Problem 28
Question
In Exercises \(23-30,\) show that the given sequence is geometric and find the common ratio. $$\left\\{4^{n-4}\right\\}$$
Step-by-Step Solution
Verified Answer
Answer: Yes, the sequence {4^(n-4)} is geometric with a common ratio of 4.
1Step 1: Identify the sequence and its general term
The given sequence is \(\left\\{4^{n-4}\right\\}\). The general term \(a_n\) can be written as:
$$a_n = 4^{n-4}$$
2Step 2: Calculate the ratio between consecutive terms
To determine if the sequence is geometric, we need to find the ratio between consecutive terms, \(r = \frac{a_{n+1}}{a_n}\). Using the general term formula, we can find \(a_{n+1}\):
$$a_{n+1} = 4^{(n+1)-4} = 4^{n-3}$$
Now, we can find the ratio \(r\):
$$r = \frac{4^{n-3}}{4^{n-4}}$$
To simplify this ratio, we can use the exponent rule \(\frac{a^m}{a^n} = a^{m-n}\):
$$r = 4^{(n-3)-(n-4)} = 4^{1}$$
3Step 3: Determine if the sequence is geometric and find the common ratio
Since the ratio between consecutive terms is constant (\(r = 4\)), the sequence is geometric. Therefore, the common ratio for the sequence \(\left\\{4^{n-4}\right\\}\) is \(4\).
Key Concepts
Common RatioExponent RulesSequences
Common Ratio
Understanding the common ratio is key to analyzing geometric sequences. In a geometric sequence, each term after the first is found by multiplying the previous term by a constant, known as the common ratio. For the sequence \( \{4^{n-4}\} \), the common ratio is discovered by dividing one term by the previous term.
The formula for determining the common ratio \( r \) is given by:
The formula for determining the common ratio \( r \) is given by:
- \( r = \frac{a_{n+1}}{a_n} \)
Exponent Rules
Simplifying terms in geometric sequences often requires a good grasp of exponent rules. In our exercise, the exponent rule used is:
Exponent rules like this make it easier to work with sequences and identify patterns quickly.
- \( \frac{a^m}{a^n} = a^{m-n} \)
Exponent rules like this make it easier to work with sequences and identify patterns quickly.
Sequences
Sequences are ordered lists of numbers following a particular rule. A geometric sequence is a type of sequence where the ratio between consecutive terms remains the same.
To verify if a sequence is geometric, note whether this ratio is constant across the sequence. In this case, the sequence \( \{4^{n-4}\} \) shows a constant ratio of 4.
To verify if a sequence is geometric, note whether this ratio is constant across the sequence. In this case, the sequence \( \{4^{n-4}\} \) shows a constant ratio of 4.
- Each term is derived by multiplying the previous term by this ratio.
- Understanding the type and behavior of sequences aids in prediction and calculation of future terms.
Other exercises in this chapter
Problem 27
The first term \(a_{1}\) and the common difference d of an arithmetic sequence are given. Find the fifth term and the formula for the nth term. $$a_{1}=4, d=\fr
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Find the first five terms of the recursively defined sequence. $$a_{1}=-16 \text { and } a_{n}=\frac{a_{n-1}}{2} \quad \text { for } n \geq 2$$
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If the given statement is true, prove it. If it is false, give a counterexample. Let \(q\) be a fixed integer. Suppose a statement involving the integer \(n\) h
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Expand and (where possible) simplify the expression. $$\left(3 u-v^{3}\right)^{6}$$
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