Problem 28
Question
Let \(\mathscr{L}_{a}\) and \(\mathscr{L}_{b}\) be lines with direction vectors a and \(\mathbf{b}\), respectively. \(\mathscr{L}_{a}\) and \(\mathscr{L}_{b}\) areorthogonalifa and \(\mathbf{b}\) are orthogonal and parallel if a and \(\mathbf{b}\) are parallel. Determine which of the following lines are orthogonal and which are parallel. (a) \(\mathbf{r}=\langle 1,0,2\rangle+t\langle 9,-12,6\rangle\) (b) \(x=1+9 t, y=12 t, z=2-6 t\) (c) \(x=2 t, y=-3 t, z=4 t\) (d) \(x=5+t, y=4 t, z=3+\frac{5}{2} t\) (e) \(x=1+t, y=\frac{3}{2} t, z=2-\frac{3}{2} t\) (f) \(\frac{x+1}{-3}=\frac{y+6}{4}=\frac{z-3}{-2}\)
Step-by-Step Solution
Verified Answer
None of the lines are orthogonal or parallel.
1Step 1: Identify Direction Vectors
First, we need to identify the direction vectors for each line. The direction vector of a line in parametric form can be directly derived from the coefficients accompanying the parameter, usually denoted as \( t \). (a) Direction vector \( \mathbf{a} = \langle 9, -12, 6 \rangle \)(b) Direction vector \( \mathbf{b} = \langle 9, 12, -6 \rangle \)(c) Direction vector \( \mathbf{c} = \langle 2, -3, 4 \rangle \)(d) Direction vector \( \mathbf{d} = \langle 1, 4, \frac{5}{2} \rangle \)(e) Direction vector \( \mathbf{e} = \langle 1, \frac{3}{2}, -\frac{3}{2} \rangle \)(f) Direction vector \( \mathbf{f} = \langle -3, 4, -2 \rangle \).
2Step 2: Check Orthogonality
Two vectors are orthogonal if their dot product is zero. We calculate the dot products of all pairs:- \( \mathbf{a} \cdot \mathbf{b} = (9)(9) + (-12)(12) + (6)(-6) = 81 + (-144) + (-36) = -99 \)- \( \mathbf{a} \cdot \mathbf{c} = (9)(2) + (-12)(-3) + (6)(4) = 18 + 36 + 24 = 78 \)- \( \mathbf{a} \cdot \mathbf{d} = (9)(1) + (-12)(4) + (6)\cdot\frac{5}{2} = 9 - 48 + 15 = -24 \)- \( \mathbf{a} \cdot \mathbf{e} = (9)(1) + (-12)(\frac{3}{2}) + (6)(-\frac{3}{2}) = 9 - 18 - 9 = -18 \)- \( \mathbf{a} \cdot \mathbf{f} = (9)(-3) + (-12)(4) + (6)(-2) = -27 - 48 - 12 = -87 \) No pairs are orthogonal as no dot product equals zero.
3Step 3: Check Parallelism
Two vectors are parallel if one is a scalar multiple of the other. Let's check by comparing ratios among corresponding elements:- \( \mathbf{a} = \langle 9, -12, 6 \rangle \) and \( \mathbf{b} = \langle 9, 12, -6 \rangle \). Comparing components, 9:9, -12:12, 6:-6 are not consistent ratios.- Check if \( \mathbf{a}, \mathbf{c}, \mathbf{d}, \mathbf{e}, \mathbf{f} \). None are scalar multiples of each other based on component ratios.No pairs of vectors have consistent ratios, so no lines are parallel.
4Step 4: Conclusion: Determine Relationships
Since none of the lines have a direction vector that is the scalar multiple of another, they are not parallel. Similarly, since no dot product is zero, no lines are orthogonal.
Each line stands independently with no direct parallel or orthogonal relationships as defined here.
Key Concepts
Direction VectorsOrthogonalityParallelismDot Product
Direction Vectors
Direction vectors are crucial in understanding the orientation of a line in space. For any line given in parametric form, the direction vector can be directly obtained from the coefficients accompanying the parameter \( t \). This vector essentially provides the 'direction' in which the line extends.
For example, if you have a line given by \( \mathbf{r} = \langle x_0, y_0, z_0 \rangle + t \langle a, b, c \rangle \), the direction vector is \( \langle a, b, c \rangle \). Understanding direction vectors can help you to:
For example, if you have a line given by \( \mathbf{r} = \langle x_0, y_0, z_0 \rangle + t \langle a, b, c \rangle \), the direction vector is \( \langle a, b, c \rangle \). Understanding direction vectors can help you to:
- Visualize how a line moves along the axes.
- Determine the orientation of a line relative to others.
- Perform calculations like finding if lines are orthogonal or parallel.
Orthogonality
Orthogonality between vectors relates to them being at right angles to each other in space. Two vectors are considered orthogonal if their dot product equals zero.
Dot Product and Orthogonality
The dot product of two vectors \( \mathbf{a} \cdot \mathbf{b} \) is calculated as:\[ \mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + a_3b_3 \]For vectors to be orthogonal:- Calculate the dot product.
- If the result is zero, the vectors are orthogonal.
Parallelism
Parallelism between vectors means they lie along the same line or planes without intersecting, besides stretching infinitely. Two vectors are parallel if one is a scalar multiple of the other.For two vectors \( \mathbf{a} = \langle a_1, a_2, a_3 \rangle \) and \( \mathbf{b} = \langle b_1, b_2, b_3 \rangle \) to be parallel, there should exist a constant \( k \) such that:\[ a_1 = kb_1, \quad a_2 = kb_2, \quad a_3 = kb_3 \]
Identifying Parallel Vectors
- Compare the ratios of the corresponding components of the vectors.
- If you find a consistent ratio for each component, the vectors are parallel.
Dot Product
The dot product is an important operation that takes two equal-length sequences of numbers (usually coordinate vectors) and returns a single number. This number can tell us many important things about the vectors, such as their lengths and the angle between them.The dot product \( \mathbf{a} \cdot \mathbf{b} \) is given by the formula:\[ \mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + a_3b_3 \]Here are a few key insights:
- If \( \mathbf{a} \cdot \mathbf{b} = 0 \), the vectors are orthogonal.
- The dot product helps in calculating projections and understanding vector projections in physics and engineering.
Other exercises in this chapter
Problem 27
The given three points form a triangle. Determine which triangles are isosceles and which are right triangles. $$ (1,2,3),(4,1,3),(4,6,4) $$
View solution Problem 27
Find a unit vector (a) in the same direction as \(\mathbf{a}\), and (b) in the opposite direction of \(\mathbf{a}\). \(\mathbf{a}=\langle 0,-5\rangle\)
View solution Problem 28
Find the direction cosines and direction angles of the given vector. $$ \mathbf{a}=\langle 5,7,2\rangle $$
View solution Problem 28
Find the indicated scalar or vector without using \((5),(13)\), or \((15)\). $$ \mathbf{i} \cdot[\mathbf{j} \times(-\mathbf{k})] $$
View solution