Problem 28
Question
Simplify the rational expression. $$ \frac{1-x^{2}}{x^{3}-1} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \( \frac{-(1+x)}{x^2 + x + 1} \).
1Step 1: Identify Factoring Formulas
To simplify the rational expression \( \frac{1-x^2}{x^3-1} \), first identify any factoring formulas that can be used. Recall the difference of squares formula \( a^2 - b^2 = (a-b)(a+b) \) and the difference of cubes formula \( a^3 - b^3 = (a-b)(a^2 + ab + b^2) \).
2Step 2: Factor the Numerator
Rewrite the numerator \( 1-x^2 \) using the difference of squares formula: \( 1-x^2 = (1-x)(1+x) \).
3Step 3: Factor the Denominator
Rewrite the denominator \( x^3 - 1 \) using the difference of cubes formula: \( x^3 - 1 = (x-1)(x^2 + x + 1) \).
4Step 4: Simplify the Rational Expression
Substitute the factored forms into the rational expression: \( \frac{(1-x)(1+x)}{(x-1)(x^2 + x + 1)} \). Notice that \( 1-x \) can be rewritten as \( -(x-1) \), so the expression becomes \( \frac{-(x-1)(1+x)}{(x-1)(x^2 + x + 1)} \).
5Step 5: Cancel Common Factors
Cancel the common factor \( (x-1) \) from the numerator and the denominator to get \( \frac{-(1+x)}{x^2 + x + 1} \).
6Step 6: Simplified Expression
The simplified form of the given rational expression is \( \frac{-(1+x)}{x^2 + x + 1} \).
Key Concepts
Factoring FormulasDifference of SquaresDifference of CubesCanceling Common Factors
Factoring Formulas
Factoring formulas play a crucial role in simplifying algebraic expressions. They help break down complex expressions into more manageable parts. When it comes to rational expressions, factoring helps to identify common factors that can be canceled out, making the expression simpler.
- Difference of Squares: This is a common factoring formula and is expressed as \( a^2 - b^2 = (a-b)(a+b) \). It is used for expressions where the square of one term is subtracted from the square of another.
- Difference of Cubes: Another useful formula is \( a^3 - b^3 = (a-b)(a^2 + ab + b^2) \). This applies to expressions where one cubic term is subtracted from another.
Difference of Squares
The difference of squares formula is a simple yet powerful tool. It helps us recognize that when you subtract one square term from another, it can be factored into a product of two binomials. In our problem, the numerator \(1-x^2\) becomes easy to factor using this formula.
Consider the following steps to grasp this concept better:
Consider the following steps to grasp this concept better:
- Identify terms: Notice the expression fits the pattern \(a^2 - b^2\) where \(a = 1\) and \(b = x\).
- Apply formula: Factor it as \((1-x)(1+x)\). This transformation is straightforward and results from the formula \( (a-b)(a+b)\).
Difference of Cubes
The difference of cubes formula is a bit more involved than the difference of squares, but it follows a logical pattern. For our denominator \(x^3 - 1\), this formula proves to be essential.
To effectively use the difference of cubes:
To effectively use the difference of cubes:
- Identify terms: Recognize \(a = x\) and \(b = 1\), fitting the pattern \(a^3 - b^3\).
- Apply formula: Factor it as \((x-1)(x^2 + x + 1)\). This results from \(a^3 - b^3 = (a-b)(a^2 + ab + b^2)\).
Canceling Common Factors
Canceling common factors is the final and crucial step in simplifying rational expressions. After factoring both numerator and denominator, we look for terms that are common.
In our expression, noticing and canceling the common factor \((x-1)\) simplifies the expression further:
In our expression, noticing and canceling the common factor \((x-1)\) simplifies the expression further:
- Recognize common factors in both numerator and denominator.
- Cancel the \((x-1)\) since it appears in both places. This step does not change the overall value of the expression, just its appearance, simplifying it.
- What remains is \(-(1+x)/(x^2 + x + 1)\).
Other exercises in this chapter
Problem 27
Find the indicated set if $$ A=\\{1,2,3,4,5,6,7\\} \quad B=\\{2,4,6,8\\} \quad C=\\{7,8,9,10\\} $$ $$ \begin{array}{ll}{\text { (a) } A \cup B} & {\text { (b) }
View solution Problem 27
Use properties of real numbers to write the expression without parentheses. \(-\frac{5}{2}(2 x-4 y)\)
View solution Problem 28
\(21-28\) Use a Factoring Formula to factor the expression. $$ 16 z^{2}-24 z+9 $$
View solution Problem 28
\(7-28\) Evaluate each expression. $$ 3^{-1}-3^{-3} $$
View solution