Problem 28
Question
In Exercises 27 and \(28,\) find the center of mass of the point masses lying on the \(x\) -axis. $$ \begin{array}{l} m_{1}=12, m_{2}=1, m_{3}=6, m_{4}=3, m_{5}=11 \\ x_{1}=-6, x_{2}=-4, x_{3}=-2, x_{4}=0, x_{5}=8 \end{array} $$
Step-by-Step Solution
Verified Answer
The center of mass of the given points is located at \(x=0\) on the x-axis.
1Step 1: Find the Total Mass (M)
First we start by finding the total mass of the system. This is done by summing up all individual masses: \(M = m_{1} + m_{2} + m_{3} + m_{4} + m_{5} = 12 + 1 + 6 + 3 + 11 = 33 \) kg.
2Step 2: Multiply Each Mass With its Corresponding position
Next, multiply each mass with its position: \(x_{1}m_{1} = -6*12, x_{2}m_{2} = -4*1, x_{3}m_{3}= -2*6, x_{4}m_{4}= 0*3, x_{5}m_{5} = 8*11\). This gives us the values -72, -4, -12, 0 and 88 respectively.
3Step 3: Sum the Results of Step 2
Now, we add all the values from step 2 together: \(-72 - 4 - 12 + 0 + 88 = 0\). This value indicates the numerator of our center of mass equation.
4Step 4: Calculate the Center of Mass
To find the center of mass, we divide the sum from step 3 by the total mass from step 1: \(x_{\text{cm}} = \frac{0}{33} = 0\).
Key Concepts
Point MassesMass Distributionx-Axis Calculations
Point Masses
Point masses are idealized objects where the entire mass is concentrated at a single point in space. This abstraction is useful for simplifying the analysis of mechanical systems.
In practical terms, when calculating the center of mass, each point mass is treated as if its entire weight acts at one coordinate location. This allows us to ignore the dimensions and shapes of these masses and focus solely on their weight and position, greatly simplifying calculations.
Understanding point masses help you in scenarios involving
In practical terms, when calculating the center of mass, each point mass is treated as if its entire weight acts at one coordinate location. This allows us to ignore the dimensions and shapes of these masses and focus solely on their weight and position, greatly simplifying calculations.
Understanding point masses help you in scenarios involving
- particles on a line
- bodies with negligible volume
- systems where mass can be considered concentrated at a point, like stars in astrophysics or atoms in molecules
Mass Distribution
Mass distribution refers to how mass is spread out over space. To determine the center of mass in a linear system like this, it’s crucial to understand where each individual mass is located along the line.
Knowing the positions and values of each point mass along the x-axis allows us to calculate the influence each mass has in determining the center of mass of the system.
Consider
Knowing the positions and values of each point mass along the x-axis allows us to calculate the influence each mass has in determining the center of mass of the system.
Consider
- the influence of larger masses, which can dominate the center of mass location
- how massively weighted points further from the center will skew the center accordingly
x-Axis Calculations
Calculating the center of mass along the x-axis involves breaking down a multifaceted process into straightforward steps.
This calculation is essential in physics and engineering as it helps in understanding how a system will naturally move or balance based on the forces applied or gravitational actions. For instance, in this exercise, the result demonstrates that the masses balance at the origin, meaning their influences counteract perfectly across the x-axis with respect to distribution and weight.
- First, sum all point masses to determine the total mass of the system. This number serves as the divisor in the final calculation.
- Next, multiply each mass by its position on the x-axis. This step highlights the individual contributions to the "mass moment," showing how each point mass impacts the system's equilibrium.
- Add all these products together to obtain a total mass moment.
This calculation is essential in physics and engineering as it helps in understanding how a system will naturally move or balance based on the forces applied or gravitational actions. For instance, in this exercise, the result demonstrates that the masses balance at the origin, meaning their influences counteract perfectly across the x-axis with respect to distribution and weight.
Other exercises in this chapter
Problem 28
Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the \(x\) -axis. Verify your results using the integ
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Astroid Find the total length of the graph of the astroid \(x^{2 / 3}+y^{2 / 3}=4\)
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Use the disk or the shell method to find the volume of the solid generated by revolving the region bounded by the graphs of the equations about each given line.
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(a) use a graphing utility to graph the region bounded by the graphs of the equations, \((b)\) find the area of the region, and (c) use the integration capabili
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