Problem 28
Question
Sketch the given function and determine whether it is piecewise continuous on \([0, \infty)\). $$f(t)=n, \quad n \leq t < n+1, \quad n=0,1,2, \ldots$$
Step-by-Step Solution
Verified Answer
The given function can be visualized as a staircase-like graph with constant values for each interval \([n, n+1)\), where \(n\) is an integer value. It is continuous on each individual interval but has jump discontinuities at the integer values. Therefore, the function is piecewise continuous on the interval \([0, \infty)\).
1Step 1: Break down the function for different intervals
Let's first break down the given function into several intervals, based on the parameter \(n\):
- For \(n=0\), the function is defined as \(f(t)=0,\) for \(0\leq t<1\).
- For \(n=1\), the function is defined as \(f(t)=1,\) for \(1\leq t<2\).
- For \(n=2\), the function is defined as \(f(t)=2,\) for \(2\leq t<3\).
- This pattern continues for all integer values of \(n\).
2Step 2: Sketch the graph of the function
Now that we have defined the function for each interval, let's sketch the graph on the given domain \([0, \infty)\):
- On the interval \([0, 1)\), the function is constant at \(f(t)=0\).
- On the interval \([1, 2)\), the function is constant at \(f(t)=1\).
- On the interval \([2, 3)\), the function is constant at \(f(t)=2\).
- And so on...
We end up with a staircase-like graph, where each step has a width of \(1\) and a height equal to \(n\).
3Step 3: Determine the continuity of the function
To determine if the function is piecewise continuous, we need to check its continuity for each interval:
- On \([0, 1)\), the function is continuous since it's constant.
- On \([1, 2)\), the function is continuous since it's constant.
- On \([2, 3)\), the function is continuous since it's constant.
So, the function is continuous on each individual interval. However, we also need to check continuity at the endpoints of each interval, these are the integer values (\(n=0, 1, 2, ...\)).
At these points, there is always a jump (discontinuity) equal to \(1\), as the function jumps from the value \(n-1\) to \(n\) when moving from left to right along the domain.
4Step 4: Conclusion
The given function is a staircase-like graph with constant values for each interval \([n, n+1)\), where \(n\) is an integer value. The function is continuous on each individual interval, but there are jump discontinuities at the integer values. Therefore, the function is piecewise continuous on the interval \([0, \infty)\).
Key Concepts
Staircase FunctionInterval ContinuityDiscontinuity at Endpoints
Staircase Function
A staircase function is a type of piecewise function that resembles a set of steps. Each "step" in the graph is a horizontal line segment that maintains a constant value over a specific interval, much like the steps of a staircase. The given function, which is defined as \( f(t) = n \) for \( n \leq t < n+1 \), demonstrates this perfectly:
- For each integer \( n \), the function maintains a constant output \( n \) within the interval \([n, n+1)\).
- The width of each step is uniform and spans exactly 1 unit.
- The height of each step increases incrementally by 1 as \( n \) increases.
Interval Continuity
Interval continuity refers to the property of a function being uninterrupted and smooth over a particular range. In the case of our staircase function, the intervals \([n, n+1)\) for each integer \( n \) are where the function maintains continuity. Within these intervals,
- The function value does not change, remaining constant at \( n \).
- No sudden jumps or breaks occur, as the function value remains fixed.
Discontinuity at Endpoints
While the staircase function is continuous within each interval, it exhibits discontinuity at the endpoints, particularly at each integer \( n \). These are the points where the horizontal line segments "jump" to a new level:
- As we move from \( t = n-1 \) to \( t = n \), the function value shifts from \( n-1 \) to \( n \).
- Each jump represents a discontinuity, as there is no smooth transition between the two values.
- Discontinuities at these integer points define the piecewise nature of the entire structure.
Other exercises in this chapter
Problem 28
Sketch \(f(t),\) express \(f(t)\) in terms of \(u_{a}(t),\) and determine \(L\\{f(t)\\}\). $$f(t)=\left\\{\begin{array}{cc} t, & 0 \leq t 3 \end{array}\right.$$
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Use the Laplace transform to find the general solution to \(y^{\prime \prime}-y=0\).
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Solve the given initial-value problem. $$y^{\prime}-2 y=u_{2}(t) e^{t-2}, \quad y(0)=2$$.
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Solve the given initial-value problem up to the evaluation of a convolution integral. \(y^{\prime \prime}+16 y=f(t), \quad y(0)=\alpha, \quad y^{\prime}(0)=\bet
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