Problem 28
Question
Range of values of \(f(x)=1+\sin x+\sin ^{3} x+\sin ^{5} x \ldots\) \(x \in\left(\frac{-\pi}{2}, \frac{\pi}{2}\right)\) is (A) \((0,1)\) (B) \((-\infty, \infty)\) (C) \((-2,2)\) (D) None of these
Step-by-Step Solution
Verified Answer
The range of \( f(x) \) is \((-\infty, \infty)\), so it's option (B).
1Step 1: Understand the Infinite Series
The given function is an infinite series: \( f(x) = 1 + \sin x + \sin^3 x + \sin^5 x + \ldots \). This is a geometric series with the first term \( a = \sin x \) and the common ratio \( r = (\sin^2 x) \). We need to analyze the sum of this series.
2Step 2: Derive the Sum of Infinite Series
To find the sum of the infinite series \( S \), we use the geometric series sum formula: \( S = \frac{a}{1-r} \), provided \(|r| < 1\). Here, \( a = \sin x \) and \( r = \sin^2 x \), so the sum of the series is \( \frac{\sin x}{1 - \sin^2 x} \). This simplifies to \( \frac{\sin x}{\cos^2 x} \) since \(1 - \sin^2 x = \cos^2 x\).
3Step 3: Simplify the Sum
Now we simplify the expression further by noting that \( \frac{\sin x}{\cos^2 x} = \tan x \sec x = \sec x \tan x \). Thus, the series sum is \( \sec x \tan x \).
4Step 4: Analyze the Function Behavior
The function becomes \( f(x) = 1 + \sec x \tan x \). We know that \( \tan x \) and \( \sec x \) both have vertical asymptotes as \( x \to \frac{\pi}{2}^- \) and \( x \to \frac{-\pi}{2}^+ \). Thus, the function can grow quite large in magnitude. However, within \( x \in\left(\frac{-\pi}{2}, \frac{\pi}{2}\right) \), both functions adjust such that all values encompassing zero, positive and negative, are possible within a finite range.
5Step 5: Determine the Range
Since \( \sec x \tan x \) can take any real value from \(-\infty\) to \( \infty \) as \( x \to \pm \frac{\pi}{2} \), \( f(x) = 1 + \sec x \tan x \) can take any real value as well. Hence, the range of \( f(x) \) is \((-\infty, \infty)\).
Key Concepts
Infinite SeriesRange of FunctionsTrigonometric Functions
Infinite Series
An infinite series is a sum of infinitely many terms. In mathematics, an infinite series like the geometric series can provide great insights about function behaviors beyond finite boundaries. For the given function, we identified an infinite series:
- The first term, called the initial term, is often denoted as "a." Here, that's "\( \sin x \)."
- The common ratio for our series is "\( \sin^2 x \)."
Range of Functions
Understanding the range of a function is crucial because it tells us all possible outputs of a function given its domain. For a function to be well understood, its behavior across its entire range must be grasped. With the function in question:
- It combines a constant term, "1", with the expression \( \sec x \tan x \).
- This combination results from the sum of the infinite series.
Trigonometric Functions
Trigonometric functions are fundamental components of mathematics, describing the relationships involving angles and sides of triangles, often extending to periodic cycles. Here are key details:
- \( \sin x \) is a fundamental trigonometric function that oscillates between -1 and 1.
- \( \tan x \) is the quotient of \( \sin x \) and \( \cos x \), and it has vertical asymptotes where \( \cos x = 0 \).
- \( \sec x \), the reciprocal of \( \cos x \), also displays asymptotic behavior at the same points as \( \tan x \).
Other exercises in this chapter
Problem 26
Let \(f(x)\) be defined for all \(x>0\) and be continuous. Let \(f(x)\) satisfy \(f\left(\frac{x}{y}\right)=f(x)-f(y)\) for all \(x, y\) and \(f(e)=1 .\) Then \
View solution Problem 27
If \(g(x)=1+\sqrt{x}\) and \(f[g(x)]=3+2 \sqrt{x}+x\), then \(f(x)=\) (A) \(1+2 x^{2}\) (B) \(2+x^{2}\) (C) \(1+x\) (D) \(2+x\)
View solution Problem 29
The function \(f:(-\infty,-1] \rightarrow\left(0, e^{5}\right]\) defined by, \(f(x)=e^{x^{3}-3 x+2}\) is (A) Many one and onto (B) Many one and into (C) One-one
View solution Problem 30
The domain of the function \(f(x)=\log _{2}\left(-\log _{1 / 2}\left(1+\frac{1}{\sqrt[4]{x}}\right)-1\right)\) is (A) \(01\)
View solution