Problem 28
Question
If possible, simplify each radical expression. Assume that all variables represent positive real numbers. $$\sqrt[3]{250}$$
Step-by-Step Solution
Verified Answer
\( 5 \sqrt[3]{2} \)
1Step 1: Factor the Radicand
Begin by factoring the number inside the cube root, which is 250. Start by dividing by the smallest prime number, 2: \[ 250 \div 2 = 125 \].Next, factor 125, which can be divided by 5:\[ 125 \div 5 = 25 \].Continue factoring 25:\[ 25 \div 5 = 5 \].Thus, 250 can be written as:\[ 250 = 2 \times 5^3 \].
2Step 2: Simplify the Cube Root
Now simplify \( \sqrt[3]{250} \) using the factorization obtained.\[ \sqrt[3]{250} = \sqrt[3]{2 \times 5^3} \].Since the cube root of \(5^3\) is 5, it can be taken outside the radical:\[ \sqrt[3]{2 \times 5^3} = 5 \times \sqrt[3]{2} \].
3Step 3: Write the Simplified Expression
Finally, write down the simplified expression for the original problem:\[ \sqrt[3]{250} = 5 \sqrt[3]{2} \].
Key Concepts
Cube RootsPrime FactorizationRadical Expressions
Cube Roots
Cube roots help us find a number that, when multiplied by itself three times, gives the original number. This process is the reverse of cubing a number. For example, the cube root of 8 is 2 because 2 × 2 × 2 = 8.
To simplify a cube root, we look for perfect cubes within the radicand (the number inside the radical). This allows us to take numbers out of the radical easily. Understanding cube roots helps in solving equations and expressions where cubes are involved.
To simplify a cube root, we look for perfect cubes within the radicand (the number inside the radical). This allows us to take numbers out of the radical easily. Understanding cube roots helps in solving equations and expressions where cubes are involved.
Prime Factorization
Prime factorization involves breaking down a number into its basic building blocks, which are prime numbers. These are numbers greater than 1 that have no factors other than 1 and themselves, like 2, 3, 5, 7, and so on.
To factorize 250, we began with the smallest prime number, 2:
To factorize 250, we began with the smallest prime number, 2:
- 250 divided by 2 gives us 125.
- Then, 125 divided by 5 gives us 25.
- Finally, 25 divided by 5 gives us 5.
Radical Expressions
Radical expressions involve roots, such as square roots and cube roots, of numbers or variables. Simplifying these can make equations easier to handle.
When simplifying radical expressions, we look for terms that can move outside the radical, which can often be done using prime factorization. In our example,
When simplifying radical expressions, we look for terms that can move outside the radical, which can often be done using prime factorization. In our example,
- the cube root of 250 becomes easier to handle when expressed as 2 × 5^3.
- The cube root of 5^3 simplifies to 5, leaving us with 5 times the cube root of 2.
Other exercises in this chapter
Problem 27
Find each product or quotient. $$\frac{4 a+12}{2 a-10} \div \frac{a^{2}-9}{a^{2}-a-20}$$
View solution Problem 27
Find each sum or difference. $$-\left(8 x^{3}+x-3\right)+\left(2 x^{3}+x^{2}\right)-\left(4 x^{2}+3 x-1\right)$$
View solution Problem 28
Perform the indicated operations. Write your answers with only positive exponents. Assume that all variables represent positive real numbers. $$9^{-4} \cdot 9^{
View solution Problem 28
Factor each trinomial completely. $$9 x^{2}-6 x^{3}+x^{4}$$
View solution