Problem 28
Question
Solve. \(\sqrt{3 x+1}-2=0\)
Step-by-Step Solution
Verified Answer
x = 1
1Step 1: Isolate the Square Root Term
Start by adding 2 to both sides of the equation to isolate the square root term. This gives: \[ \sqrt{3x + 1} = 2 \]
2Step 2: Square Both Sides
To eliminate the square root, square both sides of the equation. This results in: \[ (\sqrt{3x + 1})^2 = 2^2 \]So the equation becomes: \[ 3x + 1 = 4 \]
3Step 3: Solve the Linear Equation
Subtract 1 from both sides to start solving for x:\[ 3x = 3 \]Next, divide both sides by 3:\[ x = 1 \]
Key Concepts
Linear EquationsIsolating the VariableSquaring Both Sides
Linear Equations
At the heart of many algebra problems, we find the linear equation. A linear equation is simply an equation that represents a straight line when graphed. It takes the general form of \(ax + b = c\), where \(a\), \(b\), and \(c\) are constants. Linear equations are called 'linear' because their graph is a straight line, and they have a constant rate of change.
These equations are significant in algebra largely because they are straightforward to solve using basic arithmetic operations. Solving them involves a series of steps to isolate the variable. In practice, this often involves adding, subtracting, multiplying, or dividing both sides of the equation by the same number to get the variable alone on one side.
These equations are significant in algebra largely because they are straightforward to solve using basic arithmetic operations. Solving them involves a series of steps to isolate the variable. In practice, this often involves adding, subtracting, multiplying, or dividing both sides of the equation by the same number to get the variable alone on one side.
- Example: For \(3x + 1 = 4\), subtract 1 from both sides to move the +1 to the other side, getting \(3x = 3\).
- Then, divide by 3 to solve for \(x\), resulting in \(x = 1\). This step-by-step breakdown shows how versatile and manageable linear equations can be.
Isolating the Variable
Isolating the variable is a crucial first step in solving equations, particularly when you're faced with more complicated expressions like those involving square roots. The goal is to manipulate the equation so that the variable you're solving for is alone on one side of the equal sign. This makes it easier to perform further operations that lead to a solution.
In the context of our exercise, isolating the square root term involves rearranging the given equation, \(\sqrt{3x + 1} - 2 = 0\). Here, you add 2 to both sides, resulting in \(\sqrt{3x + 1} = 2\).
In the context of our exercise, isolating the square root term involves rearranging the given equation, \(\sqrt{3x + 1} - 2 = 0\). Here, you add 2 to both sides, resulting in \(\sqrt{3x + 1} = 2\).
- The idea is to change the equation's form without altering its truth, maintaining balance by performing the same operation on both sides.
- Once the term is isolated, you can proceed to eliminate the square root by squaring both sides, simplifying the equation further.
Squaring Both Sides
Squaring both sides of an equation is a powerful technique used when dealing with square roots. The objective is to remove the square root, transforming the equation into a linear form, which is easier to solve. After isolating the square root term, you are left with an equation like \(\sqrt{3x + 1} = 2\).
To eliminate the square root, you must square both sides of the equation:
\[(\sqrt{3x + 1})^2 = 2^2\]
To eliminate the square root, you must square both sides of the equation:
\[(\sqrt{3x + 1})^2 = 2^2\]
- This operation converts \(\sqrt{3x + 1}\) into \(3x + 1\), and \(2^2\) results in 4.
- The equation now reads \(3x + 1 = 4\), a simple linear equation that can easily be solved.
Other exercises in this chapter
Problem 28
Add or subtract. Write the sum or difference in the form \(a+b i .\) See Example 3 $$ (2-4 i)-(2-i) $$
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Use radical notation to write each expression. Simplify if possible. $$ \left(\frac{49}{25}\right)^{3 / 2} $$
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Add or subtract. $$ 3 \sqrt{8 x^{2} y^{3}}-2 x \sqrt{32 y^{3}} $$
View solution Problem 29
Find each root. Assume that all variables represent nonnegative real numbers. $$ -\sqrt[4]{16} $$
View solution