Problem 28
Question
Simplify the expression, writing your answer using positive exponents only. $$ \left(3 u^{-1} v^{-2}\right)^{-3} $$
Step-by-Step Solution
Verified Answer
\( \dfrac{u^3 v^6}{27} \)
1Step 1: Apply properties of exponents to each term inside the parentheses and separate the variables
By applying the power rule, we multiply the exponents of each term inside the parentheses by -3. \( \left( \left( 3 \right)^{-3} \left( u^{-1} \right)^{-3} \left( v^{-2} \right)^{-3} \right) \)
2Step 2: Simplify the expression inside the parentheses
Simplify each term and write them separately.
\( 3^{-3} \cdot u^{-1 \cdot (-3)} \cdot v^{-2 \cdot (-3)} = \dfrac{1}{3^3} \cdot u^3 \cdot v^6 \)
3Step 3: Combine terms to get the final simplified expression
Finally, merge the terms inside the expression to get the simplified result.
\( \dfrac{1 \cdot u^3 \cdot v^6}{3^3} = \dfrac{u^3 v^6}{27} \)
Key Concepts
Power RuleSimplifying ExpressionsPositive Exponents
Power Rule
The power rule is a key concept when dealing with exponents, especially in expressions. It allows us to simplify complex expressions by multiplying the exponents. When raising a power to another power, you multiply the exponents according to the power rule. For instance, if you have \((x^a)^b\), it becomes \(x^{a \cdot b}\).
The power rule makes simplifying expressions much more straightforward. In the given expression, \( (3u^{-1}v^{-2})^{-3} \), each term inside the brackets has its exponent multiplied by -3. Let's break down each term:
The power rule makes simplifying expressions much more straightforward. In the given expression, \( (3u^{-1}v^{-2})^{-3} \), each term inside the brackets has its exponent multiplied by -3. Let's break down each term:
- \(3\) raised to power -3 becomes \(3^{-3}\)
- \(u^{-1}\) raised to power -3 becomes \(u^{-1 \cdot (-3)} = u^3\)
- \(v^{-2}\) raised to power -3 becomes \(v^{-2 \cdot (-3)} = v^6\)
Simplifying Expressions
Simplifying an expression often involves using the power rule as well as other fundamental properties of exponents. It helps express terms in the simplest form possible. For instance, in our exercise, after applying the power rule, we get \(3^{-3} \cdot u^3 \cdot v^6\). To simplify this expression further, focus on converting any negative exponents into positive exponents.
Negative exponents, such as \(3^{-3}\), can be rewritten as fractions: \(\frac{1}{3^3}\). This process entails placing the term with the negative exponent in the denominator to make it positive. So, \(3^{-3}\) becomes \(\frac{1}{27}\).
Negative exponents, such as \(3^{-3}\), can be rewritten as fractions: \(\frac{1}{3^3}\). This process entails placing the term with the negative exponent in the denominator to make it positive. So, \(3^{-3}\) becomes \(\frac{1}{27}\).
- Arrange the simplified terms: \(u^3\) and \(v^6\) remain in the numerator.
- Final expression: \(\frac{u^3 \cdot v^6}{27}\)
Positive Exponents
Positive exponents are often preferred in final expressions. They provide a clearer and more standard representation of mathematical solutions. When simplifying expressions, converting all negative exponents to positive ones is essential.
Remember, a negative exponent suggests the inverse of that number. For example, \(a^{-b}\) can be rewritten as \(\frac{1}{a^b}\), leading to positive exponents. This method was applied to the original expression \(3^{-3}\) to convert it into \(\frac{1}{3^3} = \frac{1}{27}\).
Remember, a negative exponent suggests the inverse of that number. For example, \(a^{-b}\) can be rewritten as \(\frac{1}{a^b}\), leading to positive exponents. This method was applied to the original expression \(3^{-3}\) to convert it into \(\frac{1}{3^3} = \frac{1}{27}\).
- When simplifying, ensure all exponents are positive for clarity and standardization.
- The solution \(\frac{u^3 v^6}{27}\) represents fully positive exponents, maintaining a clean and universally understandable form.
Other exercises in this chapter
Problem 28
Solve the equation by using the quadratic formula. $$ 6 x^{2}-7 x-3=0 $$
View solution Problem 28
Carry out the indicated operation and write your answer using positive exponents only. $$ \left[(-3)^{1 / 3}\right]^{2} $$
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Solve the given equation. $$ \frac{y}{3}-\frac{2}{y+1}=\frac{1}{3}(y-3) $$
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In Exercises, factor the polynomial. If the polynomial is prime, state it. $$ 12 x^{2} y-2 x y-24 y $$
View solution