Problem 28
Question
Oxidation number of \(\mathrm{Cl}\) in \(\mathrm{NOClO}_{4}\) and \(\mathrm{NOCl}\) is respectively (a) \(-\mid\) and \(+1\) (b) \(+\mathrm{I}\) and \(-1\) (c) \(+7\) and \(-1\) (d) \(+5\) and \(+1\)
Step-by-Step Solution
Verified Answer
Oxidation numbers of Cl are +3 in NOClO4 and -1 in NOCl, but none of the options match this exactly.
1Step 1: Calculating Chlorine Oxidation Number in NOClO4
Start by identifying the known oxidation states: nitrogen (N) typically is "+5" in nitrates, and oxygen (O) is "-2".For NOClO4, the oxidation state of the whole compound sums to zero. Let the oxidation number of Cl be x. The equation becomes: \[ 5 + x + 4(-2) = 0 \] \( 5 + x - 8 = 0 \) which simplifies to \( x = +3 \)
2Step 2: Calculating Chlorine Oxidation Number in NOCl
Identify the known oxidation numbers: nitrogen (N) is typically in oxidation state "+3" in nitrosyl derivatives and oxygen (O) is "-2".For NOCl, the total oxidation state must be zero. Let the oxidation number of Cl be y:\[ 3 + y - 2 = 0 \] Solving gives \( y = -1. \)
Key Concepts
Chlorine CompoundsNitrate ChemistryOxidation Numbers Calculation
Chlorine Compounds
Chlorine is an incredibly versatile element found in many compounds with varying oxidation states. When chlorine forms compounds, its oxidation state can differ greatly. In the compound \( \text{NOClO}_4 \), chlorine takes on an oxidation state which depends on the surrounding atoms.
\( \text{NOClO}_4 \) is unique as it combines elements from nitrates with chlorine, leading to different oxidation characteristics than typical chlorides or oxychlorides.
This diversity makes chlorine compounds highly valuable in numerous chemical processes and applications. Understanding chlorine's oxidation state helps chemists determine the behavior and reactivity of these compounds in various environments.
\( \text{NOClO}_4 \) is unique as it combines elements from nitrates with chlorine, leading to different oxidation characteristics than typical chlorides or oxychlorides.
This diversity makes chlorine compounds highly valuable in numerous chemical processes and applications. Understanding chlorine's oxidation state helps chemists determine the behavior and reactivity of these compounds in various environments.
Nitrate Chemistry
Nitrates are chemical compounds that contain the nitrate ion \( \text{NO}_3^- \), often important for their oxidizing properties. These compounds play crucial roles in both industrial applications and biological processes.In nitrate chemistry, the central nitrogen atom typically maintains an oxidation state of +5. This is due to its bonding with three oxygens, each contributing a c-2 oxidation state. The balance helps dictate the overall charge of the nitrate group. Nitrates, such as those seen in \( \text{NOClO}_4 \), illustrate the intersection of nitrogen's potential to form complex oxidizing agents. Despite sometimes being overshadowed by the nitrogen atom, the nitrate ion's ability to form stable compounds significantly impacts chemical reactions.
Oxidation Numbers Calculation
Calculating oxidation numbers, or states, in a compound involves a few key rules that help assess how electrons are distributed among atoms:
Meanwhile, in \( \text{NOCl} \), recognizing nitrogen at +3 and oxygen at -2 enables calculation: \( 3 + y - 2 = 0 \), deriving chlorine's oxidation number as -1.
Understanding oxidation states allows clearer insight into reactivity and binding characteristics within compounds, enhancing comprehensive chemical comprehension.
- For a neutral compound, the sum of oxidation numbers is zero.
- Oxygen usually has an oxidation number of -2.
- Chlorine varies but often adopts negative values in simple halogen compounds.
Meanwhile, in \( \text{NOCl} \), recognizing nitrogen at +3 and oxygen at -2 enables calculation: \( 3 + y - 2 = 0 \), deriving chlorine's oxidation number as -1.
Understanding oxidation states allows clearer insight into reactivity and binding characteristics within compounds, enhancing comprehensive chemical comprehension.
Other exercises in this chapter
Problem 27
The aqueous solution of \(\mathrm{AICl}_{3}\) is acidic due to: (a) cation hydrolysis (b) anion hydrolysis (c) hydrolysis of both the ions (d) dissociation
View solution Problem 27
\(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}+\mathrm{HI} \rightarrow \mathrm{K} \mathrm{I}+\mathrm{Cr} \mathrm{I}_{3}+\mathrm{H}_{2} \mathrm{O}+\mathrm{I}_{2
View solution Problem 29
Which has the highest \(\mathrm{pH}\) ? (a) \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\) (b) \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) (c) \(\mathrm{NH}_{4} \mathrm{Cl}\) (
View solution Problem 29
Oxidation numbers of iodine in iodate and periodate are respectively (a) \(+3\) and \(+5\) (b) \(+1\) and \(+3\) (c) \(+5\) and \(+7\) (d) \(+3\) and \(+7\)
View solution