Problem 28
Question
Solve using the square root property. Simplify all radicals. $$ x^{2}=54 $$
Step-by-Step Solution
Verified Answer
x = \pm 3\sqrt{6}
1Step 1: Isolate the quadratic term
The given equation is already in the form where the quadratic term is isolated: \[ x^{2} = 54 \]
2Step 2: Apply the square root property
To solve for \( x \), apply the square root property which states that if \( x^{2} = k \), then \( x = \pm \sqrt{k} \). Using this property: \[ x = \pm \sqrt{54} \]
3Step 3: Simplify the radical
Simplify \( \sqrt{54} \) by expressing it as a product of simpler square roots. Since \( 54 = 9 \cdot 6 \) and \( 9 \) is a perfect square, you can rewrite the expression: \[ \sqrt{54} = \sqrt{9 \cdot 6} = \sqrt{9} \cdot \sqrt{6} = 3\sqrt{6} \]
4Step 4: Write the final solution
Substitute the simplified radical back into the equation to get the final solution: \[ x = \pm 3\sqrt{6} \]
Key Concepts
Isolating Quadratic TermSimplifying RadicalsSolving Quadratic Equations
Isolating Quadratic Term
Start by isolating the quadratic term in your equation. For the given problem, the equation is:
\[ x^2 = 54 \]
This equation is already in the perfect form where the quadratic term, \( x^2 \), is isolated on one side. This step is crucial because it makes it easier to apply the square root property. Once the quadratic term is alone, you can easily move forward to solve for \( x \).
\[ x^2 = 54 \]
This equation is already in the perfect form where the quadratic term, \( x^2 \), is isolated on one side. This step is crucial because it makes it easier to apply the square root property. Once the quadratic term is alone, you can easily move forward to solve for \( x \).
Simplifying Radicals
After isolating the quadratic term and applying the square root property, you often end up with a radical expression. In this case, after taking the square root of both sides of the equation, you have:
\[ x = \pm \sqrt{54} \]
Simplifying radicals is another key part of solving such equations. Look inside the radical and find factors that are perfect squares. For \( \sqrt{54} \), recognize that 54 can be factored into 9 and 6, where 9 is a perfect square. Therefore,
\[ \sqrt{54} = \sqrt{9 \cdot 6} \ = \sqrt{9} \cdot \sqrt{6} \ = 3\sqrt{6} \]
Thus, the radical \( \sqrt{54} \) simplifies to \( 3\sqrt{6} \). This makes the expression easier to understand and deal with in further calculations.
\[ x = \pm \sqrt{54} \]
Simplifying radicals is another key part of solving such equations. Look inside the radical and find factors that are perfect squares. For \( \sqrt{54} \), recognize that 54 can be factored into 9 and 6, where 9 is a perfect square. Therefore,
\[ \sqrt{54} = \sqrt{9 \cdot 6} \ = \sqrt{9} \cdot \sqrt{6} \ = 3\sqrt{6} \]
Thus, the radical \( \sqrt{54} \) simplifies to \( 3\sqrt{6} \). This makes the expression easier to understand and deal with in further calculations.
Solving Quadratic Equations
To solve quadratic equations using the square root property, you should:
\[ x^2 = 54 \]
Applying the square root to both sides:
\[ x = \pm \sqrt{54} \]
After simplifying the radical:
\[ x = \pm 3\sqrt{6} \]
The final solution provides two possible values for \( x \):
\[ x = 3\sqrt{6} \]
\[ x = -3\sqrt{6} \]
Remember, solving quadratic equations often yields two solutions because you consider both the positive and negative roots.
- Isolate the quadratic term
- Apply the square root to both sides of the equation
- Simplify the radical if possible
\[ x^2 = 54 \]
Applying the square root to both sides:
\[ x = \pm \sqrt{54} \]
After simplifying the radical:
\[ x = \pm 3\sqrt{6} \]
The final solution provides two possible values for \( x \):
\[ x = 3\sqrt{6} \]
\[ x = -3\sqrt{6} \]
Remember, solving quadratic equations often yields two solutions because you consider both the positive and negative roots.
Other exercises in this chapter
Problem 27
Solve each equation for the specified variable. (Leave \(\pm\) in the answers.) \(L I^{2}+R I+\frac{1}{c}=0\) for \(I\)
View solution Problem 28
Graph each parabola. Give the vertex, axis of symmetry, domain, and range. $$ f(x)=x^{2}+2 x-2 $$
View solution Problem 28
Solve each equation for the specified variable. (Leave \(\pm\) in the answers.) \(P=E I-R I^{2}\) for \(I\)
View solution Problem 29
Graph each parabola. Give the vertex, axis of symmetry, domain, and range. $$ f(x)=-2 x^{2}+4 x-5 $$
View solution