the transect.
- The y-intercept \(673.8\) tells us the starting concentration when \(x = 0\).
Definite Integral
A definite integral is used to calculate the accumulation of quantities, such as areas, between two boundary points. In this context, it's applied to find the total concentration of nitrogen over a specific range of distances.
Here's how definite integrals work:
Here's how definite integrals work:
- The definite integral of a function \(\int_{a}^{b} f(x) \, dx\) calculates the net area under the curve \(f(x)\) from point \(a\) to point \(b\).
- It gives us a precise numerical value, unlike indefinite integrals which provide a general formula.
- By solving the definite integral for the given linear equation, we found the total concentration of nitrogen from the start to the end of the transect.
Transect Analysis
Transect analysis involves studying variations along a linear space to infer underlying trends or patterns. This technique is commonly used in environmental science to assess changes in soil composition, vegetation, or other ecological variables over a given distance.
In this exercise, transect analysis is applied as follows:
In this exercise, transect analysis is applied as follows:
- The transect is a straight line, along which the concentration of nitrogen is measured at various points.
- By implementing a linear equation, we predict how soil nitrogen concentration changes with distance.
- The outcome helps in understanding environmental gradients and their potential impacts on local ecosystems.
Other exercises in this chapter
Problem 27
Use the algebraic rules for sums to evaluate each sum. Recall that $$\sum_{k=1}^{n} k=\frac{n(n+1)}{2}$$ and $$\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}$$ $$
View solution Problem 28
Use Leibniz's rule to find \(\frac{d y}{d x}\). $$ y=\int_{2 x^{2}}^{6}(1+\tan t) d t $$
View solution Problem 28
Use the algebraic rules for sums to evaluate each sum. Recall that $$\sum_{k=1}^{n} k=\frac{n(n+1)}{2}$$ and $$\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}$$ $$
View solution Problem 29
Use Leibniz's rule to find \(\frac{d y}{d x}\). $$ y=\int_{x}^{5} \frac{1}{u^{2}} d u, x>0 $$
View solution